Staff Selection Commission Multi Tasking Staff Exam
Question : Directions: By Interchanging which two signs the equation will be correct? 21 – 7 × 4 ÷ 10 + 2 = 4
Option 1: – and ×
Option 2: × and ÷
Option 3: – and ÷
Option 4: + and –
Correct Answer: – and ÷
Solution : Given: 21 – 7 × 4 ÷ 10 + 2 = 4
Replace the given symbols in the options one by one with the original symbols in the given equation. First option: – and × Solving the L.H.S. of the equation – =
Question : Directions: Which of the following numbers will replace the question mark (?) in the given series? 61, 65, 73, 85, 101, ?
Option 1: 123
Option 2: 120
Option 3: 121
Option 4: 119
Correct Answer: 121
Solution : Given: 61, 65, 73, 85, 101, ?
In the above-given series add multiples of 4 to obtain the next number. 61→61 + 4 = 65 65→65 + 8 =73 73→73 + 12 = 85 85→85 + 16 = 101 101→101 + 20 = 121
So,
Question : Directions: In the following question, the sentence given with a blank is to be filled in with an appropriate word. Select the correct alternative out of the four.
They were worried about a new cult that ____ many followers.
Option 1: Is gaining
Option 2: Must be gaining
Option 3: Was gaining
Option 4: Were gaining
Correct Answer: Was gaining
Solution : The correct choice is the third option "was gaining."
This choice fits grammatically in the sentence and conveys the intended meaning that they were worried about a new cult that was actively acquiring many followers. The options ''is gaining'' and ''must be gaining'' are
Question : Select the most appropriate meaning of the given idiom. Drastic times call for drastic measures.
Option 1: When you are extremely desperate you need to take extremely desperate actions.
Option 2: Don't rely on it until you sure of it.
Option 3: Something that ends at the last minute or last few seconds.
Option 4: Do not pull all your resources in one possibility.
Correct Answer: When you are extremely desperate you need to take extremely desperate actions.
Solution : The correct choice is the first option.
This idiom suggests that in challenging or desperate situations, one may need to resort to extreme or unconventional measures to address the problem. It emphasises the idea
Question : If $\frac{J}{4}=\frac{K}{5}=\frac{L}{3}$, what is the value of $(L + J)^2:(J +K)^2:(K +L)^2$?
Option 1: 25 : 16 : 9
Option 2: 64 : 25 : 81
Option 3: 49 : 81 : 62
Option 4: 49 : 81 : 64
Correct Answer: 49 : 81 : 64
Solution : Given: $\frac{J}{4}=\frac{K}{5}=\frac{L}{3}$ Let, $\frac{J}{4}=\frac{K}{5}=\frac{L}{3}=x$ So, $J=4x,K=5x$ and $L=3x$ Now, $(L + J)^2:(J +K)^2:(K +L)^2$ = $(3x+4x)^2:(4x+5x)^2:(5x+3x)^2$ = $49x^2:81x^2:64x^2$ = 49 : 81 : 64 Hence, the correct answer is 49 : 81 : 64.
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".
She placed (1) / the offering (2) / to God in the altar. (3) / No error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The error lies in the third part of the sentence.
An altar is a table in a Christian church on which offerings like bread and wine are placed. Hence, the preposition to be used is "on" instead of "in".
Therefore, the correct sentence is:
Question : Who is the author of the epic poem 'Padmaavat'?
Option 1: Kuldip Nayar
Option 2: Kalidasa
Option 3: Malik Muhammad Jayasi
Option 4: Al-Biruni
Correct Answer: Malik Muhammad Jayasi
Solution : The correct option is Malik Muhammad Jayasi.
The epic poem "Padmaavat" was written by the Sufi poet Malik Muhammad Jayasi in the Awadhi language in 1540. It is a fictionalized account of the legendary queen Padmini and the siege of Chittorgarh by Alauddin
Question : The value of 0.1 × 99% of 1000 + 1.5 ÷ 0.3 × 1.1 is:
Option 1: 105.6
Option 2: 101.0
Option 3: 104.5
Option 4: 106.5
Correct Answer: 104.5
Solution : Given expression, 0.1 × 99% of 1000 + 1.5 ÷ 0.3 × 1.1 = 0.1 × (0.99 × 1000) + 1.5 ÷ 0.3 × 1.1 = 0.1 × 990 + 1.5 ÷ 0.3 × 1.1 = 0.1 × 990 + 5 × 1.1 = 99
Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term and the sixth term is related to the fifth term. U39R : P118M : F18A : ? :: G72K : B217F
Option 1: C55V
Option 2: A55W
Option 3: A55V
Option 4: B55U
Correct Answer: A55V
Solution : Given: U39R : P118M : F18A : ? :: G72K : B217F
Subtract 5 in the place value of the first and third letter respectively, multiply the middle number by 2 and add the resultant to the addition of the number and 1 in U39R,
Question : The average of a set of 15 consecutive even numbers is 64. What is the difference between the largest and the smallest numbers belonging to this set?
Option 1: 26
Option 2: 27
Option 3: 25
Option 4: 28
Correct Answer: 28
Solution : Use : an = a + (n - 1)d, where an = nth term of largest term of A.P a = first term, n = number of terms, d = common difference According to the question n = 15 and d =
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