Correct Answer: Jawaharlal Nehru.

Solution : The correct option is Jawaharlal Nehru.

The Congress of Oppressed Nationalities in Brussels in 1927 aimed to bring together representatives from various colonized and oppressed nations to discuss their common struggles against imperialism. One of the notable attendees at this congress was Jawaharlal Nehru,

Correct Answer: 10°N to 30°N latitude

Solution : The correct option is 10°N to 30°N latitude.

The Ganga-Brahmaputra basin lies between 10°N and 30°N latitudes. This region is one of the largest river basins and includes portions of Bangladesh, Nepal, Bhutan, and India.

Correct Answer: Aquatic

Solution : Given:
1. Aquarium 2. Aquatic 3. Aquarial 4. Aquatint 5. Aquavit

Step 1: The first four letters of each word are the same – a, q, u, a; so move on to the next letter.
Step 2: The fifth letter of

Correct Answer: TVWY

Solution : Given:

KMNP : ACDF :: PRSU : ?

Here, the logic is that the second alphabet of each letter adds 2 letters ahead of the first letter, the third letter adds 1 ahead of the second letter and the fourth letter adds 2 ahead of

Correct Answer:

Sect contemporary to the Buddha   

Solution : Correct Answer is Sect contemporary to the Buddha  

The Ajivikas is a prehistoric Indian ascetic religion that believed in freedom, fatalism, and karma. This sect was particularly influential during the reign of the Mauryan king Bindusara. King Bindusara and his wife

Correct Answer: $\pm \frac{1}{2}(\sqrt{3}+1)$

Solution : Given: $\frac{2+\sqrt{3}}{2}$
$= \frac{1}{4}({4+2\sqrt{3}})$
$= \frac{1}{4}[1^2+(\sqrt{3})^2+2×1×\sqrt{3}]$
$= \frac{1}{4}(1+\sqrt{3})^2$
So, the square root of $\frac{2+\sqrt{3}}{2}$
$= \sqrt{\frac{2+\sqrt{3}}{2}}$
$= \sqrt{\frac{1}{4}(1+\sqrt{3})^2}$
$= \pm \frac{1}{2}(1+\sqrt{3})$
Hence, the correct answer is $\pm \frac{1}{2}(\sqrt{3}+1)$ .

Correct Answer: $8(\sqrt{3}-2)$

Solution : Given, $\sin \theta+\cos \theta=\frac{\sqrt{3}-1}{2 \sqrt{2}}$
Squaring both sides, we get,
⇒ $(\sin \theta+\cos \theta)^2=(\frac{\sqrt{3}-1}{2 \sqrt{2}})^2$
⇒ $\sin^2\theta+\cos^2\theta+2\sin\theta\cos\theta=\frac{3+1-2\sqrt3}{8}$
⇒ $1+2\sin\theta\cos\theta=\frac{4-2\sqrt{3}}{8}$
⇒ $2\sin\theta\cos\theta=\frac{2-\sqrt3}{4}-1$
⇒ $2\sin\theta\cos\theta=\frac{2-\sqrt3-4}{4}$
⇒ $\sin\theta\cos\theta=\frac{-2-\sqrt3}{8}$
Now consider, $\tan \theta+\cot \theta$
$=\frac{\sin\theta}{\cos\theta}+\frac{\cos\theta}{\sin\theta}$
$=\frac{\sin^2\theta+\cos^2\theta}{\sin\theta\cos\theta}$
$=\frac{1}{\sin\theta\cos\theta}$
$=\frac{1}{\frac{-2-\sqrt3}{8}}$
$=\frac{-8}{2+\sqrt3}$
Rationalizing it, we get,
$=\frac{-8}{2+\sqrt3}\times\frac{2-\sqrt3}{2-\sqrt3}$
$=\frac{-8(2-\sqrt3)}{2^2-(\sqrt3)^2}$
$=\frac{8(\sqrt{3}-2)}{4-3}=8(\sqrt3-2)$
Hence, the correct

Correct Answer: Disloyal

Solution : The correct choice is the second option.

Disloyal is the most appropriate synonym for treacherous, as both convey the idea of betrayal and untrustworthiness.

The meanings of the options are as follows:

• Devoted: Faithful and loyal.

• Transient: Temporary or lasting for only a

Correct Answer: Depth of Water

Solution : Given:
Ampere : Electric Current :: Fathom : ?

The ampere is a unit of measurement used to quantify electric current.
Similarly, a fathom is a unit used to measure the depth of water.

Hence, the first option is correct.

Correct Answer: (77, 18, 5)

Solution : Given:
(121, 81, 2); (88, 54, 2)

In the above-given set of numbers, divide the first number by 11 and the second number by 9. Then, subtract both the results.
Like, (121, 81, 2); (121 ÷ 11) – (81 ÷ 9) = 11