Correct Answer: 55

Solution : Let $x-2$, $x-1$, $x$, $x+1$, $x+2$ be the five consecutive odd numbers.
The average of five consecutive odd numbers = 53
Sum = 53 × 5 = 265
⇒ $x-2$ + $x-1$ + $x$ + $x+1$ + $x+2$ = 265
⇒ $5x$ = 265
⇒

Correct Answer: 25%

Solution : As per the graph,
The production of wheat in the year 2013 = 100 thousand tonnes/ years
The production of wheat in the year 2014 = 75 thousand tonnes/ years
The percentage decrease = $\frac{100-75}{100}× 100= 25\%$
Hence, the correct answer is 25%.

Correct Answer: Pushyabhuti

Solution : The correct answer is Pushyabhuti.

He belonged to the Vardhana dynasty, also known as the Pushyabhuti. At some point in the sixth and seventh centuries, the Pushyabhuti dynasty—also referred to as the Vardhana dynasty—ruled over northern India. From north and northwest India to the

Correct Answer: 103

Solution : Consider the numbers,
102, 103, 105, and 108
⇒ For 102,
When increased by 5, the number becomes 107 which is not divisible by 2.
Now, The number = 103
When increased by 5, the number = 108
⇒ $\frac{108}{2}=54$ and $\frac{108}{3}=36$
Number = 105,

Correct Answer: TKLPEI

Solution : Given:
95784 is written as EGYPT, and 23614 is written as LIKRT.

95784→EGYPT
23614→LIKRT
As seen above in the given words T is common in both words and 4 is denoted by T at both places. It means the number itself is the code of

Correct Answer: YJISR

Solution : Given:
GRSTB is written as GYXWL, and HANDS is written as XISFM.

Add 5 to the place value of GRSTB and HANDS and then change the position of the letters as shown, to obtain the required code –

Thus, GRSTB is coded as GYXWL.

Thus,

Correct Answer: 11

Solution : The correct answer is 11.

In field hockey, a team typically consists of 11 players, including 10 field players and one goalkeeper. The field players are divided into forwards, midfielders, and defenders, each with specific roles and responsibilities during the game. The goalkeeper in

Correct Answer: 5 days

Solution : Let the number of days they worked together be $x$
According to the question
⇒ The efficiency of B = $\frac{1}{10}$
⇒ The efficiency of C = $\frac{1}{30}$
Combined efficiency = $\frac{1}{10}$ + $\frac{1}{30}$ = $\frac{4}{30}$
⇒ Work done for $x$ days = $\frac{4x}{30}$

Correct Answer: 214

Solution : Given:
158, 160, 164, 170, 178, 188, 200, ?

The pattern is as follows –
158 + 2 = 160; 160 + 4 = 164; 164 + 6 = 170; 170 + 8 = 178; 178 + 10 = 188; 188 + 12 = 200;

Correct Answer: EI – LM

Solution : Let's check the options –
First option: EI – LM; E and I both are vowels; L + 1 = M
Second option: AE – RT; A and E both are vowels; R + 2 = T
Third option: IO – WY; I