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Staff Selection Commission Combined Graduate Level Exam

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Question : If $A=\frac{\sqrt{0.0004} \times \sqrt[3]{0.000008}}{\sqrt[4]{16000} \times \sqrt[3]{125000} \times \sqrt[4]{810}}$ and $B=\frac{\sqrt[3]{0.729} \times \sqrt[4]{0.0016}}{\sqrt{0.16}}$, then what is $A \times B$?

Option 1: $6 \times 10^{–7}$

Option 2: $\frac{7}{4} \times 10^{–8}$

Option 3: $5 \times 10^{–8}$

Option 4: $\frac{7}{3} \times 10^{–7}$

Team Careers360 20th Jan, 2024

Correct Answer: $6 \times 10^{–7}$


Solution : Given: The values of $A=\frac{\sqrt{0.0004} \times \sqrt[3]{0.000008}}{\sqrt[4]{16000} \times \sqrt[3]{125000} \times \sqrt[4]{810}}$ and $B=\frac{\sqrt[3]{0.729} \times \sqrt[4]{0.0016}}{\sqrt{0.16}}$.
$A=\frac{\sqrt{0.0004} \times \sqrt[3]{0.000008}}{\sqrt[4]{16000} \times \sqrt[3]{125000} \times \sqrt[4]{810}}=\frac{\sqrt{(0.02)^2}\times\sqrt[3]{(0.02)^3}}{\sqrt[4]{2^4\times10^3}\times\sqrt[3]{(50)^3}\times{\sqrt[4]{3^4\times10}}}$
$=\frac{{0.02} \times {0.02}}{(2\times50\times3)\times{\sqrt[4]{(10)^3}}\times{\sqrt[4]{10}}}=\frac{{0.02} \times {0.02}}{300\times{{\sqrt[4]{(10)^3\times10}}}}$
⇒ $A=\frac{{0.02} \times {0.02}}{300\times10}=\frac{0.0004}{3000}$
$B=\frac{\sqrt[3]{0.729} \times \sqrt[4]{0.0016}}{\sqrt{0.16}}=\frac{\sqrt[3]{(0.9)^3} \times \sqrt[4]{(0.2)^4}}{\sqrt{(0.4)^2}}$
⇒ $B= \frac{0.9\times 0.2}{0.4}=\frac{0.9}{0.2}$
The value of

8 Views

Question : Who introduced the Zamindari Settlement as a measure of land revenue administration?

Option 1: Lord Lytton

Option 2: Lord Curzon

Option 3: Lord Cornwallis

Option 4: Lord Wellesley

Team Careers360 25th Jan, 2024

Correct Answer: Lord Cornwallis


Solution : The correct option is Lord Cornwallis.

In 1793, Lord Cornwallis, the Governor-General of India, proposed the Zamindari Settlement. This system was a significant reform in the land revenue administration of British India. The British East India Company acknowledged zamindars, or landowners, as the rightful

14 Views

Question : An exterior angle of a triangle is 115° and one of the interior opposite angles is 45°. The other two angles are:

Option 1: 65° and 70°

Option 2: 60° and 75°

Option 3: 45° and 90°

Option 4: 50° and 85°

Team Careers360 19th Jan, 2024

Correct Answer: 65° and 70°


Solution :
Given:
$\angle$ACD = 115°, $\angle$BAC = 45°
We know, $\angle$ABC + $\angle$CAB = $\angle$ACD
⇒ $\angle$ABC = 115° - 45° 
$\therefore$ $\angle$ABC = 70°
$\angle$ACB + $\angle$BAC + $\angle$ABC = 180°
⇒ $\angle$ACB + 45° + 70° = 180°
$\therefore$ $\angle$ACB = 180°

63 Views

Question : The tens digit of a two-digit number is larger than the unit digit by 7. If we subtract 63 from the number, the new number obtained is a number formed by the interchange of the digits. Find the number.

Option 1: 81

Option 2: 18

Option 3: 62

Option 4: 26

Team Careers360 25th Jan, 2024

Correct Answer: 81


Solution : Let the number be $(10x + y)$.
According to the question,
$x > y$
⇒ $x - y = 7$
Now,
⇒ $(10x + y) - 63 =10y + x$
Options 1, 2, 3 i.e. (18, 62, 26) is lesser than 63, so we will

22 Views

Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
DISMAY : SIDYAM :: DRIVER : IRDREV :: SAFARI : ?

Option 1: SAFIAR

Option 2: IRAFAS

Option 3: FASIRA

Option 4: FSAIRA

Team Careers360 19th Jan, 2024

Correct Answer: FASIRA


Solution : Given: 
DISMAY : SIDYAM :: DRIVER : IRDREV :: SAFARI : ?

Split the words DISMAY and DRIVER into two parts. Then reverse the order of the letters of each part to get the required code.

Thus, DISMAY is related to SIDYAM.

Thus, DRIVER is

397 Views

Question : Six years ago, the ratio of ages of A to B was 7 : 5. 4 years from now, the ratio of their ages will be 11 : 9. What is A’s age at present?

Option 1: $24 \frac{1}{2}$ years

Option 2: $22 \frac{1}{2}$ years

Option 3: $23 \frac{1}{2}$ years

Option 4: $21 \frac{1}{2}$ years

Team Careers360 21st Jan, 2024

Correct Answer: $23 \frac{1}{2}$ years


Solution : Six years ago, the ratio of ages of A to B was 7 : 5.
Six years ago the ages of A and B were $7x$ and $5x$ respectively.
4 years from now, the ratio of their ages will be 11 : 9.

19 Views

Question : The value of $(0.3)^{[\frac {(200-146)}{(3 \times 3 \times 3)}-3]}$ is:

Option 1: $\frac{10}{3}$

Option 2: $\frac{5}{3}$

Option 3: $\frac{7}{3}$

Option 4: $\frac{8}{3}$

Team Careers360 25th Jan, 2024

Correct Answer: $\frac{10}{3}$


Solution : Given: $(0.3)^{[\{\frac{(200-146)}{(3 \times 3 \times 3)}\}-3]}$
= $(0.3)^{[\{\frac{54}{27}\}-3]}$
= $(0.3)^{[2-3]}$
= $(0.3)^{-1}$
= $\frac{1}{0.3}$
= $\frac{10}{3}$
Hence, the correct answer is $\frac{10}{3}$.

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