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NTA has released the CSIR NET exam pattern 2024 December session in online mode in the official notification. The CSIR UGC NET 2024 notification can be downloaded from csirnet.nta.ac.in. Candidates must have a good understanding of the CSIR UGC NET exam pattern 2024 before beginning their preparation. Those who are preparing for the CSIR UGC NET exam can find out more about the exam pattern in the article below.
The CSIR NET 2024 exam pattern outlines various details about the exam, such as duration of the exam, total number of questions, marking scheme and more. Additionally, it is also important for candidates to go through the CSIR NET syllabus as well to get a good understanding of the topics appearing in the exam.
Exam Name | CSIR NET |
Conducting Body | |
Time Duration | 3 hours |
Types of Questions | Objective Type (MCQ) |
CSIR NET Subjects |
|
Total Marks | 200 |
Mode of the exam | Online (Computer-based test) |
Marking Scheme | Negative Marking Applicable |
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NTA released the CSIR NET 2024 exam pattern in the official notification. The exam pattern of CSIR NET 2024 specifies important details such as duration of the exam, total number of questions, marking scheme, mode of the examination, subjects etc. The detailed CSIR NET exam pattern 2024 has been given below:
Subjects | Total Number of questions | Total Marks | Time Duration |
Life Sciences | 145 | 200 | 3 hours |
Earth, Atmospheric, Ocean and Planetary Sciences | 150 | ||
Mathematical Sciences | 120 | ||
Chemical Sciences | 120 | ||
Physical Sciences | 75 |
According to the CSIR NET 2024 exam pattern, each subject comprises of three parts. NTA provides the number of questions that candidates need to attempt in each section. In case candidates attempt more than the prescribed questions in any sections, the first 20 questions from the section will be taken into consideration. The details of all 3 sections of the CSIR NET 2024 exam pattern have been given below:
Part A: This section of CSIR NET 2024 is common in all the subjects and every candidate needs to attempt it. This section has been designed to test the general aptitude of the candidates. Questions in this section are from topics like logical reasoning, graphical analysis, analytical and numerical ability, series formation, quantitative comparisons, puzzles, etc.
Part B: This section in the exam focuses on topics from the subject that has been selected by the candidate.
Part C: In this section of the exam, questions will be of greater difficulty level and test the candidates’ knowledge of scientific concepts and their applications.
The exam conducting authorities have already specified the number of questions that candidates need to mandatorily attempt in each section. The questions to be attempted in each section have been given in the table below:
Particulars | Part-A | Part-B | Part-C | Total |
Total Questions | 20 | 40 | 60 | 120 |
No. of Questions to Attempt | 15 | 35 | 25 | 75 |
Marks for a correct answer | 2 | 2 | 4 | 200 |
Negative marking for an incorrect answer | 0.5 | 0.5 | 1 | - |
Particulars | Part-A | Part-B | Part-C | Total |
Total Questions | 20 | 50 | 80 | 150 |
No. of Questions to Attempt | 15 | 35 | 25 | 75 |
Marks for a correct answer | 2 | 2 | 4 | 200 |
Negative marking for an incorrect answer | 0.5 | 0.5 | 1.32 | - |
Particulars | Part-A | Part-B | Part-C | Total |
Total Questions | 20 | 50 | 75 | 145 |
No. of Questions to Attempt | 15 | 35 | 25 | 75 |
Marks for a correct answer | 2 | 2 | 4 | 200 |
Negative marking for an incorrect answer | 0.5 | 0.5 | 1 | - |
Particulars | Part-A | Part-B | Part-C | Total |
Total Questions | 20 | 40 | 60 | 120 |
No. of Questions to Attempt | 15 | 25 | 20 | 60 |
Marks for a correct answer | 2 | 3 | 4.75 | 200 |
Negative marking for an incorrect answer | 0.5 | 0.75 | 0 | - |
Particulars | Part-A | Part-B | Part-C | Total |
Total Questions | 20 | 25 | 30 | 75 |
No. of Questions to Attempt | 15 | 20 | 20 | 55 |
Marks for a correct answer | 2 | 3.5 | 5 | 200 |
Negative marking for an incorrect answer | 0.5 | 0.875 | 1.25 | - |
Candidates must go through the syllabus of 2024 CSIR NET to get an understanding of the topics and concepts from where questions will be asked. Knowing the syllabus will be very beneficial for candidates while preparing for CSIR NET 2024. There are total 5 subjects in exam and the detailed CSIR NET syllabus for all the subjects is given below:
Subject | Topics |
Chemical Sciences | Inorganic Chemistry Organic Chemistry Physical Chemistry Chemistry in nanoscience and technology Catalysis and green chemistry Medicinal chemistry Supramolecular chemistry Environmental chemistry |
