Staff Selection Commission Combined Higher Secondary Level Exam
Question : Directions: Study the given diagram carefully and answer the questions. The numbers in different sections indicate the number of students who play different games. How many students play only one game?
Option 1: 32
Option 2: 37
Option 3: 61
Option 4: 53
Correct Answer: 53
Solution : In the diagram, the shaded parts represent the regions representing students playing only one game.
The number of students that play only one game is the region that does not overlap with any other region. So, the number of students who play only chess is
Question : Which of the following Harappan towns was located on Khadir Bet in the Rann of Kutch and was divided into three parts?
Option 1: Sotka koh
Option 2: Chanhudaro
Option 3: Surkotada
Option 4: Dholavira
Correct Answer: Dholavira
Solution : The correct answer is Dholavira.
The cities of the Harappan civilisation flourished on the banks of the Indus River, and these are the earliest cities in the Indian subcontinent. The city of Dholavira is located on the Khadir Bet in the Rann of Kutch
Question : If $2x+3y = 4$ and $4x^{2}+9y^{2}= 64$, then what is the value of $8x^{3}+27y^{3}$:
Option 1: 253
Option 2: 235
Option 3: 352
Option 4: 325
Correct Answer: 352
Solution : Given: $2x+3y=4$ and $4x^2+9x^2=64$ To find: $8x^3+27y^3$ Now, $2x+3y=4$ Squaring both sides, we get: ⇒ $4x^2+9y^2+12xy=16$ Putting the values, we get: ⇒ $64+12xy=16$ ⇒ $12xy=-48$ ⇒ $xy=-4$ Now again, $2x+3y=4$ Cubing both sides, we get: ⇒ $8x^3+27y^3+3×2x×3y(2x+3y)=64$ Putting the values, we get: ⇒ $8x^3+27y^3+18×(-4)×4=64$ $\therefore8x^3+27y^3=64+288=
Question : The _______ of a ray is the angle measured from the reflected ray to the normal surface.
Option 1: Angle of Diffusion
Option 2: Angle of Reflection
Option 3: Angle of Incidence
Option 4: Angle of Refraction
Correct Answer: Angle of Reflection
Solution : The correct option is the Angle of Reflection.
The angle measured from the reflected ray to the normal surface is called the "angle of reflection." The angle of reflection is the angle between the reflected ray and the normal (a line perpendicular
Question : The value of $(x^{b+c})^{b–c}(x^{c+a})^{c–a}(x^{a+b})^{a–b}$, where $(x\neq 0)$ is:
Option 1: 1
Option 2: 2
Option 3: –1
Option 4: 0
Correct Answer: 1
Solution : Given: $(x^{b+c})^{b–c}(x^{c+a})^{c–a}(x^{a+b})^{a–b}$ $(x\neq 0)$ = $(x^{(b+c)×(b–c)})(x^{(c+a)(c–a)})(x^{(a+b)×(a–b)})$ = $(x^{(b^{2}–c^{2})})(x^{(c^{2}–a^{2})})(x^{(a^{2}–b^{2})})$ = $x^{(b^{2}–c^{2}+c^{2}–a^{2}+a^{2}–b^{2})}$ = $x^{0}$ = 1 Hence, the correct answer is 1.
Question : Directions: Read the given statements and conclusions carefully. You have to consider the given statements true even if they seem at variance from commonly known facts. You have to decide which conclusion/s logically follow/s from the given statements. Statements: (I) All spoons are forks. (II) Some forks are sticks. (III) No stick is a knife. Conclusions: (I) Some knives are forks. (II) No stick is a spoon.
Option 1: Only conclusion II follows
Option 2: Both conclusions I and II follow
Option 3: Only conclusion I follows
Option 4: Neither conclusion I nor II follows
Correct Answer: Neither conclusion I nor II follows
Solution : The possible Venn diagram according to the statements is as follows –
Let's analyse the conclusions – Conclusion (I): Some knives are forks – According to the Venn diagram, there is no definite relation between knives and forks. Therefore, this
Question : Directions: In a certain code language, rocket aeroplane sky stars is written as ci pi di ki, satellite moon sun sky is written as ni ci ui li, sky sun stars mars is written as ui gi ki ci and venus aeroplane moon planet is written as di qi mi ni. How is rocket written in the given language?
Option 1: ci
Option 2: ki
Option 3: pi
Option 4: di
Correct Answer: pi
Solution : Given: 1. rocket aeroplane sky stars ⇒ ci pi di ki 2. satellite moon sun sky ⇒ ni ci ui li 3. sky sun stars mars ⇒ ui gi ki ci 4. venus aeroplane moon planet ⇒ di qi mi ni
By comparing all the
Question : Directions: Which two mathematical operations should be interchanged to balance the following equation? 19 – 39 × 3 + 25 ÷ 5 = 131
Option 1: + and ÷
Option 2: ÷ and ×
Option 3: – and ÷
Option 4: + and ×
Correct Answer: ÷ and ×
Solution : Given: 19 – 39 × 3 + 25 ÷ 5 = 131
Let's check the options – First option: + and ÷ = 19 – 39 × 3 ÷ 25 + 5 = 19 – 39 × 0.12 + 5 = 19 –
Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series. EFGHI, LMNO, RST, WX, ?
Option 1: A
Option 2: D
Option 3: B
Option 4: E
Correct Answer: A
Solution : Given: EFGHI, LMNO, RST, WX, ?
Each term of the series contains consecutive letters in alphabetical order and the number of letters in each term of the series decreases by 1. EFGHI→5, LMNO→4, RST→3, WX→2; The next term will contain only one letter. Add 3
Question : If the perimeter of an equilateral triangle is 18 cm, then the length of each median is:
Option 1: $3\sqrt2$ cm
Option 2: $2\sqrt3$ cm
Option 3: $3\sqrt3$ cm
Option 4: $2\sqrt2$ cm
Correct Answer: $3\sqrt3$ cm
Solution : Let $a$ be the side of the triangle. The perimeter of an equilateral triangle = 18 cm $3a=18$ $\therefore a=\frac{18}{3}=6$ cm So, length of the median $=\frac{\sqrt3a}{2}=\frac{\sqrt3×6}{2}=3\sqrt3$ cm Hence, the correct answer is $3\sqrt3$ cm.
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