Staff Selection Commission Combined Graduate Level Exam
Question : Direction: Rachel starts walking towards the north. After walking 15 metres. She turns south and walks 20 metres. She then turns towards the east and walks 10 metres. Then again, she walks 5 metres towards the north. How far is she from her starting point, and in which direction?
Option 1: 10 meters, West
Option 2: 5 meters, East
Option 3: 5 meters, North
Option 4: 10 meters, East
Correct Answer: 10 meters, East
Solution : As per the given information, movement of Rachel will look as follows -
In the Given Figure, A is the starting point and E is the finishing point. So, AE is the distance from the starting point.
Here, AB = 15m, AC =
Question : Select the correct passive form of the given sentence. Hang the washing on the clothesline.
Option 1: Let the washing be hanged on the clothesline.
Option 2: Let the washing be hung on the clothesline.
Option 3: Let the washing hanging on the clothesline.
Option 4: Let the washing to be hung on the clothesline.
Correct Answer: Let the washing be hung on the clothesline.
Solution : The correct choice is the second option.
Passive voice is the voice in which the object experiences an action rather than the person who performs the action. Hence, the object in the active sentence becomes the subject in
Question : The distance between the centres of two circles having radii 16 cm and 8 cm, is 26 cm. The length (in cm) of the direct common tangent of the two circles is:
Option 1: $2 \sqrt{132}$
Option 2: $\sqrt{153}$
Option 3: $2 \sqrt{153}$
Option 4: $\sqrt{132}$
Correct Answer: $2 \sqrt{153}$
Solution : Given: The radius of the bigger circle $r_1= 16$ The radius of the smaller circle $r_2= 8$ Distance between the centres, $d = 26$ So, the length of the direct common tangent, $l = \sqrt{d^2-(r_1-r_2)^2}$ $= \sqrt{26^2-(16-8)^2}$ $=\sqrt{676-64}$ $= \sqrt{612}$ $=2\sqrt{153}$ So, the length
Question : Direction: In the following question, a series is given with one or more alphabet missing. Choose the correct alternative from the given options.
DF, GJ, KM, NQ, RT, ?
Option 1: EI
Option 2: UX
Option 3: UV
Option 4: XY
Correct Answer: UX
Solution : Given: DF, GJ, KM, NQ, RT, ?
First term→ DF → D + 2 = F
Second term → GJ → F + 1 = G; G + 3 = J
Third term → KM → J + 1 = K; K + 2
Question : Directions: In a certain code language, CAKES is written as FXNBV, and ABUSE is written as DYXPH. How will BARKS be written in that language?
Option 1: EXVHU
Option 2: EXUIU
Option 3: EXUIV
Option 4: EXUHV
Correct Answer: EXUHV
Solution : Given: CAKES is written as FXNBV and ABUSE is written as DYXPH.
Add and subtract 3 alternately from the place value of each letter of CAKES to obtain the required code – C + 3 = F; A – 3 = X; K + 3
Question : Directions: In this question, some equations are solved on the same basis as a certain system. On the same basis, find out the correct answer from the four alternatives for the unsolved equation. If 4 × 3 = 14, 5 × 4 = 18 and 6 × 5 = 22, then find the value of 7 × 6 = ?
Option 1: 20
Option 2: 26
Option 3: 30
Option 4: 42
Correct Answer: 26
Solution : Given: 4 × 3 = 14; 5 × 4 = 18; 6 × 5 = 22
Multiply 2 by the sum of the numbers on the L.H.S. Like, 4 × 3 = 14→(4 + 3) × 2 = 7 × 2 = 14 5 ×
Question : Directions: Select the option figure in which the given figure is embedded. (Rotation is NOT allowed)
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Since the rotation of the figure is not allowed, we will check where the question figure can exactly fit itself in the given option figures.
From the above, it is clear that the given question figure is embedded in the second option figure. Hence, the second
Question : A spherical ball of lead, 3 cm in diameter, is melted and recast into three spherical balls. The diameters of two of these balls are $\frac{3}{2}$ cm and 2 cm, respectively. Find the diameter of the third ball.
Option 1: 2.1 cm
Option 2: 3.3 cm
Option 3: 3 cm
Option 4: 2.5 cm
Correct Answer: 2.5 cm
Solution : Given: A spherical ball of lead, 3 cm in diameter, is melted and recast into three spherical balls. Radius = $\frac{3}{2}$ cm So, the volume of the sphere = $\frac{4}{3}\pi r^3=\frac{4}{3}\pi (\frac{3}{2})^3$ cm3 The diameters of two of the new balls are $\frac{3}{2}$
Question : A mixture of acid and water contains 20% acid. When 10 litres of water is added to the mixture, then the percentage of acid becomes 15%. What is the original quantity of the mixture?
Option 1: 30 litres
Option 2: 25 litres
Option 3: 40 litres
Option 4: 35 litres
Correct Answer: 30 litres
Solution : Given: A mixture of acid and water contains 20% acid. The mixture's ratio = $\frac{(\text{20% acid})}{(\text{80% water})}$ = $\frac{20}{80}$ = 1 : 4. Let there be $x$ litres of acid in the mixture. Additionally, $4x$ litres of water should be added to the mixture.
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
He flowed into a rage (1)/ at the very (2)/ sight of that man. (3)/ No Error (4)
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 1
Solution : The first option is the correct answer.
"To fly into a rage" means to suddenly become very angry or lose one's temper explosively or uncontrollably. It describes a rapid and intense escalation of anger or fury. In the third part of the sentence, "flowed" must
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