Staff Selection Commission Combined Higher Secondary Level Exam
Question : A vendor loses the selling price of 4 oranges on selling 36 oranges. His loss percent is:
Option 1: $12\frac{1}{2}\%$
Option 2:
$9\%$
Option 3:
$10\%$
Option 4:
$11\frac{1}{2}\%$
Correct Answer:
Solution : Let the selling price of one orange = Re. 1 The selling price of 36 oranges = Rs. 36 Loss on 36 oranges = Rs. 4 The cost price of 36 oranges = 36 + 4 = Rs. 40 Loss percentage = $\frac{\text{Loss}}{\text {Cost Price}}$
Question : Directions: In the following question, four number pairs are given. In each pair, the number on the left side of (-) is related to the number on the right side of (-) with some Logic/Rule /Relation. Three pairs are similar based on the same Logic/Rule/Relation. Select the odd one out from the given alternatives. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g.13 – operations on 13 such as adding/subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.)
Option 1: 64 – 4032
Option 2: 38 – 1444
Option 3: 42 – 1764
Option 4: 52 – 2704
Correct Answer: 64 – 4032
Solution : Let's check each option – First option: (64 – 4032); 642 = 4096 ≠ 4032 Second option: (38 – 1444); 382 = 1444 Third option: (42 – 1764); 422 = 1764 Fourth option: (52 – 2704); 522 = 2704
Question : Directions: Select the number from among the given options that can replace the question mark (?) in the following series. 183, 173, 153, 123, 83, ?
Option 1: 43
Option 2: 33
Option 3: 23
Option 4: 53
Correct Answer: 33
Solution : Given: 183, 173, 153, 123, 83, ?
Subtract multiples of 10 to the previous number to obtain the next number. 183 – 10 = 173, 173 – 20 = 153, 153 – 30 = 123, 123 – 40 = 83, 83 – 50 = 33
Question : Let ABC be a triangle right-angled at B. If $\tan A = \frac{12}{5}$, then find the values of $\operatorname{cosec A}$ and $\sec A$, respectively.
Option 1: $\frac{13}{10}, \frac{5}{13}$
Option 2: $\frac{13}{12},\frac{13}{5}$
Option 3: $\frac{10}{13}, \frac{5}{13}$
Option 4: $\frac{12}{13}, \frac{5}{13}$
Correct Answer: $\frac{13}{12},\frac{13}{5}$
Solution : Given, $\tan A=\frac{12}{5}$ $\tan A = \frac{\text{perpendicular}}{\text{base}}$ Using pythagoras theorem, $\small\text{Hypotenuse}^2=\text{Base}^2+\text{Perpendicular}^2$ ⇒ $h^2=5^2+12^2$ ⇒ $h^2=25+144$ ⇒ $h^2=169$ ⇒ $h=13$ $\therefore$ $\operatorname{cosec A}=\frac{\text{Hypotenuse}}{\text{Perpendicular}}=\frac{13}{12}$ And, $\sec A=\frac{\text{Hypotenuse}}{\text{Base}}=\frac{13}{5}$ Hence, the correct answer is $\frac{13}{12},\frac{13}{5}$.
Question : If $\theta$ is a positive acute angles and $\operatorname{cosec}\theta =\sqrt{3}$, then the value of $\cot \theta -\operatorname{cosec}\theta$ is:
Option 1: $\sqrt2-\sqrt3$
Option 2: $\frac{\sqrt{2}(3+\sqrt{3})}{3}$
Option 3: $\frac{\sqrt{2}(3-\sqrt{3})}{3}$
Option 4: $\frac{3\sqrt{2}+\sqrt{3}}{3}$
Correct Answer: $\sqrt2-\sqrt3$
Solution : Given: $\operatorname{cosec}\theta=\sqrt3$ $⇒\frac{1}{\sin\theta}=\sqrt3$ $⇒\sin\theta=\frac{1}{\sqrt3}$ We know that, $\cos\theta = \sqrt{1-\sin^2\theta}=\sqrt{1-(\frac{1}{\sqrt3})^2}=\sqrt{1-\frac{1}{3}}=\sqrt\frac{2}{3}$ So, $\cot\theta-\operatorname{cosec}\theta$ $=\frac{\cos\theta}{\sin\theta}-\operatorname{cosec}\theta$ $=\frac{\sqrt\frac{2}{3}}{\frac{1}{\sqrt3}}-\sqrt3$ $=\sqrt\frac{2}{3}×\sqrt3-\sqrt3$ $=\sqrt2-\sqrt3$ Hence, the correct answer is $\sqrt2-\sqrt3$.
Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series. HPA, FMZ, DJY, BGX, ?
Option 1: ZDW
Option 2: ZEV
Option 3: YDW
Option 4: YEV
Correct Answer: ZDW
Solution : Given: HPA, FMZ, DJY, BGX, ?
Here, subtract 2, 3, and 1 in the first, second, and third letters respectively to obtain the letters of the next term. HPA→H – 2 = F; P – 3 = M; A – 1 = Z→FMZ FMZ→F –
Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: VNHK
Option 2: MONR
Option 3: NQMJ
Option 4: NBJM
Correct Answer: MONR
Solution : Let's check the options – First option: VNHK; None of the letters V, N, H, and K are vowels. Second option: MONR; The letter O is a vowel. Third option: NQMJ; None of the letters N, Q, M, and J are vowels. Fourth option: NBJM;
Question : Select the most appropriate option that can substitute the underlined segment in the given sentence. The politician used a/an mild and indirect word to describe the controversial policy, in order to soften the blow.
Option 1: oxymoron
Option 2: metaphor
Option 3: euphemism
Option 4: hyperbole
Correct Answer: euphemism
Solution : The correct choice is the third option.
The most appropriate option to substitute the underlined segment in the sentence is euphemism. Euphemism refers to the use of a word or phrase in place of one that might be considered too harsh, blunt, or unpleasant.
The
Question : Find the part of the given sentence that has an error in it. If there is no error, choose ‘No error’. The inflow of foreign portfolio funds into Indian equities have pushed up price-earning multiples and valuation.
Option 1: up price-earning multiples and valuation.
Option 2: The inflow of foreign portfolio funds
Option 3: No error
Option 4: into Indian equities have pushed
Correct Answer: into Indian equities have pushed
Solution : The correct answer is the fourth option.
According to the subject-verb agreement rule, the verb must agree with the subject in number. If the subject is singular, the verb should be singular, and if the subject is plural, the verb should
Question : Chromosomes consists of
Option 1: DNA and lipids
Option 2: RNA and amino acids
Option 3: DNA and proteins
Option 4: RNA and sugar
Correct Answer: DNA and proteins
Solution : The correct answer is DNA and proteins.
Chromosomes are made up of DNA and protein. DNA is the genetic material that holds the instructions for the construction and maintenance of an organism. Proteins are molecules that perform several critical roles in the body,
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