Correct Answer: 3

Solution : Given: Arun can do $\frac{2}{3}$rd of the work in 12 days.
Whole work = 1
Arun can complete the whole work in $=\frac{3×12}{2}=18$ days
Thus, $\frac{1}{6}$ th of the same work is completed = $\frac{1}{6}\times18= 3$ days
Hence, the correct answer is 3.

Correct Answer: India

Solution : The correct answer is India.

The seventh edition of the ICC Women's T20 World Cup took place in 2020. It was held in Melbourne, Australia, from February 21 to March 8, 2020. International Women's Day fell on the day of the final. Australia defeated

Correct Answer: (145, 150, 165)

Solution : Given:
(73, 78, 93)

Add 5 to the first number to get the second number and add 15 to the second number to get the third number –
⇒ (73, 78, 93) → 73 + 5 = 78, 78 + 15 = 93

Correct Answer: $1 + \sqrt2 - \sqrt3$

Solution : $p = 5 + 2\sqrt{6}$
= $(\sqrt{3})^2 + (\sqrt{2})^2 + 2\sqrt{6}$
= $(\sqrt{3} + \sqrt{2})^2 $
Now, $\sqrt{p}=\sqrt{3} + \sqrt{2}$
So, $\frac{1}{\sqrt{p}} = \sqrt{3} - \sqrt{2}$ (by rationalisation)
Thus, $\frac{\sqrt{p} - 1}{\sqrt{p}} = \frac{\sqrt{p}}{\sqrt{p}} - \frac{{1}}{\sqrt{p}} = 1 - \frac{{1}}{\sqrt{p}}$
Putting

Correct Answer:

Solution : Because there is no restriction on the rotation of the figure, we will check all the possible orientations of the question figure in which of the given option figures it can fit itself. By comparison of all option figures, the question figure is embedded only in

Correct Answer: 8 hours

Solution : The rate at which Raju can paint the wall is $\frac{1}{36}$ of the wall per hour.
Similarly, the rates for Angad and Sumit are $\frac{1}{18}$ and $\frac{1}{24}$ of the wall per hour, respectively.
When they all work together, their combined rate is,
$\frac{1}{36} +

Correct Answer: fifth

Solution : The correct option is the fifth

The Finance Commission in India is constituted by the President at the expiration of every five years, or earlier, as per necessity. The Finance Commission is a constitutional body that plays a crucial role in recommending the distribution of

Correct Answer: $3$

Solution : Given sequence: $\left (1+\frac{1}{2} \right):\left (1+\frac{1}{2} \right) \left (1+\frac{1}{3} \right): \left (1+\frac{1}{2} \right )\left (1+\frac{1}{3} \right)\left (1+\frac{1}{4} \right): .........$
$T{_1}= 1+\frac{1}{2} = \frac{3}{2}$
$T{_2}= (1+\frac{1}{2})(1+\frac{1}{3}) = \frac{3}{2}\times \frac{4}{3}= 2$
$T{_3}= (1+\frac{1}{2})(1+\frac{1}{3})(1+\frac{1}{4}) = \frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}= \frac{5}{2}$
$T{_4}= (1+\frac{1}{2})(1+\frac{1}{3})(1+\frac{1}{4})(1+\frac{1}{5}) = \frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times \frac{6}{5}= 3$
Hence,

Correct Answer: 21

Solution : In a column of the given table, find the difference between the second and the third numbers and then multiply the resultant number by the first number to obtain the fourth number.

In the first column→(48 – 28) × 3 = 20 × 3 =

Correct Answer: 156

Solution : Given:
90, 110, 132, ?, 182

Add even numbers, starting from 20 to the previous term to obtain the missing term.
90 + 20 = 110; 110 + 22 = 132; 132 + 24 = 156; 156 + 26 = 182

So, 156 is the