Staff Selection Commission Combined Higher Secondary Level Exam
Question : Let ABC be a triangle right-angled at B. If $\tan A = \frac{12}{5}$, then find the values of $\operatorname{cosec A}$ and $\sec A$, respectively.
Option 1: $\frac{13}{10}, \frac{5}{13}$
Option 2: $\frac{13}{12},\frac{13}{5}$
Option 3: $\frac{10}{13}, \frac{5}{13}$
Option 4: $\frac{12}{13}, \frac{5}{13}$
Correct Answer: $\frac{13}{12},\frac{13}{5}$
Solution : Given, $\tan A=\frac{12}{5}$ $\tan A = \frac{\text{perpendicular}}{\text{base}}$ Using pythagoras theorem, $\small\text{Hypotenuse}^2=\text{Base}^2+\text{Perpendicular}^2$ ⇒ $h^2=5^2+12^2$ ⇒ $h^2=25+144$ ⇒ $h^2=169$ ⇒ $h=13$ $\therefore$ $\operatorname{cosec A}=\frac{\text{Hypotenuse}}{\text{Perpendicular}}=\frac{13}{12}$ And, $\sec A=\frac{\text{Hypotenuse}}{\text{Base}}=\frac{13}{5}$ Hence, the correct answer is $\frac{13}{12},\frac{13}{5}$.
Question : If $\theta$ is a positive acute angles and $\operatorname{cosec}\theta =\sqrt{3}$, then the value of $\cot \theta -\operatorname{cosec}\theta$ is:
Option 1: $\sqrt2-\sqrt3$
Option 2: $\frac{\sqrt{2}(3+\sqrt{3})}{3}$
Option 3: $\frac{\sqrt{2}(3-\sqrt{3})}{3}$
Option 4: $\frac{3\sqrt{2}+\sqrt{3}}{3}$
Correct Answer: $\sqrt2-\sqrt3$
Solution : Given: $\operatorname{cosec}\theta=\sqrt3$ $⇒\frac{1}{\sin\theta}=\sqrt3$ $⇒\sin\theta=\frac{1}{\sqrt3}$ We know that, $\cos\theta = \sqrt{1-\sin^2\theta}=\sqrt{1-(\frac{1}{\sqrt3})^2}=\sqrt{1-\frac{1}{3}}=\sqrt\frac{2}{3}$ So, $\cot\theta-\operatorname{cosec}\theta$ $=\frac{\cos\theta}{\sin\theta}-\operatorname{cosec}\theta$ $=\frac{\sqrt\frac{2}{3}}{\frac{1}{\sqrt3}}-\sqrt3$ $=\sqrt\frac{2}{3}×\sqrt3-\sqrt3$ $=\sqrt2-\sqrt3$ Hence, the correct answer is $\sqrt2-\sqrt3$.
Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series. HPA, FMZ, DJY, BGX, ?
Option 1: ZDW
Option 2: ZEV
Option 3: YDW
Option 4: YEV
Correct Answer: ZDW
Solution : Given: HPA, FMZ, DJY, BGX, ?
Here, subtract 2, 3, and 1 in the first, second, and third letters respectively to obtain the letters of the next term. HPA→H – 2 = F; P – 3 = M; A – 1 = Z→FMZ FMZ→F – 2 = D; M – 3 = J; Z – 1 = Y→DJY DJY→D – 2 = B; J – 3 = G; Y – 1 = X→BGX BGX→B – 2 = Z; G – 3 = D; X – 1 = W→ZDW
ZDW is the missing term of the series. Hence, the first option is correct.
Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: VNHK
Option 2: MONR
Option 3: NQMJ
Option 4: NBJM
Correct Answer: MONR
Solution : Let's check the options – First option: VNHK; None of the letters V, N, H, and K are vowels. Second option: MONR; The letter O is a vowel. Third option: NQMJ; None of the letters N, Q, M, and J are vowels. Fourth option: NBJM; None of the letters N, B, J, and M are vowels.
So, the second option is different from the other three options as here vowel is present. Hence, the second option is correct.
Question : Select the most appropriate option that can substitute the underlined segment in the given sentence. The politician used a/an mild and indirect word to describe the controversial policy, in order to soften the blow.
