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Staff Selection Commission Combined Graduate Level Exam

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12 Views

Question : Find the value of the given expression.
$\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$

Option 1: 4

Option 2: 6

Option 3: 5

Option 4: 2

Team Careers360 25th Jan, 2024

Correct Answer: 4


Solution : Given expression,
$\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$
Let us equate this with $y$
⇒ $y=\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$
⇒ $y=\sqrt{20-y}$
Squaring both sides,
⇒ $y^2=20-y$
⇒ $y^2+y-20=0$
⇒ $y^2+5y-4y-20=0$
⇒ $y(y+5)-4(y+5)=0$
⇒ $(y+5)(y-4)=0$
⇒ $y=-5$ and $y=4$
Hence, the correct answer is 4.

18 Views

Question : The Constitution forbids the employment of children below the age of________ years for dangerous jobs like factories and mines.

Option 1: 15

Option 2: 14

Option 3: 16

Option 4: 18

Team Careers360 21st Jan, 2024

Correct Answer: 14


Solution : The correct answer is 14.

The key legislation related to the employment of children in India is the "Child and Adolescent Labour (Prohibition and Regulation) Act, 1986" (often referred to as the Child Labour Act). This Act prohibits the employment of children below the age

15 Views

Question : Direction: In each of the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?

BR _ _ NB _ O _ NB

Option 1: OWOW

Option 2: RORO

Option 3: WNWN

Option 4: OWRW

Team Careers360 22nd Jan, 2024

Correct Answer: OWRW


Solution : Given:

BR _ _ NB _ O _ NB

We have to check the order of the letters in the given series.

To fill the series we have to divide the series, BR _ _ / NB _ O / _ NB.

So, the series

16 Views

Question : If $\tan x = –\frac{12}{5}$, where $x$ lies in the second quadrant, what is the value of $\sin x-\cot x$?

Option 1: $\frac{209}{156}$

Option 2: $\frac{169}{156}$

Option 3: $\frac{156}{209}$

Option 4: $\frac{144}{169}$

Team Careers360 23rd Jan, 2024

Correct Answer: $\frac{209}{156}$


Solution : In the second quadrant, $\sin x$ and $\operatorname{cosec x}$ are positive.
$\tan x = –\frac{12}{5}$
$⇒\cot x=\frac{1}{\tan x}=-\frac{5}{12}$
We know, $\sec^2x -\tan^2x=1$
$⇒\sec^2x=1+(–\frac{12}{5})^2$
$⇒\sec^2x=1+\frac{144}{25}$
$⇒\sec^2x=\frac{169}{25}$
$⇒ \sec x=\frac{13}{5}$
$⇒\cos x = \frac{5}{13}$
$\therefore\sin x = \sqrt{1-\cos^2x}=\sqrt{1-\frac{25}{169}}=\frac{144}{169}=\frac{12}{13}$
$\sin x - \cot x = \frac{12}{13} – (-\frac{5}{12})

26 Views

Question : Select the most appropriate synonym of the given word.

Authentic

Option 1: Genuine

Option 2: False

Option 3: Doubtful

Option 4: Corrupt

Team Careers360 23rd Jan, 2024

Correct Answer: Genuine


Solution : The correct option is the first option.

In the context of the word authentic, genuine is the most appropriate synonym because it closely aligns with the meaning of authentic, which means genuine, real, or true. It refers to something that is not a

19 Views

Question : $A_1$ and $A_2$ are two regular polygons. The sum of all the interior angles of $A_1$ is $1080^{\circ}$. Each interior angle of $A_2$ exceeds its exterior angle by $132^{\circ}$. The sum of the number of sides $A_1$ and $A_2$ is:

Option 1: 21

Option 2: 22

Option 3: 23

Option 4: 24

Team Careers360 21st Jan, 2024

Correct Answer: 23


Solution : Let the sides of polygon $A_1$ be $n$.
The sum of all the interior angles $A_1 = 1080^{\circ}$
$\Rightarrow (n-2)\times 180^{\circ} = 1080^{\circ}$
$\Rightarrow (n-2) =6$
$\Rightarrow n=8$
Now,
Let $I$ be the interior angle and $E$ be the exterior angle.
$\Rightarrow I-E = 132^{\circ}$.....(1)

18 Views

Question : Study the following table and answer the question that follows.

School Name

Total number of students enrolled

Percentage of students who opted for statistics
 A  450  20
 B  200  18
 C  500  12
 D  400  15

What is the average number of students who opted for other than statistics subjects in schools A and D?

Option 1: 7340

Option 2: 360

Option 3: 355

Option 4: 350

Team Careers360 20th Jan, 2024

Correct Answer: 350


Solution : In school A,
Number of students opted for other than statistics subject = (100 - 20)% of 450
= $\frac{80}{100}\times 450$ = 360
In school D,
Number of students opted for other than statistics subject = (100 - 15)% of 400
= $\frac{85}{100}\times 400$ =

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