Staff Selection Commission Combined Graduate Level Exam
Question : Select the correct direct form of the given sentence. Neha exclaimed that it was a very pleasant surprise.
Option 1: Neha said, “Is it a very pleasant surprise?”
Option 2: Neha said, “How a pleasant surprise!”
Option 3: Neha said, “It is a very pleasant surprise.”
Option 4: Neha said, “What a pleasant surprise!”
Correct Answer: Neha said, “What a pleasant surprise!”
Solution : The correct choice is the fourth option.
Direct speech involves quoting the exact words spoken by a person without any changes.
The steps of conversion are as follows:
Question : Directions: Select the correct combination of mathematical signs to sequentially replace the * and balance the given equation. 76 * 34 * 23 * 12 * 6 * 21
Option 1: +, –, +, ÷, =
Option 2: –, –, +, +, =
Option 3: ×, –, +, ÷, =
Option 4: –, –, +, ÷, =
Correct Answer: –, –, +, ÷, =
Solution : Given: 76 * 34 * 23 * 12 * 6 * 21
On replacing * with the mathematical signs, we get – First option: +, –, +, ÷, = ⇒ 76 + 34 – 23 + 12 ÷ 6 = 21
Question : The following sentence has been split into four segments. Identify the segment that contains a grammatical error. Scarcely had I / started reading / the paper / then the doorbell rang.
Option 1: Scarcely had I
Option 2: started reading
Option 3: then the doorbell rang
Option 4: the paper
Correct Answer: then the doorbell rang
Solution : The error lies in the third option.
The reason for the error is that then is not the appropriate conjunction to connect the two actions in this context.
When is the correct choice to indicate the immediate sequence of events, as scarcely
Question : Rs.11,500 has to be divided between X, Y, and Z such that X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets. How much more does Z get over X (in Rs.)?
Option 1: 7200
Option 2: 1800
Option 3: 1170
Option 4: 2450
Correct Answer: 2450
Solution : Given: Rs.11,500 has to be divided between X, Y, and Z such X gets $\frac{4}{5}$th of what Y gets and Y gets $\frac{2}{3}$rd of what Z gets. Let Z get Rs. $p$. From the question, Y will get $\frac{2p}{3}$ and X will obtain $\frac{2p}{3}×\frac{4}{5}=\frac{8p}{15}$ Also,
Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster. ACCUSED : UCCASDE :: FACTORY : TCAFOYR :: DYNAMIC : ?
Option 1: YNMICAD
Option 2: DNYMACI
Option 3: ANYDMCI
Option 4: DANYMIC
Correct Answer: ANYDMCI
Solution : Given: ACCUSED : UCCASDE :: FACTORY : TCAFOYR :: DYNAMIC : ?
Here, the letters of the given words are being shuffled following a certain pattern as shown below – ACCUSED : UCCASDE→
FACTORY : TCAFOYR→
Similarly, follow the same pattern for DYNAMIC→
So, ANYDMCI
Question : The monthly income of a person was INR 12,000 and his monthly expenditure was INR 8,000. Next year, his income increased by 10% and his expenditure by 8%. Find the percentage increase in his savings.
Option 1: 10%
Option 2: 14%
Option 3: 12%
Option 4: 15%
Correct Answer: 14%
Solution : Given: Monthly Income = INR 12000 Monthly Expenditure = INR 8000 Increase in income = 10% Increase in expenditure = 8% Solution: Savings before increase = 12000 – 8000 = INR 4000 Increase in income = 12000 + $\frac{10}{100}$ × 12000 = INR 13200 Increase
Question : The expression $\frac{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+\cot \theta+1)(\operatorname{cosec} \theta-\cot \theta+1)-2}, 0^{\circ}<\theta<90^{\circ}$, is equal to:
Option 1: $\frac{1}{2} \sin \theta$
Option 2: $2 \sin \theta$
Option 3: $\sec \theta$
Option 4: $2\operatorname{cosec} \theta$
Correct Answer: $2 \sin \theta$
Solution : $\frac{\cos ^4 \theta-\sin ^4 \theta+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+\cot \theta+1)(\operatorname{cosec} \theta-\cot \theta+1)-2}, 0^{\circ}<\theta<90^{\circ}$ $=\frac{(cos^2\theta)^2-(\sin^2\theta)^2+2 \sin ^2 \theta+3}{(\operatorname{cosec} \theta+1+\cot \theta)(\operatorname{cosec} \theta+1-\cot \theta)-2}$ $=\frac{(cos^2+\sin^2\theta)(cos^2-\sin^2\theta)+2 \sin ^2 \theta+3}{[(\operatorname{cosec} \theta+1)^2-\cot^2 \theta]-2}$ $=\frac{cos^2+\sin^2\theta +3}{[\operatorname{cosec^2} \theta+1+2\operatorname{cosec \theta}-\cot^2 \theta]-2}$ $=\frac{4}{2+2\operatorname{cosec} \theta-2}$ $=\frac{4}{2\operatorname{cosec} \theta}$ $=2 \sin \theta$ Hence, the correct answer
Question : Directions: In the following question, select the odd letter pair from the given alternatives.
Option 1: CD
Option 2: PR
Option 3: ST
Option 4: WX
Correct Answer: PR
Solution : Let's check the options – First option: CD; C + 1 = D Second option: PR; P + 2 = R Third option: ST; S + 1 = T Fourth option: WX; W + 1 = X
So, the second option is different from the
Question : The table given below shows the number of salesmen in five companies.
The number of salesmen in J is what percentage of the number of salesmen in K?
Option 1: 250%
Option 2: 150%
Option 3: 125%
Option 4: 225%
Correct Answer: 225%
Solution : Number of salesmen in J = 45 Number of salesmen in K = 20 Percent = $\frac{45}{20}\times 100 = 225$% Hence, the correct answer is 225%.
Question : (91 + 92 + 93 + ... + 110) is equal to:
Option 1: 4020
Option 2: 2010
Option 3: 6030
Option 4: 8040
Correct Answer: 2010
Solution : First term, $a$ = 91 Last term, $l$ = 110 Number of terms, $n$ = 20 The sum of n terms of series = $\frac{n}{2}(a+l)$ The sum of 20 terms of series = $\frac{20}{2}(91+110)=10(91+110)=2010$ Hence, the correct answer is 2010.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
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