Staff Selection Commission Sub Inspector Exam
Question : Who was the Contitutional Advisor to the Constituent Assembly of India?
Option 1: Dr. Rajendra Prasad
Option 2: Dr. B.R. Ambedkar
Option 3: Sir B.N. Rao
Option 4: Shri K.M.Munshi
Correct Answer: Sir B.N. Rao
Solution : Correct Answer is Sir B.N. Rao
The Constituent Assembly commissioned B. N. Rao to serve as its constitutional adviser as it drafted the Indian Constitution. He created a Draft Constitution based on the discussions in the Constituent Assembly and the reports of the
Question : The volume of a sphere is given by 130977 cm3. Its surface area (in cm2) is:
Option 1: 16847
Option 2: 12474
Option 3: 17424
Option 4: 14274
Correct Answer: 12474
Solution : Volume of a sphere = $(\frac{4}{3}) × \pi r^3$, where $r$ is the radius of the sphere. ⇒ $(\frac{4}{3}) × (\frac{22}{7}) × r^3 = 130977$ ⇒ $r^3 = \frac{(130977 × 7 × 3)}{ (4 × 22)}$ ⇒ $r = \sqrt[3]{\frac{3×3×3×3×3×3×7×7×7×11}{2 × 2 × 2×11}}$ $\therefore
Question : The vitamin most readily destroyed by heat is:
Option 1: Riboflavin
Option 2: Ascorbic acid
Option 3: Tocopherol
Option 4: Thiamine
Correct Answer: Ascorbic acid
Solution : The correct option is Ascorbic acid.
Vitamin C, often known as Ascorbic acid, is the vitamin that is most easily damaged by heat. Vitamin C is heat-sensitive and readily destroyed when exposed to heat during cooking or food preparation. To preserve more vitamin C
Question : A cell increases in volume when it is placed in
Option 1: Hypertonic solution
Option 2: Hypotonic solution
Option 3: Isotonic solution
Option 4: None of these
Correct Answer: Hypotonic solution
Solution : The correct option is a Hypotonic solution.
When a cell is immersed in a hypotonic solution with a lower solute concentration than the interior of the cell, water moves into the cell via osmosis. As a result, the cell will absorb water and
Question : Directions: In the following question a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. $7 \frac{1}{7}, 8 \frac{2}{6}, 9 \frac{5}{5}, 12 \frac{2}{4}, 16 \frac{2}{3},?$
Option 1: $35 \frac{3}{4}$
Option 2: $16 \frac{4}{4}$
Option 3: $\frac{50}{2}$
Option 4: $15 \frac{2}{4}$
Correct Answer: $\frac{50}{2}$
Solution : Given: $7 \frac{1}{7}, 8 \frac{2}{6}, 9 \frac{5}{5}, 12 \frac{2}{4}, 16 \frac{2}{3}, ?$
First, convert all the mixed fractions into fractions –
$ \frac{50}{7}, \frac{50}{6}, \frac{50}{5}, \frac{50}{4}, \frac{50}{3}, ?$ Here, numerators are constant and subtract 1 from the denominator to get the next missing term in
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. L_ _LM_L_L_ML
Option 1: MLLML
Option 2: LMMML
Option 3: MMMLL
Option 4: LMLLM
Correct Answer: MLLML
Solution : Given: L_ _LM_L_L_ML
To fill the series, we have to divide the series – L_ _ / LM_ / L_L / _ML Let's check each option – First option: MLLML; LML / LML / LML / LML (LML is repeated
Question : In which state is the Sarhul festival celebrated
Option 1: Gujarat
Option 2: Chhattisgarh
Option 3: Assam
Option 4: Jharkhand
Correct Answer: Jharkhand
Solution : The correct option is Jharkhand.
The Sarhul festival is primarily celebrated by the tribal communities in the Indian state of Jharkhand. It is a significant festival for the Munda and Oraon tribes in the region. Sarhul is dedicated to the worship of trees, especially the
Question : The value of $\frac{0.325 \times 0.325+0.175 \times 0.175+25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}+\frac{0.5}{1.5}$ is:
Option 1: $3$
Option 2: 0
Option 3: $\frac{7}{3}$
Option 4: $\frac{11}{3}$
Correct Answer: $\frac{11}{3}$
Solution : Given: $\frac{0.325 \times 0.325+0.175 \times 0.175+25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}+\frac{0.5}{1.5}$ $=\frac{(0.325)^2 \times(0.175)^2+2 \times 0.0325\times0.175}{0.0325\times3.25- 0.225 \times 1.025}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{0.325\times0.325- 0.175 \times0.175}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{(0.325)^2(0.175)^2}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)^2}{(0.325+0.175)(0.325-0.175)}+\frac{0.5}{1.5}$ $=\frac{(0.325+0.175)}{(0.325-0.175)}+\frac{0.5}{1.5}$ $=\frac{0.5}{0.15}+\frac{0.5}{1.5}$ $=\frac{5+0.5}{1.5}$ $=\frac{5.5}{1.5}$ $=\frac{11}{3}$ Hence, the correct answer is $\frac{11}{3}$.
Question : Which one of the following cities has the maximum number of registered vehicles on the road?
Option 1: Mumbai
Option 2: Kolkata
Option 3: Delhi
Option 4: Chennai
Correct Answer: Delhi
Solution : The correct answer is Delhi
Delhi had the most registered vehicles among the million-plus cities, with nearly 1.18 crore, and Bengaluru had the second-most, with 96.4 lakh. Given the information above, it is safe to say that Delhi, the capital of India, is the city
Question : Directions: In the following question, some parts of the sentence may have errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
I felt privileged (1) / to recite a poem in an honour of my teacher (2) / at a recent school function. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The correct choice is the second option.
The error lies in the use of "an honour" instead of "the honour". The definite article "the" is more appropriate in this context because it refers to a specific honour, i.e., the honour of the teacher.
Therefore,
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