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CSIR UGC NET 2025 - National Testing Agency has extended the last date to fill the CSIR NET application form 2025 until June 26, 2025. The CSIR NET 2025 application form was released on June 3, 2025 on the official website, csirnet.nta.ac.in. The application form was activated along with the CSIR NET June notification 2025. The CSIR UGC NET fee payment can be done until June 27, 2025. NTA has scheduled to conduct the CSIR NET June exam 2025 on July 26, 27, 28, 2025.
Council of Scientific and Industrial Research, University Grants Commission, National Eligibility Test is also called as the CSIR UGC NET. The National Testing Agency (NTA) conducts the CSIR UGC NET to select eligible candidates as Lecturers and Junior Research Fellow persons in the faculty of science. CSIR NET 2025 exam will be conducted in online mode.
Only eligible candidates can fill the application form. The CSIR UGC NET 2025 exam paper includes questions from five main subjects like Life Sciences, Chemical Sciences, Mathematical Sciences, Physical Sciences, Earth Sciences. For more information candidates are advised to read the article below.
Full exam name | Council of Scientific and Industrial Research, University Grants Commission, National Eligibility Test |
Short exam name | CSIR UGC NET |
Exam conducting body | National Testing Agency |
Frequency of conduct | Twice a year (June and December) |
Exam level | National level exam |
Languages | English and Hindi |
Mode of application | Online |
Application fee | Online (Rs. 1,150) |
Mode of exam | Online |
Exam duration | 3 hours |
Official website | csirnet.nta.ac.in |
The NTA announced the CSIR NET 2025 dates along with exam schedule in the official notification. The table given below details on important dates of CSIR UGC NET 2025 in order to be updated on upcoming events.
Events | CSIR UGC NET Dates |
CSIR UGC NET 2025 Notification | June 3, 2025 |
Release of CSIR UGC NET 2025 application form | June 3, 2025 |
Last date to fill CSIR NET application form 2025 |
June 26, 2025 |
Last date to pay the CSIR NET application fee | June 27, 2025 (revised date) |
CSIR NET 2025 application form correction window | June 28, & 29, 2025 (revised date) |
Issuing of CSIR NET city intimation slip | TBA |
Release of CSIR NET admit card 2025 | TBA |
CSIR NET 2025 exam date | July 26, 27, 28, 2025 |
CSIR NET 2025 provisional answer key | TBA |
Closing date of answer key challenge window | TBA |
CSIR NET final answer key date | TBA |
CSIR UGC NET 2025 result date | TBA |
CSIR UGC NET 2025 rank list | TBA |
The CSIR UGC NET application last date is June 26, 2025 (extended date). National Testing Agency released the CSIR NET 2025 application form on June 3, 2025 in online mode at csirnet.nta.ac.in. Candidates looking to apply for CSIR NET 2025 are advised to go through the eligibility criteria. Only the candidates who successfully complete and submit the CSIR NET application form will be issued the admit card. Given below are the steps to fill CSIR UGC NET application form 2025 for candidates to follow along.
Visit the official website csirnet.nta.ac.in.
Click on ‘Apply Online’ on the bottom of the homepage
Complete the registration process
Fill up the online application form
Upload scanned photograph and signature
Pay the applicable examination fee online
Take print out for future reference
Category | Application fee |
General | Rs. 1,150 |
OBC/EWS | Rs. 600 |
SC/ST/PwD/Third gender | Rs. 325 |
The exam conducting authority has released CSIR NET 2025 eligibility criteria in the official notification. The CSIR UGC NET 2025 notification can be downloaded from csirnet.nic.ac.in. Only the candidates fulfilling CSIR UGC NET eligibility criteria can appear for exam. The eligibility criteria of CSIR NET 2025 mentions the conditions candidates are expected to meet to be identified as lecturer or receive Junior Research Fellowship. The eligibility requirements for CSIR UGC NET 2025 are given below.
Nationality: Candidates must be citizens of India.
