Correct Answer: 32

Solution : Given:
14 C 3 A 12 E 4 D 2 = ?

After replacing the letters with mathematical signs, the equation becomes –
= 14 × 3 –12 + 4 ÷ 2
= 14 × 3 –12 + 2
= 42 –12 + 2
=

Correct Answer: (2)

Solution : There is an error in the second part of the sentence as "to travel" is not needed after "avoid." The verb "avoid" is followed by the gerund form of the verb, so it should be "avoid travelling" instead of "to travel."

The correct sentence is

Correct Answer: would never have

Solution : The correct choice is the third option.

Explanation: When expressing a hypothetical or unreal condition in the past, the correct structure is, "If + past perfect + would have + past participle". The use of "would have" is appropriate to convey

Correct Answer: The movie fascinated me.

Solution : The correct choice is the first option.

Active voice emphasises the doer of the action, while passive voice emphasises the receiver. To convert passive to active, we make the subject perform the action and rephrase the verb.

The structure of the

Correct Answer: census

Solution : The correct answer is the census.

The official enumeration of the population done periodically is called a "census." The primary purpose of a census is to gather accurate and detailed information about the population, which includes data on demographics (age, gender, race, etc.), economic

Correct Answer: 4, 3, 7, 6, 1, 2, 5

Solution : Given:
E = 1, N = 2, T = 3, S = 4, T = 5, D = 6, U = 7

Let's check the given options –
First option: 4, 3, 7, 6, 1, 2, 5→STUDENT
Second option: 

Correct Answer: fod

Solution : Given:
1. hit ka tom⇒tie the shoes
2. ka lo fod⇒shoes of leather
3. lo tin lot⇒leather and rexine

By comparing all the three coded sentences, we find that –
In sentences 1 and 2, shoes and ka are common.
In sentences 2 and 3,

Correct Answer: 15127

Solution : Given:
$a+\frac{1}{a}=7$----------------(1)
Squaring both sides we get,
⇒ $a^2+\frac{1}{a^2}+2×a×\frac{1}{a}=49$
⇒ $a^2+\frac{1}{a^2}=49-2=47$ ------------------(2)
Now cubing equation 1 we get,
⇒ $a^3+\frac{1}{a^3}+3a×\frac{1}{a}(a+\frac{1}{a})=7^3$
⇒ $a^3+\frac{1}{a^3}+3×7=343$
⇒ $a^3+\frac{1}{a^3}=343-21=322$ ----------------(3)
Multiplying equations 2 and 3 we get
⇒ $a^5+a+\frac{1}{a}+\frac{1}{a^5}=47×322$
⇒ $a^5+\frac{1}{a^5}=47×322-(a+\frac{1}{a})$
⇒ $a^5+\frac{1}{a^5}=47×322-7$
$\therefore a^5+\frac{1}{a^5}=15127$
Hence, the correct answer is

Correct Answer: 98998

Solution : To be divisible by 8, the last three digits of a number must form a multiple of 8
(a) 98984: The last three digits are 984, a multiple of 8 (8 * 123). So, 98984 is divisible by 8.
(b) 98992: The last three digits

Correct Answer: (2)

Solution : The error lies in the second part of the sentence.

"Much" should be replaced with "many", as "much" is used to refer to large quantities that are uncountable in nature, whereas "many" is used to refer to large quantities that are countable in nature. It