Staff Selection Commission Sub Inspector Exam
Question : Researchers from the UK and India have developed a hand-washing robot, which has been named:
Option 1: Gope
Option 2: Hepe
Option 3: Pepe
Option 4: Hope
Correct Answer: Pepe
Solution : The correct answer is Pepe.
Researchers from India and the United Kingdom have developed a hand-washing robot which is named Pepe & it was created to encourage children to wash their hands. It was the second such ‘social robot’ research project conducted by the University
Question : Directions: Select the odd letter pair from the given alternatives.
Option 1: MT
Option 2: CJ
Option 3: SZ
Option 4: FN
Correct Answer: FN
Solution : Let's check the options – First option: MT; M + 7 = T Second option: CJ; C + 7 = J Third option: SZ; S + 7 = Z Fourth option: FN; F + 8 = N
The fourth option does not fit the pattern.
Question : Directions: Select the figure that will come next in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the given figures – Each figure given in the box is rotated by 90° in a clockwise direction. So, following the above pattern, the required figure will be as follows –
Therefore, the figure in the second option is the required figure. Hence, the
Question : Select the most appropriate ANTONYM of the underlined word.
The entire environment was very hostile towards us.
Option 1: Antagonistic
Option 2: Favourable
Option 3: Accurate
Option 4: Handy
Correct Answer: Favourable
Solution : The second option is correct.
Hostile is an adjective that is used to describe a situation of aggression, opposition, or unfriendliness.
Favourable is used to describe a situation that is advantageous, positive, and supportive. Both the words display contrasting meanings, as one describes a negative
Question : The value of $\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times(0.107)(0.76)(0.777)}$ is:
Option 1: 60
Option 2: –6
Option 3: –3
Option 4: 30
Correct Answer: –6
Solution : As we know, If $a + b + c = 0$ Then, $a^3 + b^3 + c^3 = 3abc$ Now, 0.321 + 0.456 – 0.777 = 0 Then, $0.321^3 + 0.456^3 - 0.777^3 = -3 \times 0.321 \times 0.456 \times 0.777$ So, $\frac{(0.321)^3+(0.456)^3-(0.777)^3}{0.9 \times(0.107)(0.76)(0.777)}$ =
Question : Directions: In the following question, select the related number from the given alternatives. 7 : 343 :: 9 : ?
Option 1: 529
Option 2: 629
Option 3: 729
Option 4: 1008
Correct Answer: 729
Solution : Given: 7 : 343 :: 9 : ?
73 = 343 (343 is the cube of 7) Similarly, 93 = 729 (729 is the cube of 9)
Hence, the third option is correct.
Question : An article is sold for Rs. 5330 after a discount of 18%. What is the marked price (in Rs.) of the article?
Option 1: 6250
Option 2: 6450
Option 3: 6800
Option 4: 6500
Correct Answer: 6500
Solution : Given: An article is sold for Rs. 5330 after a discount of 18%. Let the marked price be $x$. ⇒ Selling price after 18% discount = $x – 0.18x = 0.82x$ ⇒ $0.82x = 5330$ ∴ Marked price = $ x = \frac{5330}{0.82}$ = Rs.
Question : As of October 2019, how many nuclear power plants are present in India?
Option 1: 9
Option 2: 5
Option 3: 11
Option 4: 7
Correct Answer: 7
Solution : The correct option is 7.
Over 22 nuclear reactors, spread across seven power stations in India, are in operation and provide 6780 MW of nuclear power annually. Moreover, the Kakrapar Atomic Power Project (KAPP-3) effectively included a third reactor in the power system in
Question : In the given figure, O is the centre of the circle, $\angle DAB=110^{\circ}$ and $\angle BEC=100^{\circ}$. What is the value (in degrees) of $\angle OCB$?
Option 1: 5
Option 2: 10
Option 3: 15
Option 4: 20
Correct Answer: 10
Solution : Given, $\angle DAB=110^{\circ}$ and $\angle BEC=100^{\circ}$ Since the angle subtended by the chord at the centre is double the angle subtended by the chord at the circumference, reflex$\angle BOC = 2\angle BEC = 200^\circ$ So, $\angle BOC = 360^\circ-200^\circ = 160^\circ$ By angle sum property
Question : $\left(4 x^3 y-6 x^2 y^2+4 x y^3-y^4\right)$ can be expressed as:
Option 1: $(x+y)^4-x^4$
Option 2: $(x+y)^4-y^4$
Option 3: $(x-y)^4-x^4$
Option 4: $x^4-(x-y)^4$
Correct Answer: $x^4-(x-y)^4$
Solution : $\left(4 x^3 y-6 x^2 y^2+4 x y^3-y^4\right)$ $=2xy^3 + 2xy^3 - 2x^2y^2 - 4x^2y^2 + 4x^3y- y^4 $ $=2xy^3 - 2x^2y^2 - y^4 + 4x^3y + 2xy^3 - 4x^2y^2$ $=-y^2(-2xy + 2x^2 + y^2) + 2xy (2x^2 + y^2 - 2xy)$ $=(2xy - y^2) (2x^2
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