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Staff Selection Commission Sub Inspector Exam

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Question : Simplify.
$\cos \left(36^{\circ}-\mathrm{A}\right) \cos \left(36^{\circ}+\mathrm{A}\right)+\cos \left(54^{\circ}-\mathrm{A}\right) \cos \left(54^{\circ}+\mathrm{A}\right)$

Option 1: $\cos A$

Option 2: $\sin 2A$

Option 3: $\cos 2A$

Option 4: $\sin A$

Team Careers360 25th Jan, 2024

Correct Answer: $\cos 2A$


Solution :

Given: $\cos(36^{\circ}-A) \cos (36^{\circ}+A)+\cos (54^{\circ}-A) \cos (54^{\circ}+A)$
= $\sin[90^{\circ} - (36^{\circ} - A)]\sin[90^{\circ} - (36^{\circ} + A)] + \cos (54^\circ - A) \cos (54^\circ + A)$
= $\sin(54^\circ + A)\sin(54^\circ - A) + \cos (54^\circ - A)\cos (54^\circ + A)$
= $\cos(54^{\circ} + A

82 Views

Question : Directions: If LOVE is coded as 27, then how is COME coded as?

Option 1: 38

Option 2: 18

Option 3: 28

Option 4: 8

Team Careers360 19th Jan, 2024

Correct Answer: 18


Solution : Given:
LOVE is coded as 27.

Add the place value of the letters of the LOVE and divide it by 2 to get the codes –
L→12; O→15; V→22; E→5
(12 + 15 + 22 + 5) ÷ 2 = 27
So, LOVE is coded

31 Views

Question : Which of the following statements is correct regarding fuse wire?

Option 1: It has a low melting point and low conductivity.

Option 2: It has a high melting point and low conductivity.

Option 3: It has a low melting point and high conductivity.

Option 4: It has a high melting point and high conductivity.

Team Careers360 23rd Jan, 2024

Correct Answer: It has a low melting point and high conductivity.


Solution : The correct answer is that it has a low melting point and high conductivity.

The material used to make fuse wire has a high conductivity and a low melting point. It will prevent excessive power from

15 Views

Question : The next number of the sequences 3, 7, 15, 31, 63, ? is:

Option 1: 95

Option 2: 111

Option 3: 123

Option 4: 127

Team Careers360 25th Jan, 2024

Correct Answer: 127


Solution : Given: The sequences 3, 7, 15, 31, 63,?
Here, 3 + (22) = 7
7 + (23) = 15
15 + (24) = 31
31 + (25) = 63
63 + (26) = 127
Hence,

16 Views

Question : If $\left (\sqrt{5} \right)^{7}\div \left (\sqrt{5} \right)^{5}=5^{p},$ then the value of $p$ is:

Option 1: $5$

Option 2: $2$

Option 3: $\frac{3}{2}$

Option 4: $1$

Team Careers360 20th Jan, 2024

Correct Answer: $1$


Solution : Given: $\frac{(\sqrt{5})^7}{(\sqrt{5})^5} = 5^p$
$⇒(\sqrt{5})^{7 - 5} = 5^p$
$⇒(\sqrt{5})^2 = 5^p$
$⇒5^{\frac{1}{2}×2} = 5^{p}$
$⇒5^1=5^p$
Comparing both sides, we get,
$\therefore p=1$
Hence, the correct answer is $1$.

18 Views

Question : El Nino occurs over:

Option 1: Atlantic Ocean

Option 2: Indian Ocean

Option 3: Pacific Ocean

Option 4: Mediterranean Sea

Team Careers360 11th Jan, 2024

Correct Answer: Pacific Ocean


Solution : The correct answer is the Pacific Ocean.

El Nino is a climate phenomenon characterised by unusually warm surface waters in the eastern tropical Pacific Ocean. When the eastern tropical Pacific's coastal waters warm (El Nino), the air pressure above the ocean falls. Increased

83 Views

Question : Select the most appropriate option to substitute the underlined segment in the given sentence.
Any sort of unfair conduct is not tolerated in international sports tournaments as it can completely ruin an athlete’s career.
 

Option 1: straw in the eye

Option 2: hand in the mud

Option 3: foul play

Option 4: red handed

Team Careers360 25th Jan, 2024

Correct Answer: foul play


Solution : The correct choice is the third option.

Foul play is a term commonly used to describe dishonest or unsportsmanlike behaviour, especially when it comes to breaking the rules of a game or competition. It is well-established in the context of sports ethics, making it

17 Views

Question : Directions: Select the letter cluster that can replace the question mark (?) in the given letter cluster series.
UKS, ZPX, EUC, JZH, ?

Option 1: ODN

Option 2: OEM

Option 3: PEM

Option 4: ODM

Team Careers360 17th Jan, 2024

Correct Answer: OEM


Solution : Given:
UKS, ZPX, EUC, JZH, ?

Add 5 to each letter of the previous term to obtain the next term in the series –
UKS→U + 5 = Z; K + 5 = P; S + 5 = X
ZPX→Z +

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