Staff Selection Commission Sub Inspector Exam
Question : Who abolished the Jizya Tax?
Option 1: Jahangir
Option 2: Humayun
Option 3: Akbar
Option 4: Aurangzeb
Correct Answer: Akbar
Solution : The correct answer is Akbar.
It was Akbar who abolished the Jizya Tax in 1564. The third Mughal emperor ruled from 1556 to 1605 AD. He founded Din-e-Illahi, a brand-new religion. Jizya was a tax that the Muslim kings imposed on Hindu citizens in
Question : Which of the following statements is not correct regarding hydrocarbons?
Option 1: Saturated hydrocarbons are unreactive and are inert in the presence of most reagents.
Option 2: Most carbon compounds also release the amount of heat and light on burning.
Option 3: Carbon compounds cannot get oxidised on combustion.
Option 4: Unsaturated hydrocarbons add hydrogen in the presence of catalysts such as palladium or nickel to give saturated hydrocarbons.
Correct Answer: Carbon compounds cannot get oxidised on combustion.
Solution : The correct answer is Carbon compounds cannot get oxidised on combustion.
Combustion causes the easy oxidation of carbon and its compounds. For instance, alcohol oxidises to form carboxylic acid. When oxygen is present, carbon compounds oxidise during a
Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement."
Before I could stop him, the boy (was throwing) the box down the stairs.
(1) were throwing
(2) threw
(3) did throw
(4) No Improvement
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : The correct answer is the second option.
"Were throwing" is in the past continuous tense, indicating an ongoing action, which does not fit the context of a completed action. "Did throw" is grammatically correct, but this option is less concise and, thus, incorrect to use.
Question : Directions: In the following question, select the one different from the other three alternatives.
Option 1: (97 – 16)
Option 2: (78 – 15)
Option 3: (58 – 13)
Option 4: (69 – 14)
Correct Answer: (69 – 14)
Solution : Let's check the options – First option: (97 – 16); 9 + 7 = 16 Second option: (78 – 15); 7 + 8 = 15 Third option: (58 – 13); 5 + 8 = 13 Fourth option: (69 – 14); 6 + 9
Question : If $x + y = 10$, $2xy = 48$ and $x > y$, then find $2x - y$.
Option 1: 6
Option 2: 8
Option 3: 4
Option 4: 3
Correct Answer: 8
Solution : Given that $x + y = 10$ and $2xy = 48$, $⇒y = 10 - x$ Substituting this into the second equation, $⇒2x(10 - x) = 48$ $⇒x^2-10x+24=0$ $⇒(x-4)(x-6)=0$ $x = 6$ and $x = 4$ But given that $x > y$, we take $x
Question : Directions: If A denotes addition, B denotes multiplication, C denotes subtraction, and D denotes division, then what will be the value of the following expression? 74 A (31 B 2) B 2 C (68 C 4) D (4 B 2) = ?
Option 1: 188
Option 2: 190
Option 3: 98
Option 4: 160
Correct Answer: 190
Solution : Given: 74 A (31 B 2) B 2 C (68 C 4) D (4 B 2) = ?
On replacing the alphabet with mathematical signs, we get – = 74 + (31 × 2) × 2 – (68 – 4) ÷ (4 × 2) =
Question : Deepali made a model of a cylindrical kaleidoscope for her science project. She uses a chart paper to make it. if the length of the kaleidoscope is 25 cm and the radius is 3.5 cm, the area of the paper she used, in the project is: $\left ( \pi=\frac{22}{7} \right )$
Option 1: 1100 cm2
Option 2: 550 cm2
Option 3: 500 cm2
Option 4: 450 cm2
Correct Answer: 550 cm2
Solution : The area of the paper used to make the cylindrical kaleidoscope $= 2\pi r h$, where \(r\) is the radius of the cylinder and \(h\) is the height of the cylinder. Given: r = 3.5 cm and h = 25 cm Area required
Question : Select the most appropriate ANTONYM of the given word. Abhor
Option 1: Occupy
Option 2: Despise
Option 3: Danger
Option 4: Love
Correct Answer: Love
Solution : The correct answer to this question is the fourth option.
Explanation: "Abhor" and "love" are opposites in terms of emotions and attitudes. When you abhor something, you have a strong dislike or hatred for it. On the other hand, when you love something, you have
Question : Directions: Find the odd word pair from the given responses.
Option 1: Play – Actor
Option 2: Building – Architect
Option 3: Craft – Artisan
Option 4: Cloth – Skirt
Correct Answer: Cloth – Skirt
Solution : Let's check the options – First option: Play – Actor; An actor performs in the play. Second option: Building – Architect; An architect builds a building. Third option: Craft – Artisan; An artisan crafts material objects by hand. Fourth option: Cloth – Skirt;
Question : If $ p(x+y)^{2}=5$ and $q(x-y)^{2}=3$, then the simplified value of $p^{2}(x+y)^{2}+4pq xy -q^{2}(x-y)^{2}$ is:
Option 1: $-(p+q)$
Option 2: $2(p+q)$
Option 3: $p+q$
Option 4: $-2(p+q)$
Correct Answer: $2(p+q)$
Solution : $p(x+y)^{2}=5$ and $q(x-y)^{2}=3$ $(x+y)^2 = \frac{5}{p}$ and $(x-y)^2 = \frac{3}{q}$ Since $(x+y)^2- (x-y)^2 = 4xy $ So, $ 4xy = \frac{5}{p} - \frac{3}{q}$ By putting it in the given expression, we have, $p^{2}(x+y)^{2}+4pq xy -q^{2}(x-y)^{2}$ = $p^2 \frac{5}{p} + 4pqxy - q^2 \frac{3}{q}$ = $5p
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