Staff Selection Commission Sub Inspector Exam
Question : Directions: Select the option that is related to the third word in the same way as the second word is related to the first word. (The words must be considered meaningful words and must not be related to each other based on the number of letters/number of consonants/vowels in the word.) Cat : Paw :: Crow : ?
Option 1: Hoff
Option 2: Wings
Option 3: Beak
Option 4: Claw
Correct Answer: Claw
Solution : Given: Cat : Paw :: Crow : ?
Like, the foot of a cat is called a paw. Similarly, the foot of a crow is called a claw.
Hence, the fourth option is correct.
Question : The radius of a hollow sphere is 21 cm. It is cut into two equal halves by a plane passing through its centre. What is 75% of the curved surface area (in cm2, rounded off to the nearest tens) of the hemisphere? (Take $\pi=\frac{22}{7}$ )
Option 1: 4160
Option 2: 3470
Option 3: 2080
Option 4: 2770
Correct Answer: 2080
Solution : Here, radius, $r$ = 21 cm The curved surface area of a hemisphere $= 2\pi r^2=2×\frac{22}{7}×21^2=2772\ \text{cm}^2$ 75% of the curved surface area $= 2772×\frac{75}{100}=2079\ \text{cm}^2$ If we round off it to the nearest tens, we get 2080 cm2. Hence, the correct answer
Question : A person was standing on a road near a mall. He was 1215 m away from the mall and able to see the top of the mall from the road in such a way that the top of a tree, which is in between him and the mall, was exactly in line of sight with the top of the mall. The tree's height is 20 m and it is 60 m away from him. How tall (in m) is the mall?
Option 1: 300
Option 2: 375
Option 3: 405
Option 4: 250
Correct Answer: 405
Solution : Let the height of the mall be AB. In $\triangle DEC$, $\tan\theta = \frac{DE}{CE}$ ⇒ $\tan\theta = \frac{20}{60}$ ⇒ $\tan\theta = \frac{1}{3}$ In $\triangle ABC$, $\tan\theta = \frac{AB}{BC}$ ⇒ $\frac{1}{3} = \frac{AB}{1215}$ ⇒ AB = 405 m Hence, the correct answer is 405.
Question : Directions: Select the figure that will come next in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the question figure – 1. The circle is shifted one position in an anticlockwise direction. 2. The triangle is shifted in one position in an anticlockwise direction. So, following the above pattern, the required figure will be as follows –
Therefore, the figure in
Question : Cooking gas is a mixture of:
Option 1: methane and ethylene
Option 2: carbon dioxide and oxygen
Option 3: butane and propane
Option 4: carbon monoxide and carbon dioxide
Correct Answer: butane and propane
Solution : The correct option is butane and propane.
Cooking gas typically refers to liquefied petroleum gas (LPG), which is a mixture of primarily two hydrocarbons: propane (C3H8) and butane (C4H10). These gases are commonly used
Question : Directions: In each of the following questions, Which answer figure will complete the series?
Solution : According to the given figures – 1. The number of small circles surrounding the small square is increased by one in each figure series as compared to the previous figure in an anticlockwise direction. 2. The position of small circles outside the sides of the square
Question : In the given figure, the area of isosceles triangle $\text{PQT}$ is $128\;\mathrm{cm^2}$ and $\text{QT = PQ}$, $\text{PQ= 4 PS}$ and $\text{PT || SR}$. Then what is the area (in $\mathrm{cm^2}$ ) of the quadrilateral $\text{PTRS}$?
Option 1: $80$
Option 2: $64$
Option 3: $124$
Option 4: $72$
Correct Answer: $64$
Solution : Given that $\mathrm{PQT}$ is an isosceles triangle with $\mathrm{QT = PQ}$, and $\mathrm{PQ= 4 PS}$. The height of the triangle $\mathrm{PQT}$ is four times the height of the quadrilateral $\mathrm{PTRS}$. The area of a triangle $=\frac{1}{2} \times \text{base} \times \text{height}$ The area of the triangle
Question : Directions: In the following question, a piece of paper is folded and cut as shown below in the question figures. From the given answer figures, indicate how it will appear when opened.
Solution : When the given folded paper is unfolded, it will look like –
Hence, the first option is correct.
Question : $\frac{33}{5}×\frac{33}{5}\div 2×3\frac{3}{5}×\frac{2}{5} +\frac{2}{5}×\frac{2}{5}$ = ?
Option 1: 15
Option 2: 31.52
Option 3: 17
Option 4: 18
Correct Answer: 31.52
Solution : $\frac{33}{5}×\frac{33}{5}\div2×3\frac{3}{5}×\frac{2}{5}+\frac{2}{5}×\frac{2}{5}$ = $\frac{33}{5}×\frac{33}{10}×\frac{18}{5}×\frac{2}{5}+\frac{2}{5}×\frac{2}{5}$ = $\frac{19602}{625}+\frac{4}{25}$ = $\frac{19602+100}{625}$ = $\frac{19702}{625}$ = 31.52 Hence, the correct answer is 31.52.
Question : Direction: The table given below shows the production (in 000 tonnes) of five companies from 2012 to 2016.
The production of company R in 2014 is how much percent more than the production of company R in 2013?
Option 1: 12.68
Option 2: 11.56
Option 3: 14.42
Option 4: 15.31
Correct Answer: 12.68
Solution : The production of company R in the year 2014 = 302 The production of company R in the year 2013 = 268 Required percentage = $\frac{302-268}{268}\times 100= 12.68\%$ Hence, the correct answer is 12.68.
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