Staff Selection Commission Sub Inspector Exam
Question : Directions: In the following question a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. $7 \frac{1}{7}, 8 \frac{2}{6}, 9 \frac{5}{5}, 12 \frac{2}{4}, 16 \frac{2}{3},?$
Option 1: $35 \frac{3}{4}$
Option 2: $16 \frac{4}{4}$
Option 3: $\frac{50}{2}$
Option 4: $15 \frac{2}{4}$
Correct Answer: $\frac{50}{2}$
Solution : Given: $7 \frac{1}{7}, 8 \frac{2}{6}, 9 \frac{5}{5}, 12 \frac{2}{4}, 16 \frac{2}{3}, ?$
First, convert all the mixed fractions into fractions –
$ \frac{50}{7}, \frac{50}{6}, \frac{50}{5}, \frac{50}{4}, \frac{50}{3}, ?$ Here, numerators are constant and subtract 1 from the denominator to get the next missing term in
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. L_ _LM_L_L_ML
Option 1: MLLML
Option 2: LMMML
Option 3: MMMLL
Option 4: LMLLM
Correct Answer: MLLML
Solution : Given: L_ _LM_L_L_ML
To fill the series, we have to divide the series – L_ _ / LM_ / L_L / _ML Let's check each option – First option: MLLML; LML / LML / LML / LML (LML is repeated
Question : In which state is the Sarhul festival celebrated
Option 1: Gujarat
Option 2: Chhattisgarh
Option 3: Assam
Option 4: Jharkhand
Correct Answer: Jharkhand
Solution : The correct option is Jharkhand.
The Sarhul festival is primarily celebrated by the tribal communities in the Indian state of Jharkhand. It is a significant festival for the Munda and Oraon tribes in the region. Sarhul is dedicated to the worship of trees, especially the
Question : The value of $\frac{0.325 \times 0.325+0.175 \times 0.175+25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}+\frac{0.5}{1.5}$ is:
Option 1: $3$
Option 2: 0
Option 3: $\frac{7}{3}$
Option 4: $\frac{11}{3}$
Correct Answer: $\frac{11}{3}$
Solution : Given: $\frac{0.325 \times 0.325+0.175 \times 0.175+25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}+\frac{0.5}{1.5}$ $=\frac{(0.325)^2 \times(0.175)^2+2 \times 0.0325\times0.175}{0.0325\times3.25- 0.225 \times 1.025}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{0.325\times0.325- 0.175 \times0.175}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{(0.325)^2(0.175)^2}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{(0.325+0.175)(0.325-0.175)}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)}{(0.325-0.175)}+\frac{0.5}{1.5}$ $=\frac{0.5}{0.15}+\frac{0.5}{1.5}$ $=\frac{5+0.5}{1.5}$ $=\frac{5.5}{1.5}$ $=\frac{11}{3}$ Hence, the correct answer is $\frac{11}{3}$.
Question : Which one of the following cities has the maximum number of registered vehicles on the road?
Option 1: Mumbai
Option 2: Kolkata
Option 3: Delhi
Option 4: Chennai
Correct Answer: Delhi
Solution : The correct answer is Delhi
Delhi had the most registered vehicles among the million-plus cities, with nearly 1.18 crore, and Bengaluru had the second-most, with 96.4 lakh. Given the information above, it is safe to say that Delhi, the capital of India, is the city
Question : Directions: In the following question, some parts of the sentence may have errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
I felt privileged (1) / to recite a poem in an honour of my teacher (2) / at a recent school function. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The correct choice is the second option.
The error lies in the use of "an honour" instead of "the honour". The definite article "the" is more appropriate in this context because it refers to a specific honour, i.e., the honour of the teacher.
Therefore,
Question : A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at points R, P and Q, respectively. If AQ = 3.5 cm, PC = 4.5 cm and BR = 7 cm, then the perimeter (in cm) of the triangle $\triangle \mathrm{ABC}$ is:
Option 1: 30
Option 2: 15
Option 3: 28
Option 4: 45
Correct Answer: 30
Solution :
AQ = 3.5 cm, PC = 4.5 cm and BR = 7 cm AQ and AR are two tangents on the circle from point A. ⇒ AQ = AR = 3.5 cm BP and BR are two tangents on the circle from point B. ⇒
Question : Directions: Select the figure that will replace the question mark (?) in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Here the pattern is as follows — 1. In the given series, the shaded quarter of the circle is moving 90° clockwise. 2. The arrow is moving 90° anti-clockwise and rotated in a 90° clockwise direction in its position. 3. The circle along the line is
Question : The opportunity cost of production of a commodity is
Option 1: The cost that the firm could have incurred when a different technique was adopted
Option 2: The cost that the firm could have incurred under a different method of production
Option 3: The actual cost incurred
Option 4: The best alternative output
Correct Answer: The best alternative output
Solution : The correct answer is the best alternative output.
The value of the best alternative that must be given up when resources are employed to create that commodity rather than another one is referred to as the opportunity cost of production of
Question : The process of imbibition involves
Option 1: Diffusion
Option 2: Capillary action
Option 3: Absorption
Option 4: Both 1 and 2
Correct Answer: Absorption
Solution : The correct option is Absorption.
Absorption of water by solid things, particularly porous materials such as plant tissues or powdered solids, is the process of imbibition. Imbibition happens when water molecules are drawn into the substance by capillary action, causing swelling and expansion. This
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