Correct Answer: Dhyanchand

Solution : The correct option is - Dhyanchand.

Field hockey player Major Dhyan Chand, who represented India, is recognized as the game's all-time best.
Due to his exceptional ball control, he was known as The Wizard or The Magician of hockey.
In 1956, the Indian government presented

Correct Answer: 0

Solution : Given, $\mathrm{K}+\frac{1}{\mathrm{~K}}+2=0$
⇒ $K^{2} + 2K + 1 = 0$
⇒ $(K+1)^{2} = 0$
⇒ $K+1 = 0$
$\therefore$ $K = -1$
Now, we have to find $K^{11}+\frac{1}{K^4}$
Putting the value of $K$, we get
$(-1)^{11} + \frac{1}{(-1)^{4}}$
$= -1 + 1 = 0$
Hence,

Correct Answer: 378

Solution : Given:
583 : 295 :: 486 : ?

Here, the sum of the digits of the first number is equal to the sum of the digits of the second number.
Like, 583 : 295; 5 + 8 + 3 = 16 and 2 + 9

Correct Answer: IUATQJ

Solution : Given:
STABLE : AEQRZJ :: TARGET : AERPER :: VISUAL :?

Vowels are written first in the code and subtract 2 from the place value of the consonants of each letter of STABLE to obtain the required code –

Thus, STABLE is coded as AEQRZJ.

Correct Answer: 34

Solution : Given –

4, 6, 10, 16, 24, ?

The pattern follow for the series is –

4 + 2 = 6; 6 + 4 = 10; 10 + 6 = 16; 16 + 8 = 24; 24 + 10 = 34

Correct Answer: (3)

Solution : The correct option is the third option.

The original sentence has a mistake with respect to pronouns. It uses "there" to refer to the plural noun "applications" which is incorrect. "There" is used for places, whereas "their" is used for persons. The correct choice

Correct Answer: 9 cm

Solution : The curved surface area of a right circular cone = 594 sq. cm.
The radius of a right circular cone, $r$ = 21 cm
Let the slant height be $l$ cm.
We know that the curved surface area of a right circular cone =

Correct Answer: 1981

Solution : The correct option is 1981.

India's population growth rate has been steadily falling since 1981. The reason behind this is that fewer individuals are having children as they realise the benefits of having small, nuclear households as opposed to huge ones.

Correct Answer: $9$ cm

Solution :
Let BD be $x$ cm.
$\therefore$ CD =$ (12\sqrt{3} - x) $cm.
$\angle$ADB = $\angle$ADC = 90°
From $\triangle$ ABD,
$\tan 30°=\frac{AD}{BD}$
$⇒\frac{1}{\sqrt{3}}=\frac{AD}{x}$
So, AD = $\frac{x}{\sqrt{3}}$-----------(1)
From $\triangle$ACD,
$\tan 60°=\frac{AD}{CD}$
$⇒\sqrt{3}=\frac{AD}{ (12\sqrt{3} - x)}$
So, AD = $\sqrt{3}(12\sqrt{3}-x)$----------(2)
From 1 and 2, we

Correct Answer: Abhinav Bindra

Solution : The correct option is - Abhinav Bindra.

At the 2008 Summer Olympics in Beijing, Abhinav Bindra won the men's 10m air rifle gold medal. He made Olympic history by becoming the first Indian to win an individual gold medal.

Sport shooter Anjali Bhagwat represented