Railway Recruitment Boards Non Technical Popular Categories Exam
In places like Andhra Pradesh and Telangana, the BC-E category is usually used to refer to specific backward classes, especially among Muslim groups.
For reservations in employment and education, this group is often recognised at the state level.Reservation benefits are available solely to OBC categories recognised by the Central Government
OEC is a Category stands for Other Eligible Communities is not included in center list so the exam which is conducted on national level dont give reservation to this category students And this is seen in the State of Kerala. However These are the Communities that have been recommended to
Hello there,
Document verification is a very hectic and long process. There would be so many students who will be waiting for their documents to be verified. Thus, starting the classes on the same day will be not possible. Almost every colleges fix two different dates for the verification and
The RRB NTPC 2024 exam dates have not been officially announced yet. However, based on previous trends, the exams are expected to be conducted in the first quarter of 2025. For candidates from Telangana, the exam will be held at designated centers within the state. The exact date, center, and
Yes, you can apply for the job, but it depends on the specific eligibility criteria mentioned in the job notification. Most jobs after +2 in Arts allow candidates to apply, especially for clerical, administrative, or entry-level government/private positions .
Key Points:
Check Educational Requirement: Some jobs require specific streams (Science/Commerce/Arts),
Question : If $A+B=90^{\circ}$, then the expression $\frac{\cot A}{\cot B}+\cos ^2 A+\cos ^2 B$ is equal to:
Option 1: $\cot ^2 B$
Option 2: $\operatorname{cosec}^2 A$
Option 3: $\cot ^2 A$
Option 4: $\operatorname{cosec}^2 B$
Correct Answer: $\operatorname{cosec}^2 A$
Solution : $A+B=90^{\circ}$ $B=90^{\circ}-A$ $\frac{\cot A}{\cot B}+\cos ^2 A+\cos ^2 B$ = $\frac{\cot A}{\cot (90^{\circ}-A)}+\cos ^2 A+\cos ^2 (90^{\circ}-A)$ = $\frac{\cot A}{\tan A}+\cos ^2 A+\sin ^2A$ = $\cot^2 A +1$ = $\operatorname{cosec}^2 A$ Hence,the correct answer is $\operatorname{cosec}^2 A$.
Hello aspirant,
To fill positions at various levels, the Railway Recruitment Board will publish the RRB NTPC 2023 announcement on each of its official regional websites. Within a set timeframe on the official regional websites, applicants who wish to sit for the exam may complete the RRB NTPC application form
Hello Aspirant,
Your candidature is more likely to get cancelled. They will ask for an OBC certificate failing to submit it will eventually cancel your candidature for this exam. Moreover, the cut off for different categories is different and as your entered OBC as your category, you cleared the exam
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