CSIR UGC NET Application Date:25 Sep' 25 - 24 Oct' 25
The National Testing Agency will release the Council of Scientific and Industrial Research CSIR UGC NET December 2025 result in online mode on the official website—csirnet.nta.nic.in. Candidates who filled the CSIR NET application form for the December session can download the CSIR UGC NET 2025 result after logging in with the necessary credentials that is application number and password.
This Story also Contains
The CSIR UGC NET December 2025 result will contain the roll number and rank of the candidate along with the total number of qualified candidates. The scorecard of CSIR UGC NET and the merit list will be released along with the CSIR UGC NET December 2025 result. The CSIR UGC NET cut off will also be released both the category-wise and subject-wise along with the CSIR UGC NET December 2025 result
CSIR NET Result 2020 - Overview
Exam name | Joint CSIR UGC NET |
Exam-conducting body | National Testing Agency (NTA) |
Mode of CSIR UGC NET result | Online (PDF) |
Details to be displayed | Roll number and rank |
Scorecard (credentials required) | Registration number and Date of Birth |
CSIR NET result validity | Two years |
Check out the official website for NTA CSIR – csirnet.nta.nic.in
On that tab, you can click on the link CSIR NET result. Select the submission number and the password / date of birth.
There will be a login window. Please enter your registration number, birth date, password date, and press "Login".
On the screen will be shown the December result of CSIR NET 2020 (merit list).Check for your roll by using the keyboard. Press Ctrl + F.
You are eligible for CSIR NET 2020 if your roll number is included in the CSIR NET merit list. Now save the file as a guide in PDF format.
The following details will be mentioned in the result of CSIR NET 2025:
Roll number
Rank
Total number of qualified candidates
CSIR released the scorecard of CSIR UGC NET for the December session. To download the scorecard of CSIR UGC NET, candidates will have to follow these steps:
Click on the scorecard link provided above
Enter your roll number and date of birth in the login window
Click on submit button to get access to your scorecard
You can now check your scores and download your CSIR NET scorecard
Name
Roll number
Subject
Total marks
Percentile
Rank
CSIR UGC NET scorecard will contain the following details that are mentioned below.
Candidates must check the details mentioned below in the CSIR UGC NET scorecard after the declaration of CSIR UGC NET December 2025 result:
Name
Roll Number
Subject
Marks obtained in Part A, B and C
Percentage
Total Marks
Rank
Also Read:
After NTA announces the CSIR NET December 2025 result, the Lectureship and Junior Research Fellowship (JRF) eligibility certificates will be given to applicants. The certificate provided for the shortlisted candidates will be valid for 2 years from the date of the CSIR NET result.
Candidates who get shortlisted under the CSIR NET 2025 result can apply for an eligibility certificate. The appointment of an applicant as a lecturer or the grant of a fellowship will be considered after the document has been confirmed. Applicants must submit self-tested photocopies of their documents along with their applications.
Class 10 certificate for date of birth proof
Final mark sheet with a minimum percentage of marks required
Degree/provisional degree of qualifying exam/M.Sc. or equivalent degree
Copy of CSIR mark sheet
Caste certificate, if applicable
Candidates who have applied under the result awaited (RA) category (M.Sc. or equivalent) must submit the required documents only after they complete their qualifications.
The eligibility certificate will be given by NTA to all CSIR NET eligible candidates in online mode after the DV has been completed. The steps for downloading the e-certificate are listed below:
Visit the official website of CSIR UGC NET-csirnet.nta.nic.in.
Click on the e-certificate link and the JRF letter link
Enter your credential roll/application number, date of birth, exam session and security captcha code in the login pane.
Upload your certificate.
Frequently Asked Questions (FAQs)
As per the official announcement, the CSIR NET exam for the December session will be held on December 18, 2025.
To prepare better for the CSIR UGC NET 2025, candidates need to follow the proper study plan. Choose the best books and solve sample papers based on the latest syllabus and exam pattern.
Candidates can apply for the CSIR NET 2025 December session through the link available on the official website.
On Question asked by student community
Hello Aspirant,
To prepare for CSIR UGC Net Examination you need to follow some steps:
1.Know the exam pattern
Total Marks 200
It consists 3 section-
Part A(Aptitude common for all).
Part B and C(Subject specific questions)
2.Choose your subject for this examination
As this examination consider in different subjects,so you need to choose one among these subjects.
https://csirhrdg.res.in/Home/Index/1/Default/2666/78 check about subjects from official website.
3.Collect the right study material.
4.Make a study plan and follow it.
All the best for your CSIR UGC NET preparation.
A six month preparation window is ideal for CSIR UGC NET, especially if you follow a structured plan. Below is a month wise breakdown of how you can prepare effectively, balancing core subjects, General Aptitude, revision, mock tests , and research paper reading .
In the first three months , focus on completing the full syllabus, spending most of your time on core subjects and 1 day a week on General Aptitude. Also, begin reading 1 to 2 research papers weekly.
In month 4 , start your first full revision, practice topic-wise questions, and begin attempting small mock tests.
In month 5 , do your second revision and shift to full-length mock tests (2 per week) while analyzing mistakes.
In month 6 , do a final quick revision, increase mock tests to 3 to 4 per week, and avoid starting new topics.
Overall, spend around 60 to 70% of your time on subject preparation , 15 to 20% on revision , and 10 to 15% on mock tests and paper solving , increasing test practice in the last two months.
Hi aspirant.
If you're looking to download the CSIR UGC NET question papers, you can follow this method for easy access:
You can also download it from the Career360 website
Hello,
As of now there is no official announcement made regarding the release date of application form for CSIR NET for June session, you may follow the official website at https://csirnet.nta.nic.in/ to know the latest information pertaining this,
CSIR NET is conducted to determine the eligibility of candidate for JRF/Assistant Professor or Lectureship, it is conducted for three hours for 200 marks, there are three parts; part A is common to all subjects for general aptitude carrying 15 questions for two marks, total marks allotted is 30 marks, part B is subject related conventional MCQs for 70 marks with question range of 20-35, part C has been allotted 100 marks to test scientific concepts and its application. there is negative marking of 25% for each wrong answer, check out our page at https://competition.careers360.com/articles/csir-ugc-net-exam-dates to know more details regarding this.
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
Apply for Online M.Com from Manipal University