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Staff Selection Commission Combined Graduate Level Exam

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Question : Directions: A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
ABCD, AXUR, ATMF, APET, ?

Option 1: RATM

Option 2: ALWH

Option 3: ALHR

Option 4: AMNO

Team Careers360 24th Jan, 2024

Correct Answer: ALWH


Solution : Given:
ABCD, AXUR, ATMF, APET, ?

In the given series, A is constant in all the terms. Subtract 4, 8, and 12 from the place value of the second, third, and fourth letters of the previous term to obtain the next term –
ABCD

14 Views

Question : Directions: In the following question a series is given, with one number missing. Select the missing number from the given alternatives.
1357, 3085, 5282, 8026, ?

Option 1: 9961

Option 2: 10441

Option 3: 11321

Option 4: 11401

Team Careers360 25th Jan, 2024

Correct Answer: 11401


Solution : Given:
1357, 3085, 5282, 8026, ?

Let's apply the pattern –
1357 + (12)3 = 1357 + 1728 = 3085
3085 + (13)3 = 3085 + 2197 = 5282
5282 + (14)3 = 5282 + 2744 = 8026
8026 + (15)3

21 Views

Question : Directions: Which two signs and two numbers should be interchanged to make the following equation correct?
840 ÷ 38 – 7 + 10 × 12 = 462

Option 1: 12 and 10, ÷ and +

Option 2: 12 and 38, × and –

Option 3: 12 and 7, + and ×

Option 4: 840 and 10, + and –

Team Careers360 25th Jan, 2024

Correct Answer: 12 and 38, × and –


Solution : Given:
840 ÷ 38 – 7 + 10 × 12 = 462

Let's check the options –
First option: 12 and 10, ÷ and +
On interchanging the numbers and signs, the equation becomes –
840 + 38 – 7

12 Views

Question : If $2x-6\leq x-3$ and $1+3x<4x+4$, then $x$ can take which of the following values?

Option 1: 4

Option 2: –4

Option 3: –6

Option 4: 2

Team Careers360 24th Jan, 2024

Correct Answer: 2


Solution : Given: $2x-6\leq x-3$ and $1+3x<4x+4$
Or, $2x-x\leq 6-3$ and $-4+1<4x-3x$
Or, $x\leq 3$ and $-3<x$
Or, $-3<x\leq 3$
Amongst all the given values, 2 satisfies the above condition.
Hence, the correct answer is 2.

10 Views

Question : Which of the following elements has variable valency?

Option 1: Iron

Option 2: Sodium

Option 3: Sulphur

Option 4: Magnesium

Team Careers360 23rd Jan, 2024

Correct Answer: Iron


Solution : The correct option is Iron.

Elements with variable valency are typically found in transition metals and some non-metals. Iron is a chemical element with the symbol Fe and atomic number 26. Iron is a silvery-grey, lustrous metal with a high melting point. It is known

9 Views

Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer.

I have been ______this problem since noon.

Option 1: working into

Option 2: working on

Option 3: working for

Option 4: with after

Team Careers360 23rd Jan, 2024

Correct Answer: working on


Solution : The correct choice is the second option.

Explanation: "Working on" is a commonly used phrase to indicate that someone is actively engaged in solving or addressing a problem, task, or project.

So, the sentence would be: "I have been working on this problem since

24 Views

Question : Who among the following is popularly known as '  Blade Runner ' ?

Option 1: Usain Bolt 

Option 2: Oscar Carl Pistorious

Option 3: Carl Lewis

Option 4: Ben Johnson

Team Careers360 25th Jan, 2024

Correct Answer: Oscar Carl Pistorious


Solution : The correct option is - Oscar Carl Pistorious.

Oscar Pistorius, a sprinter from South Africa, is referred to as the "Blade Runner" since he is an amputee and uses prosthetic legs to run. In 2012, he made Olympic history by becoming the first

16 Views

Question : When $2x+\frac{2}{x}=3$, then the value of ($x^3+\frac{1}{x^3}+2)$ is:

Option 1: $\frac{2}{7}$

Option 2: $\frac{7}{8}$

Option 3: $\frac{7}{2}$

Option 4: $\frac{8}{7}$

Team Careers360 24th Jan, 2024

Correct Answer: $\frac{7}{8}$


Solution : Given: $2x+\frac{2}{x}=3$
⇒ $x+\frac{1}{x}=\frac{3}{2}$ (Dividing both sides by 2)
Now, $(x+\frac{1}{x})^3=(\frac{3}{2})^3$ (Taking cube on both sides)
⇒ $x^3+\frac{1}{x^3}+3×x×\frac{1}{x}(x+\frac{1}{x})=\frac{27}{8}$
⇒ $x^3+\frac{1}{x^3}+3(\frac{3}{2})=\frac{27}{8}$
⇒ $x^3+\frac{1}{x^3}=\frac{27}{8}–\frac{9}{2}$
⇒ $x^3+\frac{1}{x^3}+2=\frac{27}{8}–\frac{9}{2}+2=\frac{27–36+16}{8}=\frac{7}{8}$
Hence, the correct answer is = $\frac{7}{8}$.

5 Views

Question : Directions: In the following question, find the odd letter cluster from the given alternatives.

Option 1: CBED

Option 2: JILK

Option 3: TSVU

Option 4: VZXY

Team Careers360 23rd Jan, 2024

Correct Answer: VZXY


Solution : Let's check the options –
First option: CBED; C – 1 = B; B + 3 = E; E – 1 = D
Second option: JILK; J – 1 = I; I + 3 = L; L – 1 = K
Third option: TSVU; T

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