Staff Selection Commission Sub Inspector Exam
Question : Directions: Select the set in which the numbers are related similarly to the numbers of the following sets. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) (17, 12, 612) (6, 14, 252)
Option 1: (3, 6, 108)
Option 2: (11, 4, 144)
Option 3: (13, 7, 273)
Option 4: (2, 3, 12)
Correct Answer: (13, 7, 273)
Solution : Given: (17, 12, 612); (6, 14, 252)
Multiply the product of the first and second numbers by 3, to get the third number – (17, 12, 612)→17 × 12 × 3 = 612 (6, 14, 252)→6 × 14 × 3 = 252
Let's
Question : The LCM of $x^2-8x + 15$ and $x^2-5x + 6$ is:
Option 1: $(x-2)(x-3)^2(x-5)$
Option 2: $(x + 5) (x + 2) (x + 3)$
Option 3: $(x + 5) (x - 2) (x - 3)$
Option 4: $(x - 5) (x - 2) (x - 3)$
Correct Answer: $(x - 5) (x - 2) (x - 3)$
Solution : Given: The equations are $x^2- 8x + 15$ and $x^2- 5x + 6$. LCM is the product of every prime factor that is present in the numbers to the greatest power. The factors of $x^2-8x+15$ is given
Question : The minimum number of forces to keep a particle in equilibrium is
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : The correct option is 2.
The minimum of forces needed to maintain a particle in equilibrium is two. This is because a particle in equilibrium is not accelerating. The net force acting on a particle must be zero for it not to accelerate. A single
Question : In which of the following languages did Amoghavarsha write Kavirajamarga?
Option 1: Tamil
Option 2: Sanskrit
Option 3: Kannada
Option 4: Telugu
Correct Answer: Kannada
Solution : The correct answer is Kannada.
Kavirajamarga is the oldest known grammar, rhetoric, and poetics text on Kannada grammar. The renowned Rashtrakuta King Amoghavarsha inspired it or contributed to its writing, and other historians believe it was partially inspired by the Sanskrit text Kavyadarsha.
Question : Directions: I walk 12 km to the North, then 10 kilometres East, and then 12 km south. How far am I from the starting point?
Option 1: 34 km
Option 2: 24 km
Option 3: 22 km
Option 4: 10 km
Correct Answer: 10 km
Solution : Firstly, we will draw the diagram as per the given instructions –
In the above figure, O is the starting point and C is the finishing point. So, OC is the distance from the starting point. Here, OC = AB = 10 km.
So,
Question : The value of $\frac{0.325 \times 0.325+0.175 \times 0.175-25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}$ lies between:
Option 1: 0.35 and 0.45
Option 2: 0.15 and 0.25
Option 3: 0.25 and 0.35
Option 4: 0.05 and 0.15
Correct Answer: 0.25 and 0.35
Solution : Given: $\frac{0.325 \times 0.325+0.175 \times 0.175-25 \times 0.00455}{5 \times 0.0065 \times 3.25-7 \times 0.175 \times 0.025}$ $=\frac{0.325 \times 0.325+0.175 \times 0.175-2 \times 0.325\times0.175}{(0.325)^2- (0.175)^2 }$ $=\frac{(0.325 -0.175)^2}{(0.325+0.175)(0.325-0.175) }$ $=\frac{(0.325 -0.175)}{(0.325+0.175) }$ $=0.3$ Hence, the correct answer is 0.25 and 0.35.
Question : The speed of the current is 5 km/h. A motorboat goes 10 km upstream and back again to the starting point in 50 minutes. The speed (in km/h) of the motorboat in still water is:
Option 1: 20
Option 2: 26
Option 3: 25
Option 4: 28
Correct Answer: 25
Solution : Let the speed of the boat be $x$ km/h. Given: The speed of current = 5 km/h Therefore, upstream speed of boat = $(x-5)$ km/h Downstream speed of the boat = $(x + 5)$ km/h According to the question, $ \frac{10}{x-5}+\frac{10}{x+5}=\frac{50}{60} $ ⇒ $10 \left(\frac{x+5+x-5}{x^{2}-25}\right)=\frac{5}{6}$
Question : In a cricket match, there are three types of tickets say A, B, and C each costing Rs. 1000, Rs. 500, and Rs. 200 respectively. The ratio of the tickets sold in categories A, B, and C is $3:2:5$. If the total collection from selling the tickets is Rs. 2.5 crores. Find the total number of tickets sold.
Option 1: 5000
Option 2: 4800
Option 3: 50000
Option 4: 52000
Correct Answer: 50000
Solution : Let the number of tickets be $3n, 2n,$ and $5n$. According to the question, $(3n×1000)+(2n×500)+(5n×200) = 25000000$ ⇒ $3000n+1000n+1000n = 25000000$ ⇒ $5000n = 25000000$ ⇒ $n = \frac{25000000}{5000}$ $\therefore n= 5000$ So, total number of tickets $=(3n+2n+5n) = 10n= (10 × 5000) = 50000$
Question : Directions: Select the figure from among the given options that can replace the question mark (?) in the following series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the question figure, The box is rotated by 90° in an anticlockwise direction and for each box, one more triangle has been added. Thus, the required missing figure is –
Therefore, the complete figure is as follows –
Hence, the third option is correct.
Question : Directions: Arrange the following words in the order in which they appear in an English dictionary. 1. General 2. Gender 3. Gasket 4. Genial 5. Gather
Option 1: 5, 3, 2, 1, 4
Option 2: 4, 3, 2, 1, 5
Option 3: 3, 5, 2, 4, 1
Option 4: 3, 5, 2, 1, 4
Correct Answer: 3, 5, 2, 1, 4
Solution : Given: 1. General 2. Gender 3. Gasket 4. Genial 5. Gather
Step 1: The first letter of each word is the same, so move on to the next letter. Step 2: The second letter of each word is either a or
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