Earth Sciences | The Earth and the Solar System Earth Materials, Surface Features and Processes Interior of the Earth, Deformation and Tectonics Oceans and Atmosphere Environmental Earth Sciences Geology Physical Geography Geophysics Meteorology Ocean Sciences |
Mathematical Sciences | Analysis Linear Algebra Complex Analysis Algebra Topology Ordinary Differential Equations Partial Differential Equations Numerical Analysis Calculus of Variations Linear Integral Equations Classical Mechanics Descriptive statistics |
Life Sciences | Molecules and their Interaction Relevant to Biology Cellular Organization Fundamental Processes Cell Communication and Cell Signaling Developmental Biology System Physiology – Plant System Physiology – Animal Inheritance Biology Diversity of Life Forms Ecological Principles Evolution and Behavior Applied Biology Methods in Biology |
Physical Sciences | Mathematical Methods of Physics Classical Mechanics Electromagnetic Theory Quantum Mechanics Thermodynamic and Statistical Physics Electronics and Experimental Methods Atomic & Molecular Physics Condensed Matter Physics Nuclear and Particle Physics |
All the candidates who are planning to appear for the examination must download the CSIR NET question papers and practice from there. Solving the CSIR NET question papers will help the candidates get an idea about the type of questions that will be asked in the exam, and which topics are important
Check Here For A List of Other Government Exams
NTA provides the mock test for CSIR NET 2024 for the aspirants. Aspirants can visit the official website and choose the subjective out of five option for which they want to appear in the mock test of CSIR NET 2024. The mock test will help the students to understand the exam pattern of CSIR NET 2024, question paper level and other important aspects of the exam.
The CSIR NET application form 2024 for December session is has been released on December 9, 2024 on the official website - csirnet.nta.ac.in.
Yes, marks will be deducted for all incorrect answers.
Only the first 55 questions you have attempted will be evaluated to calculate your score.
The authorities will allot exam centres to candidates on the basis of the exam centres they have selected while filling the application form. The detailed information about the exam centre will be given in the CSIR NET 2024 Admit card.
Part-A of each question paper of CSIR NET 2024 will include questions of general aptitude, logical reasoning and problem solving.
Application Date:22 November,2024 - 12 December,2024
Application Date:04 December,2024 - 19 December,2024
Hello,
As of now there is no official announcement made regarding the release date of application form for CSIR NET for June session, you may follow the official website at https://csirnet.nta.nic.in/ to know the latest information pertaining this,
CSIR NET is conducted to determine the eligibility of candidate for JRF/Assistant Professor or Lectureship, it is conducted for three hours for 200 marks, there are three parts; part A is common to all subjects for general aptitude carrying 15 questions for two marks, total marks allotted is 30 marks, part B is subject related conventional MCQs for 70 marks with question range of 20-35, part C has been allotted 100 marks to test scientific concepts and its application. there is negative marking of 25% for each wrong answer, check out our page at https://competition.careers360.com/articles/csir-ugc-net-exam-dates to know more details regarding this.
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
CSIR NET and UGC NET exams are typically conducted per year, permitting the aspirants to get the primary selection for the lectureship in the Indian colleges & universities. Both these exams are conducted at the national level by National Testing Agency if u want net related any confusion so u can connect with our website letsatalkacadmey clear all confusion .thank you
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
Greetings, Aspirant
CSIR UGC NET conducts the exam every year for LS and JRF program.
Candidates can either apply for LS or JRF. They cannot apply for both.
CSIR UGC NET assembles the merit list to assign Lectureship and JRF to the meritorious candidates.
Candidates who qualify for the cut-off for the lectureship program can apply for the post of assistant professor in different universities and colleges. Still, they will not be eligible for the regular Junior research fellowship program.
Prospects who qualify for the NET-JRF exam will get a chance to kickstart their higher education and research in their desired subject or specialization.
If you have applied for JRF :-
1) clear the qualifying cut off then you will be eligible for LS also.
2) do not clear the cut off for JRF you will not be eligible for LS.
I hope it helps. Good Luck.
Thank you
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