Staff Selection Commission Combined Higher Secondary Level Exam
Question : Directions: In a code language, the following alphabets are coded in a particular way.
Which word can be decoded from the following?
Option 1: BOAST
Option 2: TOAST
Option 3: GHOST
Option 4: TASTE
Correct Answer: BOAST
Solution : Given:
Here, all the letters are coded with the equivalent code given in the question. Therefore, Thus, the decoded word is BOAST. Hence, the first option is correct.
Question : Parts of the following sentence are given as options. Identify the part that contains a grammatical error. If there is no error, select "No Error".
Shyam, so good with weapons, fail to find the words / to tell him that everything he'd done / so far, all the compromises he'd made, had been for love.
Option 1: to tell him that everything he’d done
Option 2: Shyam, so good with weapons, fail to find the words
Option 3: so far, all the compromises he'd made, had been for love.
Option 4: No Error
Correct Answer: Shyam, so good with weapons, fail to find the words
Solution : The second option is correct.
The subject Shyam is singular, and so the verb should also be singular to match.
The verb fail is in the plural form, so it should be replaced with fails to
Question : Directions: Select the option in which the numbers share the same relationship in the set as that shared by the numbers in the given set. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g.13 – Operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) (14, 55, 41); (36, 99, 63)
Option 1: (76, 153, 67)
Option 2: (128, 949, 821)
Option 3: (28, 120, 82)
Option 4: (34, 107, 43)
Correct Answer: (128, 949, 821)
Solution : Given: (14, 55, 41); (36, 99, 63)
Here, (14, 55, 41)→14 + 41 = 55 (36, 99, 63)→36 + 63 = 99
Let's check the options – First option: (76, 153, 67)→76 + 67 = 143 ≠ 153 Second option:(128, 949, 821)→128
Question : Which of the following numbers is NOT divisible by 11?
Option 1: 1735624
Option 2: 752563
Option 3: 1661308
Option 4: 1904529
Correct Answer: 752563
Solution : If the difference between the sum of the digits at the odd places and the sum of digits at even places of the number is 0 or divisible by 11, then the number is divisible by 11. Option 1: 1735624 The sum of digits at
Question : Directions: Which number from among the given options can replace the question mark (?) in the following series? 31, 97, ?, 259, 355, 461
Option 1: 127
Option 2: 234
Option 3: 189
Option 4: 173
Correct Answer: 173
Solution : Given: 31, 97, ?, 259, 355, 461
The difference between the numbers of the given series holds the common difference of 10, as shown below –
So, 173 is the missing number of the series. Hence, the fourth option is correct.
Question : If $x+\frac{1}{x}=3$, then the value of $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{2}$
Option 4: $\frac{5}{3}$
Correct Answer: $\frac{5}{2}$
Solution : Given: $x+\frac{1}{x}=3$ To find: $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ Dividing with $x$ on both numerator and denominator, = $\frac{3x-4+\frac{3}{x}}{x-1+\frac{1}{x}}$ = $\frac{3(x+\frac{1}{x})-4}{(x+\frac{1}{x})-1}$ = $\frac{(3×3)-4}{3-1}$ = $\frac{5}{2}$ Hence, the correct answer is $\frac{5}{2}$.
Question : Which metal ion released from the tannery industry causes acute water pollution?
Option 1: Mg
Option 2: As
Option 3: Cr
Option 4: Zn
Correct Answer: Cr
Solution : The correct answer is Cr.
The metal ion that is often released from the tannery industry and can cause acute water pollution is chromium. Specifically, it is usually hexavalent chromium (Cr(VI)) that poses a significant environmental concern. Tanneries use chromium in the tanning process,
Question : A shopkeeper gives an additional concession of 5% on an item which is already discounted by 15% on the marked price. If the buyer pays INR 3,068.50 for the item, then find the marked price.
Option 1: INR 3,500
Option 2: INR 3,700
Option 3: INR 3,800
Option 4: INR 3,780
Correct Answer: INR 3,800
Solution : We know the formula for successive discounts, Selling price = $MP(1 - \frac{D_1}{100})(1 - \frac{D_2}{100})$ Where $MP$ is the marked price and $D_1, D_2$ are the discounts. $\mathrm{D_1=5}$% $\mathrm{D_2=15}$% On substituting the values, $\mathrm{MP(1 - \frac{5}{100})(1 - \frac{15}{100})}=3068.50$ $⇒\mathrm{MP×( \frac{19}{20})×(\frac{17}{20})}=3068.50$ $⇒\mathrm{MP×( \frac{323}{400})}=3068.50$ $⇒\mathrm{MP}=\frac{400}{323}× 3068.50$
Question : Directions: In a certain code language, LOAF is coded as 8362, LICK is coded as 5103, JOCK is coded as 0841, JEAN is coded as 9472. What is the code for LOC in that code language?
Option 1: 385
Option 2: 341
Option 3: 381
Option 4: 480
Correct Answer: 381
Solution : Given: I. LOAF is coded as 8362 II. LICK is coded as 5103 III. JOCK is coded as 0841 IV. JEAN is coded as 9472
By comparing all the above-coded letters, we find that – On comparing words I and II, the common letter and
Question : A computer programming language often used by children is:
Option 1: LOGO
Option 2: PILOT
Option 3: BASIC
Option 4: JAVA
Correct Answer: LOGO
Solution : The correct answer is LOGO.
LOGO is another popular computer programming language among children. It is a text-based language, but it is intended to be simple to learn and apply. LOGO is also incredibly adaptable and can be used to build tasks, including sketching graphics,
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