Option 1: oxymoron
Option 2: metaphor
Option 3: euphemism
Option 4: hyperbole
Correct Answer: euphemism
Solution : The correct choice is the third option.
The most appropriate option to substitute the underlined segment in the sentence is euphemism. Euphemism refers to the use of a word or phrase in place of one that might be considered too harsh, blunt, or unpleasant.
The meanings of the other options are as follows:
Therefore, the correct answer is euphemism.
Question : Find the part of the given sentence that has an error in it. If there is no error, choose ‘No error’. The inflow of foreign portfolio funds into Indian equities have pushed up price-earning multiples and valuation.
Option 1: up price-earning multiples and valuation.
Option 2: The inflow of foreign portfolio funds
Option 3: No error
Option 4: into Indian equities have pushed
Correct Answer: into Indian equities have pushed
Solution : The correct answer is the fourth option.
According to the subject-verb agreement rule, the verb must agree with the subject in number. If the subject is singular, the verb should be singular, and if the subject is plural, the verb should be plural. In the given sentence, the subject of the verb is inflow, which is singular. So, has should be used instead of have to make it grammatically correct.
Therefore, the correct sentence is, "The inflow of foreign portfolio funds into Indian equities has pushed up price-earning multiples and valuation."
Question : Chromosomes consists of
Option 1: DNA and lipids
Option 2: RNA and amino acids
Option 3: DNA and proteins
Option 4: RNA and sugar
Correct Answer: DNA and proteins
Solution : The correct answer is DNA and proteins.
Chromosomes are made up of DNA and protein. DNA is the genetic material that holds the instructions for the construction and maintenance of an organism. Proteins are molecules that perform several critical roles in the body, including as tissue construction and repair, nutrition delivery, and catalysing chemical processes.
Question : Directions: If 19 June 2001 is Tuesday, then what will be the day of the week on 14 August 2007?
Option 1: Sunday
Option 2: Monday
Option 3: Tuesday
Option 4: Friday
Correct Answer: Tuesday
Solution : Given: 19 June 2001 is a Tuesday.
Let's calculate the total number of days from the 19th of June 2001 to the 14th of August 2007 –
Number of days from 19 June 2001 to 31 December 2001 = 11 + 31 + 31 + 30 + 31 + 30 + 31 = 195 Number of days from 1 January 2002 to 31 December 2006 = (5 × 365) + 1 = 1826 (1 leap year) Number of days from 1 January 2007 to 14 August 2007 = 31 + 28 + 31 + 30 + 31 + 30 + 31 +14 = 226 So, the total number of days from 19 June 2001 to 14 August 2007 = 195 + 1826 + 226 = 2247 Now, on dividing 2247 by 7, we get 321 as the quotient and 0 as the remainder.
Therefore, add 0 to Tuesday, Tuesday + 0 = Tuesday
So, the 14th of August 2007 will be Tuesday. Hence, the third option is correct.
Question : Directions: Select the option figure in which the given figure is embedded. (rotation is NOT allowed)
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Since the rotation is restricted. So, the embedded figure will have the same orientation as the main figure. By comparison of all the option figures, the given question figure is embedded only in the second option figure.
Hence, the second option is correct.
Question : The simple interest (in INR, rounded off to the tens place) on INR 12,300 from 22 May 1993 to 2 August 1993 (both days are included) at the rate of 12% per annum is:
Option 1: 300
Option 2: 200
Option 3: 250
Option 4: 350
Correct Answer: 300
Solution : Here, P = INR 12,300 R = 12% T = from 22 May 1993 to 2 August 1993 (both days are included) May = (31 – 22 + 1) days = 10 days June = 30 days July = 31 days August = 2 days Total time = 10 + 30 + 31 + 2 = 73 days In years, total time = $\frac{73}{365}$ year Simple interest = $\frac{\text{Principal × Rate × Time}}{100}$ ⇒ Simple interest = $\frac{12300\times 12\times 73}{100\times 365}$ ⇒ Simple interest = $\frac{29520}{100}\approx$ INR 300 Hence, the correct answer is 300.
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