Staff Selection Commission Multi Tasking Staff Exam
Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the highlighted part of the sentence. In case no improvement is needed, select "No Improvement".
There are schools in either sides of the road.
(1) schools on either side
(2) school on either side
(3) school on either sides
(4) No Improvement
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The correct choice is the first option.
Since one is talking about multiple schools on both sides of the road, one should use the plural form "schools" instead of "school". "Side" must be used in the singular form because it refers to one of those options at a time.
The sentence conveys the meaning that there are schools on the left side as well as on the right side of the road. So, even though the sentence collectively talks about both sides of the road, it treats each side separately, and that's why "side" is in the singular form.
Therefore, the correct sentence is: There are schools on either side of the road.
Question : What is the value of $(1\div 4) \ \text{of} \ 16+{120\div 24 \times 10}$?
Option 1: 40
Option 2: 46
Option 3: 50
Option 4: 54
Correct Answer: 54
Solution : $(1\div 4) \ \text{of} \ 16+{120\div 24 \times 10}$ $=4+{120\div 24 \times 10}$ $=4+{5 \times 10}$ $=4+50$ $=54$ Hence, the correct answer is 54.
Question : If the radius of a cylinder is decreased by 12%, then by how much percentage must its height be increased so that the volume of the cylinder remains the same?
Option 1: 29.13%
Option 2: 21.78%
Option 3: 42.56%
Option 4: 34.27%
Correct Answer: 29.13%
Solution : Let's denote the original radius of the cylinder as $r$ and the original height as $ℎ$. Now, if the radius is decreased by 12%, ⇒ $r$′ = $r$ −0.12$r$ = 0.88$r$ ⇒ $V'$ = $π(0.88r)^2h'$ Since the volume remains the same ⇒ $πr^{2}h$ = $π(0.88r)^2h'$ ⇒ $h'$ = $\frac{r^{2}h}{(0.88r)^2}$ ⇒ $h'$ = $\frac{r^{2}h}{(0.7744)r^2}$ ⇒ $h'$ = $\frac{100h}{0.7744}$ – $h$ ⇒ $Δℎ$ = $h'−h$ ⇒ $Δℎ$ = $\frac{100h}{0.7744}$ – $h$ ⇒ Percentage change in height = $\frac{Δh}{h}×100$ = $(\frac{100}{77.44} – 1)×100$ = 29.13% Hence, the correct answer is 29.13%.
Question : Directions: The following bar diagram depicts figures for some agricultural imports from January - May 2008. Answer (as closely as possible) the questions using the data provided here: Agricultural Imports - January to May Average cost per ton over 5 months of period What was the total cost of wheat imports in March?
Option 1: Rs. 3,212
Option 2: Rs. 5,616
Option 3: Rs. 7,042
Option 4: Rs. 2,224
Correct Answer: Rs. 5,616
Solution : Refer to the given bar graph: Cost of Wheat = Rs. 156 Total Wheat import in March = 36 tons Required cost of wheat = 36 × 156 = Rs. 5616 Hence, the correct answer is Rs. 5616.
Question : Who among the following is not a moderate?
Option 1: Pherozeshah Mehta
Option 2: Surendranath Banerjee
Option 3: Womesh Chandra Bonnerjee
Option 4: Bal Gangadhar Tilak
Correct Answer: Bal Gangadhar Tilak
Solution : The correct answer is Bal Gangadhar Tilak.
Bal Gangadhar Tilak disagreed with its moderate stance, particularly about the struggle for self-government. He started a large-scale movement for independence by focusing on religious and cultural renewal.
Question : A alone can do a work in 16 days and B alone can do the same work in 12 days. If they worked together on it for 4 days and A left. How long did B take to finish the remaining work?
Option 1: 7 days
Option 2: 5 days
Option 3: 6 days
Option 4: 8 days
Correct Answer: 5 days
Solution : Time taken by A to do the work = 16 days Part of work done by A in a day = $\frac{1}{16}$ Time taken by B to do the work = 12 days Part of work done by B in a day = $\frac{1}{12}$ Part of work done by A and B in 4 days = 4 × ( $\frac{1}{16}$+$\frac{1}{12}$) = 4 × $\frac{3+4}{48}$ = $\frac{7}{12}$ Remaining work = $1-\frac{7}{12}$ = $\frac{5}{12}$ Time taken by B to do the remaining work = $\frac{\frac{5}{12}}{\frac{1}{12}}$ = 5 days Hence, the correct answer is 5 days.
Question : The joint sector industry is one of the classifications of industries based on ______.
Option 1: source of raw material
Option 2: capital investment
Option 3: bulk and weight of raw material
Option 4: ownership
Correct Answer: ownership
Solution : The correct answer is ownership.
Ownership Industries can be divided into four categories: joint, cooperative, state-owned, or public and private. Industries in the private sector are owned and run by a single person or a group of people.
Question : How many tax slabs are classified in the GST Bill?
Option 1: Seven
Option 2: Three
Option 3: Eight
Option 4: Four
Correct Answer: Four
Solution : The correct option is Four.
India's goods and services tax (GST) has four tax slabs.
Question : Directions: In a certain code language, WORK is coded as 67, and CUP is coded as 40. How will KITE be coded in that code language?
Option 1: 36
Option 2: 45
Option 3: 38
Option 4: 42
Correct Answer: 45
Solution : Given: WORK is coded as 67, and CUP is coded as 40.
Add the positional values of the alphabet of the given word to obtain the code. WORK→23 + 15 + 18 + 11 = 67 CUP→3 + 21 + 16 = 40 Similarly, KITE→11 + 9 + 20 + 5 = 45
So, KITE is coded as 45. Hence, the second option is correct.
Question : Directions: Which of the following numbers will replace the question mark (?) in the given series? –67, –64, –58, –49, –37, –22, ?
Option 1: –2
Option 2: 2
Option 3: –4
Option 4: 4
Correct Answer: –4
Solution : Given: –67, –64, –58, –49, –37, –22, ?
The pattern is as follows – –67 + 3 = –64; –64 + 6 = –58; –58 + 9 = –49; –49 + 12 = –37; –37 + 15 = –22; –22 + 18 = –4
So, the missing number is –4. Hence, the third option is correct.
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