Staff Selection Commission Sub Inspector Exam
Question : On which of the following dates/dates, the winter solstice is observed in the Northern Hemisphere?
I. 21st December
II. 5th August
III. 10th January
Option 1: Only I
Option 2: I and II both
Option 3: Only III
Option 4: Only II
Correct Answer: Only I
Solution : The correct answer is only I.
Solstice is the day when the Earth is tilted to its maximum towards the Northern or Southern side. In the Northern Hemisphere, the Winter Solstice is usually observed on December 21 or 22, whereas the summer solstice
Question : Select the most appropriate one-word substitution of the given group of words. A list of source materials that are used or consulted in the preparation of a work or that are referred to in the text.
Option 1: Bibliography
Option 2: Bibliophile
Option 3: Bibliotheca
Option 4: Bibliomemoir
Correct Answer: Bibliography
Solution : The first option is correct.
The most appropriate one-word substitution for the given group of words a list of source materials that are used or consulted in the preparation of a work or that are referred to in the text is bibliography.
A bibliography
Question : The speed of a boat in still water is 20 km/hr, while the river is flowing at a speed of 8 km/hr and the time taken to cover a certain distance upstream is 6 hr more than the time taken to cover the same distance downstream. Find the distance.
Option 1: 120 km
Option 2: 336 km
Option 3: 126 km
Option 4: 125 km
Correct Answer: 126 km
Solution : The speed of a boat in still water = 20 km/hr Speed of river = 8 km/hr Upstream speed = 20 – 8 = 12 km/hr Downstream speed = 20 + 8 = 28 km/hr Let $x$ be the distance. Time taken to cover
Question : The sum of the two numbers is 1215 and their HCF is 81. If the numbers lie between 500 and 700, then the sum of the reciprocals of the numbers is _____.
Option 1: $\frac{5}{702}$
Option 2: $\frac{5}{378}$
Option 3: $\frac{5}{1512}$
Option 4: $\frac{5}{1188}$
Correct Answer: $\frac{5}{1512}$
Solution : Let the number be 81$x$ and 81$y$ 81$x$ + 81$y$ = 1215 ⇒ $x + y = \frac{1215}{81}$ = 15 Pair of $x+ y$ = (1,14), (2,13), (4,11), and (7,8) ⇒ $x = 7$ and $y = 8$ First number = 81 × 7 =
Question : A cone-shaped storage tank's height and radius are 9 feet and 7 feet, respectively. Determine how much liquid the tank can contain. (Take $\pi$ = 3.14)
Option 1: 471 cubic feet
Option 2: 450 cubic feet
Option 3: 435.32 cubic feet
Option 4: 461.58 cubic feet
Correct Answer: 461.58 cubic feet
Solution : The volume $V$ of a cone, where $r$ is the radius and $h$ is the height. $V = \frac{1}{3} \pi r^2 h$ $= \frac{1}{3} \times 3.14 \times (7)^2 \times 9$ $= 461.58$ Hence, the correct answer is 461.58 cubic feet.
Question : Directions: In the following question observe the series and figure out the pattern used to form it. What will be the 3rd term of the series? 1, 5, ?, 22, 35
Option 1: 11
Option 2: 14
Option 3: 10
Option 4: 12
Correct Answer: 12
Solution : Given: 1, 5, ?, 22, 35
The difference between each consecutive term is increasing by 3 – 1 + 4 = 5 5 + (4 + 3) = 5 + 7 = 12 12 + (7 + 3) = 12 + 10 = 22 22
Question : A sum amounts to INR 7,562 in 4 years and to INR 8,469.44 in 5 years, at a certain rate per cent per annum when the interest is compounded yearly. If INR 10,000 at the same rate of interest is borrowed for two years, then what will be the compound interest (in INR)?
Option 1: 2,544
Option 2: 1,736
Option 3: 2,764
Option 4: 1,965
Correct Answer: 2,544
Solution : Let P be the principal. We know, $\text{Total Amount}=\text{Principal}×(1+\frac{\text{Rate}}{100})^{\text{Time}}$ $\text{P}(1 +\frac{r}{100})^4$ = 7562 -----------------(1) $\text{P}(1 +\frac{r}{100})^5$ = 8469.44 -------------(2) Dividing (2) by (1) we get, $(1 +\frac{r}{100}) = \frac{846944}{756200}$ $⇒\frac{r}{100} = 1.12 - 1$ $\therefore r = 12$ Compound Interest $=10,000 × [(1 + \frac{12}{100})^2
Question : As observed from the top of a lighthouse, 45 m high above the sea level, the angle of depression of a ship, sailing directly towards it, changes from 30° to 45°. The distance travelled by ship during the period of observation is: (Your answer should be correct to one decimal place.)
Option 1: 32.9 m
Option 2: 33.4 m
Option 3: 36.9 m
Option 4: 24.8 m
Correct Answer: 32.9 m
Solution : Given, AB = 45 m In $\triangle$ABC $\tan$ 45° = $\frac{\text{AB}}{\text{BC}}$ ⇒ 1 = $\frac{45}{\text{BC}}$ ⇒ BC = 45 m In $\triangle$ABD $\tan 30° = \frac{\text{AB}}{\text{BD}}$ ⇒ $\frac{1}{\sqrt{3}} = \frac{45}{\text{BD}}$ ⇒ BD = $45\sqrt{3}$ Also, BD = CD + BC ⇒ $45\sqrt{3}$ = CD
Question : $\frac{\sqrt{24}+\sqrt{216}}{\sqrt{96}}$ is equal to:
Option 1: 1
Option 2: 6
Option 3: 8
Option 4: 2
Correct Answer: 2
Solution : Given: $\frac{\sqrt{24}+\sqrt{216}}{\sqrt{96}}$ = $\frac{2\sqrt{6}+6\sqrt{6}}{4\sqrt{6}}$ = $\frac{8\sqrt{6}}{4\sqrt{6}}$ = $2$ Hence, the correct answer is 2.
Question : If a 4-digit number x58y is exactly divisible by 9, then the least value of (x + y) is:
Option 1: 4
Option 2: 5
Option 3: 3
Correct Answer: 5
Solution : A number is divisible by 9 if the sum of its digits is divisible by 9. Given a 4-digit number x58y, the sum of its digits is x + 5 + 8 + y = (x + y) + 13. For the number to be
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