Staff Selection Commission Sub Inspector Exam
Question : Who among the following is the founder of the social activist organization called ‘Global March Against Child Labour’?
Option 1: Anna Hazare
Option 2: Kiran Bedi
Option 3: Kailash Satyarthi
Option 4: Baba Amte
Correct Answer: Kailash Satyarthi
Solution : The correct answer is Kailash Satyarthi
Kailash Satyarthi founded the Global March Against Child Labour in 1998. Rather than being an annual march, it was a grassroots movement that inspired numerous people and organisations to unite in the battle against child labour. The march
Question : If 25% of 400 + 35% of 1260 + 27% of 1800 = 1020 + $x$, then the value of $x$ lies between:
Option 1: 6 to 10
Option 2: 0 to 5
Option 3: 11 to 15
Option 4: 16 to 20
Correct Answer: 6 to 10
Solution : According to the question, 25% of 400 + 35% of 1260 + 27% of 1800 = 1020 + $x$ ⇒ $\frac{25}{100}$ × 400 + $\frac{35}{100}$ × 1260 + $\frac{27}{100}$ × 1800 = 1020 + $x$ ⇒ 100 + 441 + 486 = 1020
Question : In which year was "Ramlila" inscribed on the UNESCO Representative List of the Intangible Cultural Heritage of Humanity?
Option 1: 2008
Option 2: 2006
Option 3: 2010
Option 4: 2012
Correct Answer: 2008
Solution : The correct option is 2008.
In 2008, the traditional performance art form known as "Ramlila" was added to the Intangible Cultural Heritage of Humanity Representative List by UNESCO. With this UNESCO certification, Ramlila's cultural significance and worth are acknowledged as essential components of the
Question : Select the INCORRECTLY spelt word from the given sentence. Gandhiji considared untouchability to be one of India’s major social ills.
Option 1: social
Option 2: major
Option 3: considared
Option 4: untouchability
Correct Answer: considared
Solution : The correct choice is the third option.
Explanation: The correct spelling of the word is "considered."
"Considered" is the past participle of the verb "consider." It means to think about something carefully, contemplate, or take into account. When something is considered, it has been carefully
Question : Nowruz is celebrated by which of the following communities in India?
Option 1: Buddhist
Option 2: Jain
Option 3: Sikh
Option 4: Parsi
Correct Answer: Parsi
Solution : The correct option is Parsi.
The Parsi community in India celebrates Nowruz. The Parsis are followers of Zoroastrianism, one of the world's oldest monotheistic religions. Nowruz holds significant cultural and religious importance for Zoroastrians, and it marks the beginning of the Zoroastrian calendar year.
Question : If a shopkeeper allows a discount of 10% to his customers and still gains 30%, then the marked price of an article which costs INR 450 is:
Option 1: INR 700
Option 2: INR 650
Option 3: INR 500
Option 4: INR 750
Correct Answer: INR 650
Solution : Given: Cost price = INR 450 Selling price = $\frac{100+\text{profit %}}{100}\times$ cost price = $\frac{100+30}{100}\times450$ = $\frac{130}{100}\times450$ = 585 Selling price = $\frac{100-\text{discount %}}{100}\times$ mark price ⇒ $585 = \frac{100-10}{100}\times$ mark price ⇒ Mark price = $\frac{585\times100}{90}$ = 650 Hence, the correct answer is
Question : If $\theta$ is an acute angle and $\sin \theta+\operatorname{cosec} \theta=2$, then the value of $\sin ^5 \theta+\operatorname{cosec}^5 \theta$ is:
Option 1: 10
Option 2: 2
Option 3: 4
Option 4: 5
Correct Answer: 2
Solution : Given, $\sin \theta+\operatorname{cosec} \theta=2$ This is possible only when both $\sin \theta=\operatorname{cosec} \theta=1$ So, $\sin ^5 \theta+\operatorname{cosec}^5 \theta=1^5+1^5$ ⇒ $\sin \theta+\operatorname{cosec} \theta=1+1$ ⇒ $\sin \theta+\operatorname{cosec} \theta=2$ Hence, the correct answer is 2.
Question : The two banks of a canal are straight and parallel. A, B, and C are three persons, of whom A stands on one bank and B and C on the opposite banks. B finds the angle ABC is 30°, while C finds that the angle ACB is 60°. If B and C are 100 metres apart, the breadth of the canal is:
Option 1: $\frac{25}{\sqrt{3}}$ metres
Option 2: $20\sqrt{3}$ metres
Option 3: $25\sqrt{3}$ metres
Option 4: $\frac{20}{\sqrt{3}}$ metres
Correct Answer: $25\sqrt{3}$ metres
Solution : BD = $x$ metre (let) ∴ CD = $(100 - x)$ metres AD ⊥ BC; AD = $y$ metres From ∆ ABD, tan 30° = $\frac{AD}{BD}$ $⇒\frac{1}{\sqrt{3}}=\frac{y}{x}$ $\therefore x=\sqrt{3}y$ ----(1) From ∆ACD, $\tan 60° = \frac{AD}{CD}$ $⇒\sqrt{3}=\frac{y}{(100 - x)}$ $\therefore y=(100 - x)\sqrt{3}$ Using
Question : Directions: In the given question, if a mirror is placed on the line AB, then which of the answer figures is the right image of the given figure?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear closer to the mirror in the reflection. So, according to the above property and the information provided, the mirror is placed on the left side of the figure (on line AB). So, the left side of the
Question : If $0 \leq \theta \leq 90^{\circ}$ and $\sec ^{107} \theta+\cos ^{107} \theta=2$, then, $(\sec \theta+\cos \theta)$ is equal to:
Option 1: $2$
Option 2: $1$
Option 3: $\frac{1}{2}$
Option 4: $2^{-107}$
Correct Answer: $2$
Solution : Given, $\sec^{107} θ + \cos^{107} θ = 2$ Put $θ = 0°$ ⇒ $\sec^{107} 0° + \cos^{107} 0° = 2$ ⇒ $1^{107} + 1^{107} = 2$ ⇒ 1 + 1 = 2 ⇒ 2 = 2 (satisfied) Now, $\sec θ + \cos θ$ = $\sec
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