Staff Selection Commission Sub Inspector Exam
Question : When a host is exposed to antigens, which may be in the form of living or dead microbes or other proteins, antibodies are produced in the host body. This type of immunity is called ______ immunity.
Option 1: acquired
Option 2: active
Option 3: passive
Option 4: strong
Correct Answer: active
Solution : The correct answer is active.
When a host encounters antigens, which could be living or dead microbes or other proteins, the host's body produces antibodies in response. This form of immunity is termed "active immunity." Active immunity is a gradual process and can be either
Question : If $\frac{\cos \theta}{1-\sin \theta}+\frac{\cos \theta}{1+\sin \theta}=4,0^{\circ}<\theta<90^{\circ}$, then what is the value of $(\sec \theta+\operatorname{cosec} \theta+\cot \theta) ?$
Option 1: $1+2 \sqrt{3}$
Option 2: $\frac{1+2 \sqrt{3}}{3}$
Option 3: $\frac{2+\sqrt{3}}{3}$
Option 4: $2+\sqrt{3}$
Correct Answer: $2+\sqrt{3}$
Solution : Given, $\frac{\cos \theta}{1-\sin \theta}+\frac{\cos \theta}{1+\sin \theta}=4$ ⇒ $\frac{\cos\theta(1+\sin\theta)+\cos\theta(1-\sin\theta)}{(1+\sin\theta)(1-\sin\theta)}=4$ ⇒ $\frac{\cos\theta+\sin\theta\cos\theta+\cos\theta-\sin\theta\cos\theta}{(1+\sin\theta)(1-\sin\theta)}=4$ ⇒ $\frac{2\cos\theta}{1-\sin^2\theta}=4$ [As $\sin^2\theta+\cos^2\theta=1$] ⇒ $\frac{\cos\theta}{\cos^2\theta}=2$ ⇒ $\cos\theta=\frac{1}{2}$ ⇒ $\theta=60°$ Now, $\sec \theta+\operatorname{cosec} \theta+\cot \theta=\sec60°+\operatorname{cosec}60°+\cot60°$ $=2+\frac{2}{\sqrt3}+\frac1{\sqrt3}$ $=\frac{2\sqrt3+2+1}{\sqrt3}$ $=\frac{2\sqrt3+3}{\sqrt3}$ $=2+\sqrt3$ Hence, the correct answer is $2+\sqrt3$.
Question : A canister holds 36 litres of a mixture of milk and water in a ratio of 3 : 1. 15 litres of milk is added to the canister. The new ratio of the mixture is:
Option 1: 12 : 5
Option 2: 14 : 3
Option 3: 7 : 4
Option 4: 9 : 4
Correct Answer: 14 : 3
Solution : Given: A canister holds 36 litres of a mixture of milk and water in a ratio of 3 : 1. Quantity of milk = $\frac{3}{4} × 36 = 27$ Quantity of water = $\frac{1}{4} × 36 = 9$ After adding 15 litres of
Question : Directions: In the following question a series is given, with one number missing. select the missing number from the given alternatives. 84, 42, 28, 21, ?
Option 1: 10.5
Option 2: 16.8
Option 3: 18.4
Option 4: 19.6
Correct Answer: 16.8
Solution : Given: 84, 42, 28, 21, ?
Let's apply the pattern – 84 ÷ (1 + $\frac{1}{1}$) = 42; 42 ÷ (1 + $\frac{1}{2}$) = 28; 28 ÷ (1 + $\frac{1}{3}$) = 21; 21 ÷ (1 + $\frac{1}{4}$) = 16.8
So, 16.8 is the missing term
Question : The value of $\tan1° \tan2° \tan3°...\tan89°$ is:
Option 1: $1$
Option 2: $0$
Option 3: $\sqrt{3}$
Option 4: $\frac{1}{\sqrt{3}}$
Correct Answer: $1$
Solution : $\tan1° \tan2° \tan3°...\tan89°$ $= \tan1° \tan2° \tan3°...\tan45°...\tan(90-3)°\tan(90-2)°\tan(90-1)°$ $=\tan1° \tan2° \tan3°...\tan45°...\cot3°\cot2°\cot1°$ As we know, $\tan\theta=\frac{1}{\cot\theta}$ So, it will cancel out all the terms except $\tan45°$. $=\tan45°$ $= 1$ Hence, the correct answer is $1$.
Question : Directions: If P denotes ×, Q denotes ÷, R denotes +, and S denotes –, then what will come in place of (?) in the following equation? $\sqrt[4]{81}$ R 6 P 3 S 26 R 64 = ?
Option 1: 63
Option 2: 65
Option 3: 56
Option 4: 59
Correct Answer: 59
Solution : Given: $\sqrt[4]{81}$ R 6 P 3 S 26 R 64 = ?
After replacing the letters with the mathematical signs, we get: = $\sqrt[4]{81}$ + 6 × 3 – 26 + 64 = 3 + 6 × 3 – 26 + 64 = 3 +
Question : Which of the following diseases has been eradicated worldwide?
Option 1: Plague
Option 2: Dracunculiasis
Option 3: Chickenpox
Option 4: Smallpox
Correct Answer: Smallpox
Solution : The correct answer is Smallpox.
Smallpox is a deadly and highly contagious viral disease, caused by the Variola virus and now it is successfully eradicated worldwide, the last known case of smallpox was recorded in 1977 in Ethiopia and it was declared to be
Question : Directions: In a code language, if my personal use is written as 521, use these things is written as 169, and personal things are written as 29, then which phrase would code 569 represent in this language?
Option 1: my personal things
Option 2: my these things
Option 3: these personal things
Option 4: my personal use
Correct Answer: my these things
Solution : Given: 1. my personal use⇒521 2. use these things⇒169 3. personal things⇒29
By comparing all the above–coded sentences, we find that – In sentences 1 and 2, use is a common word and 1 is a common code. In sentences 2 and 3,
Question : Directions: Four pairs of letter clusters have been given out of which three are alike in some manner, while one is different. Choose the odd one.
Option 1: NVH–KUK
Option 2: REA–ODD
Option 3: CWX– AVZ
Option 4: TXB–QWE
Correct Answer: CWX– AVZ
Solution : Let's check each option – First option: NVH–KUK; N – 3, V – 1, H + 3 = KUK Second option REA–ODD; R – 3, E – 1, D + 3 = ODD Third option: CWX–AVZ; C – 2, W – 1, X +
Question : Directions: The following bar chart represents the number of first-year B.Com. students of St. Xavier's College using different company's smartphones.
What percentage of girls are using the smartphones of Nokia?
Option 1: 33.58%
Option 2: 32.58%
Option 3: 30.58%
Option 4: 31.58%
Correct Answer: 31.58%
Solution : As per the given graph, The number of girls using smartphones $=180+60+120+20=380$ The number of girls using the smartphones of Nokia $=120$ The required percentage $=\frac{120}{380}×100=31.58$% Hence, the correct answer is 31.58%.
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