TOEFL ® Registrations 2024
ApplyAccepted by more than 11,000 universities in over 150 countries worldwide
National Testing Agency (NTA) conducts the CSIR UGC NET exam every year in two sessions. Almost 2 to 3 lakh candidates apply for the CSIR UGC NET exam every year for July and December sessions. Out of which about 1.5 to 1.75 lakhs appear for the CSIR NET exam.
As per the previous session’s CSIR UGC NET exam statistics a total of 2,19,146 candidates applied. Out of that, a total of 1,75,355. Aspirants can go through the full article to know how many candidates have applied for the CSIR UGC NET exam every year.
Check the CSIR UGC NET 2024 exam information from the table below.
Particulars | Details |
Exam Name | Council of Scientific and Industrial Research National Eligibility Test |
Short Exam Name | CSIR UGC NET |
Exam Conducting Body | National Testing Agency |
Frequency of Conduct | Twice a year |
Mode of Application | Online |
Application Fee (General) | Rs 1150 (Online) |
Exam Mode | Online |
Duration of Exam | 3 Hours |
Official Website | csirnet.nta.ac.in |
Related articles:
CSIR UGC NET Exam Statistics of Previous Years are as follows:
Year | No. of registered candidates (Assistant Professor Only + Both JRF & Assistant Professor) | No. of candidates appeared (Assistant Professor Only + Both JRF & Assistant Professor) |
Dec 2023 | 219146 | 175355 |
Dec 2022 - June 2023 | 274027 | 199890 |
June 2021 | 207306 | 159824 |
June 2020 | 262292 | 171273 |
The exam conducting body determines the CSIR UGC NET 2024 eligibility criteria and mentions on the official notification. The eligibility criteria of CSIR UGC NET exam are comprised of the following factors.
Nationality - Indian
Age limit - 30 years (Age relaxation is provided to reserved category applicants only)
Educational Qualification - Passed post-graduation from any recognized University with a minimum of 55 % aggregate marks while for reserved categories candidates 50%.
NTA releases the CSIR UGC NET 2024 application form on the official website. Candidates who fullfil the minimum eligibility will be able to fill and submit the CSIR UGC NET application form. Candidates are required to fill in all the important details in the application form such as personal, contact and academic details.
Visit the CSIR UGC NET official website - csirnet.nta.ac.in
Complete the registration process by filling the basic information.
Fill the other details in CSIR UGC NET application form 2024
Upload a scanned passport sized photograph and signature.
Preview the CSIR UGC NET form 2024 details.
Pay the registration fee
Download and take the printout of the application form for future reference.
Category | Application Fee (Rs) |
General | Rs 1,150 |
General-EWS/OBC(NCL) | Rs 600 |
SC/ST/PwD/Third Gender | Rs 325 |
Approximately 2 to 3 lakh candidates apply for the CSIR UGC NET exam every year for each session.
Candidates can submit the CSIR UGC NET application form at csirnet.nta.ac.in.
National Testing Agency (NTA) is the conducting body for CSIR NET exam.
NTA releases the CSIR NET application form in online mode only.
Admit Card Date:31 January,2025 - 09 February,2025
Application Date:31 January,2025 - 03 March,2025
Hello,
As of now there is no official announcement made regarding the release date of application form for CSIR NET for June session, you may follow the official website at https://csirnet.nta.nic.in/ to know the latest information pertaining this,
CSIR NET is conducted to determine the eligibility of candidate for JRF/Assistant Professor or Lectureship, it is conducted for three hours for 200 marks, there are three parts; part A is common to all subjects for general aptitude carrying 15 questions for two marks, total marks allotted is 30 marks, part B is subject related conventional MCQs for 70 marks with question range of 20-35, part C has been allotted 100 marks to test scientific concepts and its application. there is negative marking of 25% for each wrong answer, check out our page at https://competition.careers360.com/articles/csir-ugc-net-exam-dates to know more details regarding this.
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
CSIR NET and UGC NET exams are typically conducted per year, permitting the aspirants to get the primary selection for the lectureship in the Indian colleges & universities. Both these exams are conducted at the national level by National Testing Agency if u want net related any confusion so u can connect with our website letsatalkacadmey clear all confusion .thank you
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
Greetings, Aspirant
CSIR UGC NET conducts the exam every year for LS and JRF program.
Candidates can either apply for LS or JRF. They cannot apply for both.
CSIR UGC NET assembles the merit list to assign Lectureship and JRF to the meritorious candidates.
Candidates who qualify for the cut-off for the lectureship program can apply for the post of assistant professor in different universities and colleges. Still, they will not be eligible for the regular Junior research fellowship program.
Prospects who qualify for the NET-JRF exam will get a chance to kickstart their higher education and research in their desired subject or specialization.
If you have applied for JRF :-
1) clear the qualifying cut off then you will be eligible for LS also.
2) do not clear the cut off for JRF you will not be eligible for LS.
I hope it helps. Good Luck.
Thank you
Accepted by more than 11,000 universities in over 150 countries worldwide
Apply for Online M.Com from Manipal University