CSIR NET Exam Dates 2020 - Check Registration, Admit Card & Result Dates
CSIR NET Exam Dates 2020 - National Testing Agency(NTA) has released CSIR NET 2020 exam dates for June Session at its official website - nta.ac.in. With the help of exam dates of CSIR NET 2020, candidates can keep track of all the upcoming events. As per CSIR NET Exam Dates 2020, the official notification has been released on March 16 along with the application form. Candidates could fill the online application form of CSIR NET till June 30, 2020 (extended dates). CSIR NET 2020 exam dates include the admit card release date, exam date, result declaration dates and result date. CSIR NET online exam date which will be announced anytime soon at various centres. For more details candidates can check CSIR NET exam dates 2020 from the article given below.
Latest: CSIR NET 2020 to be held in second week of November. Admit Card of CSIR NET 2020 to be released anytime soon. Practice CSIR NET Question Papers 2020 for exam preparations.
CSIR NET exam is conducted for appointment of Lecturers (NET) in subjects under the faculty of Science and Technology and awarding Junior Research Fellowship (JRF). Candidates can check CSIR NET result 2020 in online mode at the official website.
CSIR NET Exam Dates 2020
Candidates can check the exam dates of CSIR NET 2020 from the table given below.
Events | Dates for June 2020 | Dates for December 2020 (Tentative) |
Starting date of online application form | March 16, 2020 (Started) | September 9, 2020 |
Last date of application form |
June 30, 2020 (5:00 pm) | October 9, 2020 |
Dates to edit the application form | July 6- July 20, 2020 (Extended) | October 18 to 25, 2020 |
CSIR NET admit card 2020 | To be notified | November 9, 2020 |
CSIR NET exam date 2020 | Second week of November | December 15, 2020 |
Result of CSIR NET 2020 | To be notified | December 31, 2020 |
CSIR NET Application Form 2020 Dates
NTA has released the application form of CSIR NET 2020 on March 16 in online mode at its official website. Candidates first need to register themselves with basic details like the candidate’s name, corresponding address and contact information. After the registration process, a system-generated registration ID and password will be sent to the candidate’s email ID. Now candidates need to upload a scanned image of photograph, signature and caste certificate(if applicable) as per the specifications. After filling all details in the application form of CSIR NET candidates can proceed to pay the application fee. Candidates can pay the application fees of CSIR NET through debit card (Rupay/Visa/MasterCard/Maestro), credit card, internet banking.
CSIR NET 2020 Admit Card Dates
Candidates who submit the application form successfully can download the admit card of CSIR NET from the official website. As per the CSIR NET exam dates 2020, the admit card will be available few days before the dates of exam and will be announced soon. Candidates need to login with registration ID and password to download the CSIR NET admit card. After downloading the admit card, candidates are advised to check all the details mentioned in the admit card. In case of any discrepancy, candidates can contact the exam conducting authorities.
CSIR NET Exam Dates 2020
The computer-based exam of CSIR NET for the June session will be conducted in the second week of November. Candidates need to carry one hard copy of admit card along with one photo ID proof same as used at the time of filling the application form on the exam day. Qualified candidates can download their eligibility certificates from the official website a few days after the declaration of results.
CSIR NET Result 2020 Dates
NTA will release the result of CSIR NET 2020 on its official website after the conclusion of the exam. CSIR NET 2020 result dates will be announced anytime soon. Qualified candidates will be issued CSIR NET eligibility certificate for lectureship while the fellowships will be awarded only to JRF qualified candidates. The result of CSIR UGC NET will remain valid for a period of 2 years from the date of declaration of the result.
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Frequently Asked Question (FAQs) - CSIR NET Exam Dates 2020 - Check Registration, Admit Card & Result Dates
Question: What is the last date to download the admit card of CSIR NET exam?
Answer:
Candidates can download CSIR NET admit card till the exam date.
Question: What are the documents required to fill the CSIR NET application form?
Answer:
Candidates need to upload a scanned image photograph, signature and caste certificate(if applicable) in the CSIR NET application form 2020.
Question: Can I fill CSIR NET application fee in offline mode?
Answer:
No, candidates can pay the application fee of CSIR NET 2020 in online mode only.
Question: What is the exam date of CSIR NET 2020?
Answer:
The online exam was earlier scheduled to be held on June 21, 2020 but due to COVID-19 outbreak, the exam has been postponed. The new dates will be announced later.
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Questions related to CSIR UGC NET
when will be CSIR net 2020 exam conducted??
Hello,
CSIR UGC NET June 2020 Exam will be conducted by the National Testing Agency (NTA) on 21st June 2020 for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for Lectureship (LS)/Assistant Professorship in certain subject areas falling under the faculty of Science & Technology like Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.
Good Luck.
Answer laterCan I be eligible for CSIR UGC NET LIFE SCIENCE after completing MBA IN BIOTECHNOLOGY?
There is no age criteria for NET exam but for the JRF post you age should be below 28 years..
Good luck... hope it helps!!
Is final year Btech Mechanical student is eligible for NTA CSIR UGC NET exam?
Hello aspirant,
As per the eligibility criteria of CSIR UGC NET exam you should secure at least 50% marks in your B.Tech degree.
But if you are in the final semester you can also submit the application form but then you are have to apply under the result awaited category. in this situation you have to put your aggregate marks after completion of B.Tech degree to avail the fellowship.
For more detailed information about eligibility criteria for CSIR UGC-NET you should visit -
https://competition.careers360.com/articles/csir-ugc-net-eligibility-criteria
I hope this information helps you.
For further queries feel free to ask in comment section.
Good Luck!!
in which month Csir net june 2020 is most likely to occour ?
Hello,
The CSIR NET application form deadline has further been extended till June 15, 2020. In this case, it is difficult to say whether the exam will be held in which month. However, any update related to the exam will be updates in CSIR NET exam dates .
difference between applied and pure mathematics for csir ugc net exam
Dear,
Pure mathematicians try to generalize and make more abstract the pre-existing concepts , they delve deeper into seemingly simplistic mathematics.
There are two things that can be done with a concept or an idea, you can go uphill or you can go downhill ( look deeper into the concepts).Pure mathematics goes downhill.
Lets say that we have the Cartesian co-ordinate system. A pure mathematician defines a field of numbers, develops the concept of vectors , define vector spaces,find some of the properties of vector spaces ,generalise to functional spaces, define hilbert spaces and so on.
On the other hand an applied mathematician would find how to use this concept of Cartesian co-ordinate system to solve some problems, in other words how can this mathematical concept be applied.
In the light of the above example, they may realise that quantum mechanics is having some sort of link with linear algebra, incorporate the concept of hilbert spaces , get more result out of the equations (as those concepts have already been developed in pure mathematics )
Applied mathematics like pure mathematics plays a crucial role in science. In physics many concepts of pure mathematics are now applied ( so in a sense physics is applied mathematics) .
Hope this helps!
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