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Staff Selection Commission Combined Higher Secondary Level Exam

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Question : Directions: Study the given diagram carefully and answer the questions. The numbers in different sections indicate the number of students who play different games. How many students play only one game?

Option 1: 32

Option 2: 37

Option 3: 61

Option 4: 53

Team Careers360 24th Jan, 2024

Correct Answer: 53


Solution : In the diagram, the shaded parts represent the regions representing students playing only one game.


The number of students that play only one game is the region that does not overlap with any other region. So, the number of students who play only chess is

8 Views

Question : Which of the following Harappan towns was located on Khadir Bet in the Rann of Kutch and was divided into three parts?

Option 1: Sotka koh

Option 2: Chanhudaro

Option 3: Surkotada

Option 4: Dholavira

Team Careers360 24th Jan, 2024

Correct Answer: Dholavira


Solution : The correct answer is Dholavira.

The cities of the Harappan civilisation flourished on the banks of the Indus River, and these are the earliest cities in the Indian subcontinent. The city of Dholavira is located on the Khadir Bet in the Rann of Kutch

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Question : If $2x+3y = 4$ and $4x^{2}+9y^{2}= 64$, then what is the value of $8x^{3}+27y^{3}$:

Option 1: 253

Option 2: 235

Option 3: 352

Option 4: 325

Team Careers360 25th Jan, 2024

Correct Answer: 352


Solution : Given: $2x+3y=4$ and $4x^2+9x^2=64$
To find: $8x^3+27y^3$
Now,
$2x+3y=4$
Squaring both sides, we get:
⇒ $4x^2+9y^2+12xy=16$
Putting the values, we get:
⇒ $64+12xy=16$
⇒ $12xy=-48$
⇒ $xy=-4$
Now again,
$2x+3y=4$
Cubing both sides, we get:
⇒ $8x^3+27y^3+3×2x×3y(2x+3y)=64$
Putting the values, we get:
⇒ $8x^3+27y^3+18×(-4)×4=64$
$\therefore8x^3+27y^3=64+288=

15 Views

Question : The _______ of a ray is the angle measured from the reflected ray to the normal surface.

Option 1: Angle of Diffusion

Option 2: Angle of Reflection

Option 3: Angle of Incidence

Option 4: Angle of Refraction

Team Careers360 24th Jan, 2024

Correct Answer: Angle of Reflection


Solution : The correct option is the Angle of Reflection.

The angle measured from the reflected ray to the normal surface is called the "angle of reflection." The angle of reflection is the angle between the reflected ray and the normal (a line perpendicular

17 Views

Question : The value of $(x^{b+c})^{b–c}(x^{c+a})^{c–a}(x^{a+b})^{a–b}$, where $(x\neq 0)$ is:

Option 1: 1

Option 2: 2

Option 3: –1

Option 4: 0

Team Careers360 24th Jan, 2024

Correct Answer: 1


Solution : Given: $(x^{b+c})^{b–c}(x^{c+a})^{c–a}(x^{a+b})^{a–b}$ $(x\neq 0)$
= $(x^{(b+c)×(b–c)})(x^{(c+a)(c–a)})(x^{(a+b)×(a–b)})$
= $(x^{(b^{2}–c^{2})})(x^{(c^{2}–a^{2})})(x^{(a^{2}–b^{2})})$
= $x^{(b^{2}–c^{2}+c^{2}–a^{2}+a^{2}–b^{2})}$
= $x^{0}$
= 1
Hence, the correct answer is 1.

10 Views

Question : Directions: Which two mathematical operations should be interchanged to balance the following equation?
19 – 39 × 3 + 25 ÷ 5 = 131

Option 1: + and ÷

Option 2: ÷ and ×

Option 3: – and ÷

Option 4: + and ×

Team Careers360 24th Jan, 2024

Correct Answer: ÷ and ×


Solution : Given:
19 – 39 × 3 + 25 ÷ 5 = 131

Let's check the options –
First option: + and ÷
= 19 – 39 × 3 ÷ 25 + 5 
= 19 – 39 × 0.12 + 5
= 19 –

11 Views

Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series.
EFGHI, LMNO, RST, WX, ?

Option 1: A

Option 2: D

Option 3: B

Option 4: E

Team Careers360 25th Jan, 2024

Correct Answer: A


Solution : Given:
EFGHI, LMNO, RST, WX, ?

Each term of the series contains consecutive letters in alphabetical order and the number of letters in each term of the series decreases by 1.
EFGHI→5, LMNO→4, RST→3, WX→2; The next term will contain only one letter.
Add 3

11 Views

Question : If the perimeter of an equilateral triangle is 18 cm, then the length of each median is:

Option 1: $3\sqrt2$ cm

Option 2: $2\sqrt3$ cm

Option 3: $3\sqrt3$ cm

Option 4: $2\sqrt2$ cm

Team Careers360 24th Jan, 2024

Correct Answer: $3\sqrt3$ cm


Solution : Let $a$ be the side of the triangle.
The perimeter of an equilateral triangle = 18 cm
$3a=18$
$\therefore a=\frac{18}{3}=6$ cm
So, length of the median $=\frac{\sqrt3a}{2}=\frac{\sqrt3×6}{2}=3\sqrt3$ cm
Hence, the correct answer is $3\sqrt3$ cm.

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