Age: The age limit for Junior Research Fellowship is 30 years. However a 5 year duration of age relaxation is provided for reserved category candidates. However there is no upper age limit for candidates applying under Assistant professor and PhD programs.
Educational qualification: Candidates with a bachelors or masters degree with a minimum of 55% aggregate score (General), and 50% (SC/ST/PwD) candidates.
NTA mentioned the CSIR NET 2025 exam pattern in the official notification which is available on the official website. Candidates are advised to check the CSIR UGC NET exam pattern before starting to prepare for the exam. The CSIR NET exam pattern 2025 mentions important details like the duration of the exam, total number of questions, marking scheme, mode of exam, subjects and more. Given below is a detailed overview on syllabus of CSIR UGC NET 2025.
Particulars | Part A | Part B | Part C | Total |
Total number of questions | 20 | 50 | 75 | 145 |
Number of questions to attempt | 15 | 35 | 25 | 75 |
Marks for the correct answer | 2 | 2 | 4 | 200 |
Marks for each incorrect answer | 0.5 | 0.5 | 1 | - |
Particulars | Part A | Part B | Part C | Total |
Total number of questions | 20 | 50 | 80 | 150 |
Number of questions to attempt | 15 | 35 | 25 | 75 |
Marks for the correct answer | 2 | 2 | 4 | 200 |
Marks for each incorrect answer | 0.5 | 0.5 | 1 | - |
Particulars | Part A | Part B | Part C | Total |
Total number of questions | 20 | 40 | 60 | 120 |
Number of questions to attempt | 15 | 25 | 20 | 60 |
Marks for the correct answer | 2 | 3 | 4.75 | 200 |
Marks for each incorrect answer | 0.5 | 0.75 | 0 | - |
Particulars | Part A | Part B | Part C | Total |
Total number of questions | 20 | 40 | 60 | 120 |
Number of questions to attempt | 15 | 35 | 25 | 75 |
Marks for the correct answer | 2 | 2 | 4 | 200 |
Marks for each incorrect answer | 0.5 | 0.5 | 1.32 | - |
Particulars | Part A | Part B | Part C | Total |
Total number of questions | 20 | 25 | 30 | 75 |
Number of questions to attempt | 15 | 20 | 20 | 55 |
Marks for the correct answer | 2 | 3.5 | 5 | 200 |
Marks for each incorrect answer | 0.5 | 0.875 | 1.25 | - |
NTA issues CSIR UGC NET admit card 2025 to all the eligible candidates who submitted the application form online. Candidates can download the admit card of CSIR UGC NET 2025 from the official website. The authority releases the CSIC NET admit card a week before the commencement of the exam. The CSIR NET admit card 2025 contains details like name of candidate, roll number, exam date and time, exam centre details and more. It is mandatory to carry a copy of CSIR NET admit card to the examination centre of CSIR NET 2025. For any discrepancy regarding CSIR NET admit card 2025 candidates can contact NTA. Given below are the steps to download the admit card of CSIR NET 2025.
Visit the official website, csirnet.nta.ac.in.
Click on ‘CSIR UGC 2025 NET admit card’ in the homepage
Enter the application number and date of birth in the login window
Enter security pin
Click on ‘submit’ button
Download and take a print out of the CSIR NET admit card.
The NTA authority mentioned the CSIR NET 2025 syllabus in the official notification. Candidates can download the CSIR NET syllabus 2025 from the official website. The board releases the syllabus of CSIR NET separately for each subject. The pdf files for detailed view of CSIR UGC NET 2025 syllabus is given in the table below.
Subject name | Link to download syllabus pdf |
Chemical sciences | |
Earth sciences | |
Mathematical sciences | |
Life sciences | |
Physical sciences |
The authority will release the answer key of CSIR UGC NET 2025 in pdf format on the official website. The board will also provide an answer key challenge facility to challenge the provisional answer key of CSIR NET 2025. Candidates will be able to download the CSIR UGC NET answer key by entering the login details like application number and date of birth. Steps to download the CSIR UGC NET 2025 answer key is mentioned below.
