Staff Selection Commission Combined Higher Secondary Level Exam
Question : A wavelength of 0.3 m is produced in air and it travels at a speed of 300m/s. Then, it will be an:
Option 1: Audible Wave
Option 2: Infrasonic Wave
Option 3: Ultrasonic Wave
Option 4: Microwave
Correct Answer: Audible Wave
Solution : The correct option is the Audible Wave.
The audible range for humans is between 20 Hz and 20,000 Hz. The speed of a wave (v) is related to its wavelength (λ) and frequency (f) by the equation: v=f⋅λ. With a wavelength of 0.3
Question : The bar graph given below shows the foreign trade by two countries A and B in 5 different years.
J1 = The total foreign trade by country A in all 5 years. J2 = The total foreign trade by country B in all 5 years. What is the value of (J2 – J1)?
Option 1: 125
Option 2: 115
Option 3: 95
Option 4: 75
Correct Answer: 115
Solution : From the bar graph, - For country A (J1): 170 + 150 + 75 + 65 + 35 = 495 - For country B (J2): 45 + 105 + 195 + 175 + 90 = 610 So, the value of (J2 – J1) = 610
Question : Which team was the Pro Kabaddi League (PKL) Season 8 winner?
Option 1: Bengal Warriors
Option 2: Bengaluru Bulls
Option 3: Dabang Delhi K.C.
Option 4: Patna Pirates
Correct Answer: Dabang Delhi K.C.
Solution : The correct option is Dabang Delhi K.C.
In Season 8 of the Pro Kabaddi League (PKL), Dabang Delhi K.C. secured their first-ever championship title. They achieved victory by narrowly defeating the Patna Pirates with a scoreline of 37-36, becoming the sixth team in
Question : In a two-digit number, the digit at unit's place is 1 less than twice the digit at the ten's place. If the digit at unit's and ten's place are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is:
Option 1: $59$
Option 2: $23$
Option 3: $35$
Option 4: $47$
Correct Answer: $47$
Solution : Let the tens digit be $x$ so the unit digit is $(2x - 1)$. Original number = $10x + 2x - 1= 12x - 1$. After the interchange, new number = $10(2x - 1) + x = 20x - 10 + x = 21x –10$.
Question : Directions: In the following question, select the related number from the given alternatives. $\frac{1}{4}: \frac{1}{8}:: \frac{2}{3} :\ ?$
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{2}$
Option 3: 1
Option 4: $\frac{1}{4}$
Correct Answer: $\frac{1}{3}$
Solution : Given: $\frac{1}{4}: \frac{1}{8}:: \frac{2}{3} :\ ?$
Multiply the first number by $\frac{1}{2}$ to obtain the second number of each pair. Like, $\frac{1}{4}: \frac{1}{8}$→$\frac{1}{4}$ × $\frac{1}{2}$ = $\frac{1}{8}$ Similarly, follow the same pattern for $\frac{2}{3} :\ ?$→$\frac{2}{3}$ × $\frac{1}{2}$ = $\frac{1}{3}$
So, $\frac{2}{3}$ is related to
Question : Directions: AKM is related to DNP in a certain way based on the English alphabetical order. In the same way, BTS is related to EWV. To which of the following is LGK related following the same logic?
Option 1: OJN
Option 2: MHC
Option 3: KGL
Option 4: ADH
Correct Answer: OJN
Solution : Given: AKM is related to DNP and BTS is related to EWV.
Add 3 to the place value of letters of AKM, to get the required code – A + 3 = D; K + 3 = N; M + 3 = P Thus, AKM
Question : An acid having basicity 1 is
Option 1: Sodium dihydrogen phosphate
Option 2: Disodium hydrogen phosphate
Option 3: Sodium phosphate
Option 4: Phosphoric acid
Correct Answer: Disodium hydrogen phosphate
Solution : The correct option is Disodium hydrogen phosphate.
The acid with the basicity one is disodium hydrogen phosphate (Na2HPO4), which has one interchangeable hydrogen ion. Because phosphoric acid (H3PO4) has three interchangeable hydrogen ions, it
Question : Bacterial cells do not have
Option 1: Cell wall
Option 2: Plasma membrane
Option 3: Ribosome
Option 4: Mitochondria
Correct Answer: Mitochondria
Solution : The correct option is Mitochondria.
Bacterial cells have a cell wall, a cell membrane and ribosomes. They do not, however, have mitochondria. Bacterial cells contain a cell wall usually formed of peptidoglycan, a unique polymer that gives structural support and protection to the cell.
Question : If $a+\frac{1}{a}=5$, then determine the value of $a^3+\frac{1}{a^3}$.
Option 1: 90
Option 2: 125
Option 3: 105
Option 4: 110
Correct Answer: 110
Solution : $a+\frac{1}{a}=5$ $⇒(a+\frac{1}{a})^3=5^3$ $⇒a^3+\frac{1}{a^3}+3×a×\frac{1}{a}(a+\frac{1}{a}) = 125$ $⇒a^3+\frac{1}{a^3} = 125 - (3×5) = 125 - 15 = 110$ Hence, the correct answer is 110.
Question : Directions: Sameer is younger than Meera. Prayas is older than Sameer but younger than Sakshi. Who is the eldest of the four?
Option 1: Meera
Option 2: Prayas
Option 3: Sameer
Option 4: Meera or Sakshi
Correct Answer: Meera or Sakshi
Solution : Given: (I) Sameer is younger than Meera. Meera > Sameer (II) Prayas is older than Sameer but younger than Sakshi. After combining all the statements the arrangement is as follows – Meera/Sakshi > Prayas > Sameer
So, either Meera or Sakshi is the
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