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Staff Selection Commission Sub Inspector Exam

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Question : 84 Maths books, 90 Physics books, and 120 Chemistry books have to be stacked topicwise. How many books will be there in each stack so that each stack will have the same height too?

Option 1: 12

Option 2: 18

Option 3: 6

Option 4: 21

Team Careers360 24th Jan, 2024

Correct Answer: 6


Solution : Required number of books in each stack = HCF of the given numbers of the three types of books. 
Now, 84 = 2 × 2 × 3 × 7,
90 = 2 × 3 × 3 × 5
and 120 = 2 ×2 × 2

11 Views

Question : Directions: Select the option figure that is embedded in the given figure as its part (rotation is NOT allowed).

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 23rd Jan, 2024

Correct Answer:


Solution : Since there is a restriction on the rotation of the figure, we will check which of the option figures can exactly fit in the given question figure.
By comparison of all the option figures, only the fourth option figure is embedded in the given question figure.

20 Views

Question : The sides of a triangular park are 60 m, 112 m and 164 m. The cost of levelling the park at the rate of INR 8.50/m2 is:

Option 1: INR 18,164

Option 2: INR 17,085

Option 3: INR 17,136

Option 4: INR 18,316

Team Careers360 23rd Jan, 2024

Correct Answer: INR 17,136


Solution : Given:
a = 60 m
b = 112 m
c = 164 m
Rate = INR 8.50/m2
Now,
Semi perimeter, $(S) = \frac{60\ +\ 112\ +\ 164 }{2} =\ 168$
Area of the triangle 
$A\ = \sqrt{168(168\ -\ 60)(168\ -\ 112)(168\ -\ 164)}

15 Views

Question : At what percentage rate, compound interest compounded annually for a sum of Rs. 40,000, will amount to Rs. 44,100 in two years?

Option 1: 5%

Option 2: 2%

Option 3: 4%

Option 4: 7.5%

Team Careers360 23rd Jan, 2024

Correct Answer: 5%


Solution : When compounded annually, $ A= P(1+\frac{R}{100})^{T}$,
Where $A$ is the total amount, $P$ is the principal amount, $R$ is the rate of interest per annum, and $T$ is the time in years.
According to the question,
$⇒44100=40000(1+\frac{R}{100})^{2}$
$⇒(1+\frac{R}{100})^{2}=\frac{44100}{40000}$
$⇒(1+\frac{R}{100})^{2}=\frac{441}{400}$
$⇒\frac{R}{100}=\frac{21}{20}-1$
$⇒\frac{R}{100}=\frac{1}{20}$
$\therefore R=5\%$
Hence, the

18 Views

Question : If $x^2-2\sqrt{10}x+1=0$, what is the value of $(x-\frac{1}{x})$?

Option 1: $4$

Option 2: $6$

Option 3: $3$

Option 4: $5$

Team Careers360 25th Jan, 2024

Correct Answer: $6$


Solution : Given: $x^2-2\sqrt{10}x+1=0$
Dividing both sides by $x$, we get,
$⇒x-2\sqrt{10}+\frac{1}{x}=0$
$⇒x+\frac{1}{x}=2\sqrt{10}$
Squaring both sides, we get,
$⇒x^2+\frac{1}{x^2}+2×x×\frac{1}{x}=(2\sqrt{10})^2$
$⇒x^2+\frac{1}{x^2}=38$
Subtracting 2 from both sides, we get,
$⇒x^2+\frac{1}{x^2}-2=38-2$
$⇒x^2+\frac{1}{x^2}-2×x×\frac{1}{x}=36$
$⇒(x-\frac{1}{x})^2=36$
$\therefore x-\frac{1}{x}=\sqrt{36}=6$
Hence, the correct answer is $6$.

15 Views

Question : Directions: If W = 46, BAT = 46, then LAMB will be equal to.

Option 1: 54

Option 2: 56

Option 3: 52

Option 4: 28

Team Careers360 24th Jan, 2024

Correct Answer: 56


Solution : Given:
W = 46, BAT = 46

Multiply the sum of the positional value of the letters by 2 of BAT, to obtain the required code –
B→2; A→1; T→20
(2 + 1 + 20) × 2 = 23 × 2 = 46
And in,

4 Views

Question : Directions: Identify the diagram that best represents the relationship among the classes given.
Whales, Fishes, Crocodiles

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 25th Jan, 2024

Correct Answer:


Solution : Whales, fishes, and crocodiles are all different types of animals found in water bodies. They all are inherently different based on their size, eating habits, and the type of water body in which they live, so all three circles will be separate from each other.

The

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