Visit the official website of CSIR UG NET, csirnet.nta.ac.in
Click on the link CSIR NET answer key
A new login window will be displayed on the screen
Enter the login details like application number and date of birth
Click on ‘submit’ button
The CSIR NET answer key 2025 will be displayed on the screen
Save and download a copy of answer key for future reference.
The NTA authority will release CSIR NET cut off 2025 along with the CSIR NET result. The board releases the cutoff for each category in the form of a pdf on the official website. The cutoff of CSIR NET 2025 depends on various factors like number of applicants, difficulty level of exam, number of posts available and more. Candidates can check the table below of previous year CSIR NET cutoff as a reference.
Category | Minimum qualifying cutoff |
General and OBC | 33% |
SC/ST & PwD | 25% |
The CSIR UGC NET result 2025 will be declared by the National Testing Agency on its official website. The authority also releases CSIR NET 2025 scorecard along with the result. Candidates who appeared for CSIR UGC NET exam 2025 will be able to check their result using application number and date of birth through the online portal of authority.
The scorecard of CSIR UGC NET 2025 result will contain details like name and qualifying status of the candidates. Only the candidates who secure marks equal or more than CSIR NET cutoff 2025 will be considered eligible for Lecturership and Junior research fellowship.
Any student qualified their Masters degree in their respective field is considered eligible to apply for CSIR NET 2025 exam.
CSIR-UGC NET 2025 is conducted twice a year which is in June and December.
The average CSIR NET Lectureship pay range is between Rs 37,000 - Rs 67,000 per month.
The CSIR UGC NET June application form was released on June 3, 2025.
There is no limit on the number of attempts for the CSIR NET exam, provided they fulfil the eligibility criteria.
Others:01 August,2024 - 30 June,2025
Application Date:05 June,2025 - 26 June,2025
Application Date:09 June,2025 - 04 July,2025
Hello Aspirant,
To prepare for CSIR UGC Net Examination you need to follow some steps:
1.Know the exam pattern
Total Marks 200
It consists 3 section-
Part A(Aptitude common for all).
Part B and C(Subject specific questions)
2.Choose your subject for this examination
As this examination consider in different subjects,so you need to choose one among these subjects.
https://csirhrdg.res.in/Home/Index/1/Default/2666/78 check about subjects from official website.
3.Collect the right study material.
4.Make a study plan and follow it.
All the best for your CSIR UGC NET preparation.
Hi aspirant.
If you're looking to download the CSIR UGC NET question papers, you can follow this method for easy access:
You can also download it from the Career360 website
Hello,
As of now there is no official announcement made regarding the release date of application form for CSIR NET for June session, you may follow the official website at https://csirnet.nta.nic.in/ to know the latest information pertaining this,
CSIR NET is conducted to determine the eligibility of candidate for JRF/Assistant Professor or Lectureship, it is conducted for three hours for 200 marks, there are three parts; part A is common to all subjects for general aptitude carrying 15 questions for two marks, total marks allotted is 30 marks, part B is subject related conventional MCQs for 70 marks with question range of 20-35, part C has been allotted 100 marks to test scientific concepts and its application. there is negative marking of 25% for each wrong answer, check out our page at https://competition.careers360.com/articles/csir-ugc-net-exam-dates to know more details regarding this.
S.N |
Topic Name for NET Life Science Syllabus 2022 |
1. | Molecules and their Interaction Relevant to Biology |
2. | Cellular Organization |
3. | Fundamental Processes |
4. | Cell Communication and Cell Signaling |
5. | Developmental Biology |
6. | System Physiology – Plant |
7. | System Physiology – Animal |
8. | Inheritance Biology |
9. | Diversity of Life Forms |
10. | Diversity of Life Forms |
11. | Evolution and Behavior |
12. | Evolution and Behavior |
13. | Evolution and Behavior |
CSIR NET and UGC NET exams are typically conducted per year, permitting the aspirants to get the primary selection for the lectureship in the Indian colleges & universities. Both these exams are conducted at the national level by National Testing Agency if u want net related any confusion so u can connect with our website letsatalkacadmey clear all confusion .thank you
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