Staff Selection Commission Multi Tasking Staff Exam
Question : Directions: In the following question, you have to identify the correct response from the given premises stated according to the following symbols. If + means ÷, × means +, – means ×, and ÷ means –, then which of the following equations is correct?
Option 1: 36 × 6 + 3 – 2 < 20
Option 2: 36 × 6 + 3 × 2 = 20
Option 3: 36 + 6 × 3 + 2 = 20
Option 4: 36 + 6 – 3 × 2 = 20
Correct Answer: 36 + 6 – 3 × 2 = 20
Solution : Given: + means ÷, × means +, – means ×, and ÷ means –
Let's check the options – First option: 36 × 6 + 3 – 2 < 20 = 36 + 6 ÷ 3 × 2 = 36 + 2 × 2 = 36 + 4 = 40 > 20; L.H.S. is not smaller than R.H.S. Second option: 36 × 6 + 3 × 2 = 20 = 36 + 6 ÷ 3 + 2 = 36 + 2 + 2 = 40 ≠ 20; L.H.S. ≠ R.H.S. Third option: 36 + 6 × 3 + 2 = 20 = 36 ÷ 6 + 3 ÷ 2 = 6 + 1.5 = 7.5 ≠ 20; L.H.S. ≠ R.H.S. Fourth option: 36 + 6 – 3 × 2 = 20 = 36 ÷ 6 × 3 + 2 = 20 = 6 × 3 + 2 = 18 + 2 = 20; L.H.S. = R.H.S.
So, only the fourth option satisfies the equation. Hence, the fourth option is correct.
Question : Directions: Which two signs should be interchanged to make the given equation correct? 9 ÷ 3 + 7 = 4 – 6
Option 1: – and =
Option 2: ÷ and –
Option 3: + and –
Option 4: ÷ and =
Correct Answer: – and =
Solution : Given: 9 ÷ 3 + 7 = 4 – 6
Replace the given symbols according to the options one by one with the original symbols in the given equation. First option: – and = ⇒ 9 ÷ 3 + 7 – 4 = 6 = 3 + 7 – 4 = 6 = R.H.S. Second option: ÷ and – ⇒ 9 – 3 + 7 = 4 ÷ 6 = 13 ≠ 0.67 Third option: + and – ⇒ 9 ÷ 3 – 7 = 4 + 6 = 3 – 7 = 10 = –4 ≠ 10 Fourth option: ÷ and = ⇒ 9 = 3 + 7 ÷ 4 – 6 = 9 = 3 + 1.75 – 6 = 9 ≠ –1.25
So, only the first option satisfies the R.H.S. of the given equation. Hence, the first option is correct.
Question : Directions: Select the option that is related to the fifth term in the same way as the second term is related to the first term and the fourth term is related to the third term. PRAY : UWFD :: MONK : RTSP :: FAIT : ?
Option 1: KEMY
Option 2: KFNY
Option 3: KENY
Option 4: KFMY
Correct Answer: KFNY
Solution : Given: PRAY : UWFD :: MONK : RTSP :: FAIT : ?
Like, PRAY : UWFD→P(16) + 5 = U(21); R(18) + 5 = W(23); A(1) + 5 = F(6); Y(25) + 5 = D(4) And, MONK : RTSP→M(13) + 5 = R(18); O(15) + 5 = T(20); N(14) + 5 = S(19); K(11) + 5 = P(16) Similarly, for FAIT : ?→F(6) + 5 = K(11); A(1) + 5 = F(6); I(9) + 5 = N(14); T(20) + 5 = Y(25)
So, KFNY is related to FAIT. Hence, the second option is correct.
Question : 42 boys can complete a piece of work in 20 days working 8 hours per day. In how many days can 14 boys complete the same work, each boy working 12 hours per day?
Option 1: 39 days
Option 2: 40 days
Option 3: 41 days
Option 4: 42 days
Correct Answer: 40 days
Solution : Let the number of days be $D$ for 14 boys working 12 hours per day. Use the formula: $M_1D_1H_1= M_2D_2H_2$ Where $M_1$ and $M_2$ are persons, $D_1$ and $D_2$ are days and $H_1, H_2$ are hours per day. ⇒ 42 × 20 × 8 = 14 × D × 12 ⇒ $D$ = 40 Hence, the correct answer is 40 days.
