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Staff Selection Commission Combined Graduate Level Exam

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Question : Directions: Dinesh travels from point A, 8 km eastward towards B, turns right and walks 12 km to C, turns again right and walks 4 km to point D, again turns right and travels 8 km to E. From E, he turns left and walks to F, 4 km. Now how far is he from his starting point?

Option 1: 4 km

Option 2: 6 km

Option 3: 8 km

Option 4: 12 km

Team Careers360 22nd Jan, 2024

Correct Answer: 4 km


Solution : Firstly, we will draw the diagram as per the given instructions –

Now, we have to find the distance between the starting point and the endpoint.

In the given figure, A is the starting point and F is the finishing point. So, AF is

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Question : If $(x+\frac{1}{x})^{2}=3$, then the value of $(x^{3}+\frac{1}{x^{3}})$ is:

Option 1: 0

Option 2: 1

Option 3: 2

Option 4: –1

Team Careers360 20th Jan, 2024

Correct Answer: 0


Solution : Given: $(x+\frac{1}{x})^{2}=3$,
Taking square root on both sides, we get
$(x+\frac{1}{x})=\sqrt{3}$
Now, Cubing both sides we get
$(x+\frac{1}{x})^3=(\sqrt{3})^3$
⇒ $x^3+\frac{1}{x^3}+3×x×\frac{1}{x}(x+\frac{1}{x})=(3\sqrt{3})$
⇒ $x^3+\frac{1}{x^3}=3\sqrt{3}–3(x+\frac{1}{x})$
$\because x+\frac{1}{x}=\sqrt{3}$
Thus, $x^3+\frac{1}{x^3}=3\sqrt{3}–3\sqrt{3} = 0$
Hence, the correct answer is 0.

12 Views

Question : M is three times as good a worker as N and together they finish a piece of work in 30 days. In how many days will M alone finish the work?

Option 1: 50

Option 2: 40

Option 3: 60

Option 4: 45

Team Careers360 20th Jan, 2024

Correct Answer: 40


Solution : Given: M is three times as good as N.
Let the efficiency of N and M be $x$ and $3x$ respectively.
So, total work $=30×(x+3x)=120x$ units
Therefore, the time required by A to finish the work alone = $\frac{120x}{3x}$ = 40 days
Hence, the correct

157 Views

Question : Directions: In a certain language, the word CLOCK is written as 4 – 13 – 17 – 4 – 12. How will you write PHONE in the same language?

Option 1: 17 – 10 – 16 – 15 – 6

Option 2: 17 – 9 – 16 – 17 – 6

Option 3: 17 – 9 – 17 – 15 – 6

Option 4: 16 – 9 – 15 – 16 – 5

Team Careers360 20th Jan, 2024

Correct Answer: 17 – 9 – 17 – 15 – 6


Solution : Given:
CLOCK is written as 4 – 13 – 17 – 4 – 12.

Write the position values of the letters of CLOCK, and then add 2 to the position value of O, and add 1 to

16 Views

Question : If $2x+\frac{2}{x}=3$, then the value of $x^{3}+\frac{1}{x^{3}}+2$ is:

Option 1: $\frac{3}{4}$

Option 2: $\frac{4}{5}$

Option 3: $\frac{5}{8}$

Option 4: $\frac{7}{8}$

Team Careers360 20th Jan, 2024

Correct Answer: $\frac{7}{8}$


Solution : Given: $2x+\frac{2}{x}=3$
$2(x+\frac{1}{x})=3$
$(x+\frac{1}{x})=\frac{3}{2}$
Cubing both sides, we get:
$(x+\frac{1}{x})^3=(\frac{3}{2})^3$
⇒ $x^3+\frac{1}{x^3}+3×x×\frac{1}{x}(x+\frac{1}{x})=\frac{27}{8}$
⇒ $x^3+\frac{1}{x^3}+3×\frac{3}{2}=\frac{27}{8}$
⇒ $x^3+\frac{1}{x^3}=\frac{27}{8}–\frac{9}{2}$
⇒ $x^3+\frac{1}{x^3}=–\frac{9}{8}$
To get the value of $x^{3}+\frac{1}{x^{3}}+2$, we need to add 2 both sides.
Thus, $x^{3}+\frac{1}{x^{3}}+2 = –\frac{9}{8}+2$
$\therefore x^{3}+\frac{1}{x^{3}}+2 = \frac{7}{8}$
Hence, the correct answer is $\frac{7}{8}$.

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