Staff Selection Commission Sub Inspector Exam
Question : What is the amount of insurance coverage available for accidental death under the Pradhan Mantri Suraksha Bima Yojana (PMSBY)?
Option 1: INR 2 lakh
Option 2: INR 3 lakh
Option 3: INR 1 lakh
Option 4: INR 4 lakh
Correct Answer: INR 2 lakh
Solution : The correct option is INR 2 lakh.
The amount of insurance coverage available for accidental death under the Pradhan Mantri Suraksha Bima Yojana (PMSBY) is INR 2 lakh. The PMSBY is a government-backed insurance scheme that provides accidental death and disability coverage at an affordable premium.
Question : What is the minimum over rate in a Test match?
Option 1: 10 overs/h
Option 2: 15 overs/h
Option 3: 12 overs/h
Option 4: 13 overs/h
Correct Answer: 15 overs/h
Solution : The correct option is 15 overs/h.
In Test cricket, the International Cricket Council (ICC) has set a minimum required over rate of 15 overs per hour. According to the ICC playing conditions, if a team fails to meet this required overrate, they may face penalties, including fines for the captain and potential suspension for repeat offences.
Question : If $a-\frac{1}{a}=4$, then the value of $a+\frac{1}{a}$ is:
Option 1: $5 \sqrt{5}$
Option 2: $4 \sqrt{5}$
Option 3: $2 \sqrt{5}$
Option 4: $3 \sqrt{5}$
Correct Answer: $2 \sqrt{5}$
Solution : Given: $a-\frac{1}{a}=4$ Squaring both sides, we get, ⇒ $a^2+\frac{1}{a^2}-2=16$ ⇒ $a^2+\frac{1}{a^2}=16+2$ ⇒ $a^2+\frac{1}{a^2}=18$ Adding 2 on both sides, we get, ⇒ $a^2+\frac{1}{a^2}+2=18+2$ ⇒ $(a+\frac{1}{a})^2=20$ $\therefore a+\frac{1}{a}=2\sqrt5$ Hence, the correct answer is $2\sqrt5$.
Question : If $\frac{\tan\theta +\cot\theta }{\tan\theta -\cot\theta }=2, (0\leq \theta \leq 90^{0})$, then the value of $\sin\theta$ is:
Option 1: $\frac{2}{\sqrt3}$
Option 2: $\frac{\sqrt3}{2}$
Option 3: $\frac{1}{2}$
Option 4: $1$
Correct Answer: $\frac{\sqrt3}{2}$
Solution : $\frac{\tan\theta +\cot\theta }{\tan\theta -\cot\theta }=2$ Use rule of componendo and dividendo i.e. If $\frac{a}{b}=\frac{c}{d}$ then, $\frac{a+b}{a-b}=\frac{c+d}{c-d}$. we have, ⇒ $\frac{\tan\theta +\cot\theta +\tan\theta -\cot\theta}{\tan\theta +\cot\theta -\tan\theta +\cot\theta}=\frac{2+1}{2-1}$ ⇒$\frac{2\tan\theta}{2\cot\theta} = 3$ ⇒ $\tan^2\theta=3$ ⇒ $\sin^2\theta= 3\cos^2\theta$ ⇒ $\sin^2\theta= 3(1-\sin^2\theta)$ ⇒ $4\sin^2\theta= 3$ ⇒ $\sin\theta=\frac{ \sqrt3 }{2}$ Hence, the correct answer is $\frac{ \sqrt3 }{2}$.
Question : Directions: From the given options, which answer figure can be formed by folding the figure given in the question?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : In the 3D view of dice, 1. Each face out of the three faces in the 3D view should be from all the pairs. 2. Two opposite faces cannot appear adjacently in the 3D view of a folded cube figure. So, the opposite pairs of faces are as follows –
(6 ⇔ 4), (3 ⇔ 1), and (5 ⇔ 2) are the opposite pairs of faces.
Thus,
is possible and will be formed by folding the dice. Hence, the second option is correct.
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "no error."
The lions kill the animals and eat his meat.
(1) The lions
(2) and eat his meat
(3) kill the animals
(4) No error
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The error is in the second option: eat his meat.
The part "and eat his meat" contains an error. The possessive adjective "his" is used to indicate that something belongs to or relates to a male and is not used with the plural form of animals. Instead, the plural pronoun "their" is used in the correct context to match the plural noun "animals".
Therefore, the correct sentence should be "The lions kill the animals and eat their meat".
Question : The Bishnu Rabha Award 2019 went to the noted ________ dance exponent Kumari Laitjonam Ebampisok Devi.
Option 1: Odissi
Option 2: Manipuri
Option 3: Kuchipudi
Option 4: Kathakali
Correct Answer: Manipuri
Solution : The correct answer is Manipuri.
Kumari Laitjonam Ebampisok Devi, a Manipuri dance maestro from Hojai, received the Kalaguru Bishnu Rabha Award in 2019. The award was presented by Chief Minister Sarbananda Sonowal at a ceremony held on June 20 in Rongjuli, Goalpara district, as part of the Bishnu Rabha Divas.
Question : Simplify: $5 \frac{1}{3}-\left\{4 \frac{1}{3}+\left(3 \frac{1}{3} \div \overline{2 \frac{1}{3}-\frac{1}{3}}\right)\right\}$
Option 1: $\frac{2}{3}$
Option 2: $\frac{1}{3}$
Option 3: $-\frac{1}{3}$
Option 4: $-\frac{2}{3}$
Correct Answer: $-\frac{2}{3}$
Solution : $5 \frac{1}{3}-\left\{4 \frac{1}{3}+\left(3 \frac{1}{3} \div \overline{2 \frac{1}{3}-\frac{1}{3}}\right)\right\}$ $=\frac{16}{3}-\left\{ \frac{13}{3}+\left( \frac{10}{3} \div \overline{\frac{7}{3}-\frac{1}{3}}\right)\right\}$ $=\frac{16}{3}-\left\{ \frac{13}{3}+\left( \frac{10}{3} \div 2\right)\right\}$ $=\frac{16}{3}-\left\{ \frac{13}{3}+( \frac{5}{3})\right\}$ $=-\frac{2}{3}$ Hence, the correct answer is $-\frac{2}{3}$.
Question : If $r$ is the remainder when each of 6454, 7306, and 8797 is divided by the greatest number $d(d>1)$, then $(d-r)$ is equal to:
Option 1: 126
Option 2: 64
Option 3: 137
Option 4: 149
Correct Answer: 149
Solution : If the remainder in each case is the same. 7306 – 6454 = 852 8797 – 7306 = 1491 8797 – 6454 = 2343 HCF of 852, 1491, and 2343:
HCF = 213 So, the greatest number, $d$ = 213 Remainder, $r$ = 64 $\therefore d - r$ = 213 – 64 = 149 Hence, the correct answer is 149.
Question : Directions: In a certain code language, CAGES is written as NADYB. How is WATER written in that code language?
Option 1: MAQYV
Option 2: SGWEB
Option 3: QCPVR
Option 4: VYQAM
Correct Answer: MAQYV
Solution : Given: CAGES is written as NADYB.
Subtract consecutive natural numbers from the place values of each letter of CAGES and then reverse them to get the required code – C – 1 = B; A – 2 = Y; G – 3 = D; E – 4 = A; S – 5 = N BYDAN→NADYB Thus, CAGES is coded as NADYB. Similarly, follow the same pattern for WATER – W – 1 = V; A – 2 = Y; T – 3 = Q; E – 4 = A; R – 5 = M VYQAM→MAQYV
Thus, WATER is coded as MAQYV. Hence, the first option is correct.
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