Question : The length of a rope, by which a calf is tied, is decreased from 9 m to 5 m. Find the decrease in the area that can be grazed by the calf. [Use $\pi=\frac{22}{7}$]
Option 1: 112 m2
Option 2: 154 m2
Option 3: 122 m2
Option 4: 176 m2
Correct Answer: 176 m2
Solution : Given: Original length of rope = 9 m The new length of rope = 5 m (Length of rope taken as the radius of the circle) So, Old area = $\pi (9^{2}) = 81\pi $ New area = $\pi (5^{2}) = 25\pi $ So, the net change in the area $=81\pi -25\pi $ $=56\pi $ $= (56\times \frac{22}{7})$ $= \frac{1232}{7}$ $= 176\ \text{m}^{2}$ So, the decrease in the area that can be grazed by the calf is 176 m2. Hence, the correct answer is 176 m2.
Question : What is the jelly-like substance between the nucleus and the cell membrane called?
Option 1: Plasma
Option 2: Cell wall
Option 3: Plasma membrane
Option 4: Cytoplasm
Correct Answer: Cytoplasm
Solution : The correct answer is Cytoplasm.
Each cell is filled with cytoplasm, which is a thick solution. The cell membrane encloses it. It consists of water, salts, and proteins. The cytoplasm in eukaryotic cells includes all of the material inside the cell and outside of the nucleus.
Question : In a bucket, there are 40 red balls and 120 blue balls. The ratio of red to blue is:
Option 1: 1 : 3
Option 2: 3 : 4
Option 3: 1 : 4
Option 4: 2 : 3
Correct Answer: 1 : 3
Solution : Given, Number of red balls in the bucket = 40 Number of blue balls in the bucket = 120 ⇒ Ratio = 40 : 120 = 1 : 3 Hence, the correct answer is 1 : 3.
Question : Who among the following founded Brahmo Samaj in Calcutta (Kolkata)?
Option 1: Swami Vivekananda
Option 2: Swami Dayanand Saraswati
Option 3: Ishwar Chandra Vidyasagar
Option 4: Raja Ram Mohan Roy
Correct Answer: Raja Ram Mohan Roy
Solution : The correct answer is Raja Ram Mohan Roy.
The social manifestation of Brahmoism is known as Brahmo Samaj. It began as a Hindu reformist movement that was monotheistic and was valued during the Bengal Renaissance. On August 20, 1828, Raja Ram Mohan Roy and Dwarkanath Tagore founded it in Calcutta. Raja Ram Mohan Roy also founded the Atmiya Sabha in 1815.
Question : The difference between compound interest and simple interest on a sum of Rs. 16,000 for two years is Rs. 160. Find the per annum rate of interest.
Option 1: 12%
Option 2: 10%
Option 3: 11%
Option 4: 15%
Correct Answer: 10%
Solution : Given: Principal = Rs. 16,000 Time = 2 years We know, Difference between compound interest and simple interest = $P(\frac{r}{100})^2$, where $P$ = Principal, $r$ = Rate of interest ⇒ $160=16000(\frac{r}{100})^2$ ⇒ $\frac{r^2}{10000}×100=1$ ⇒ $r^2=100$ $\therefore r =10$% Hence, the correct answer is 10%.
Question : Who among the following founded the Muhammadan Anglo-Oriental College?
Option 1: Sri Aurobindo
Option 2: Muhammad Ali Jinnah
Option 3: Khan Abdul Ghaffar Khan
Option 4: Sir Syed Ahmad Khan
Correct Answer: Sir Syed Ahmad Khan
Solution : The correct answer is Sir Syed Ahmad Khan.
In 1875, Sir Sayed Ahmad Khan established the Mohammedan Anglo-Oriental College in Aligarh, drawing inspiration from the Cambridge education system. The institution later evolved into the renowned Aligarh Muslim University, pivotal in educational and social development in British India.
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