Staff Selection Commission Combined Graduate Level Exam
Question : Select the option that can be used as a one-word substitute for the underlined group of words. While I was travelling in Europe, I met a man who drew maps.
Option 1: Cartographer
Option 2: Geographer
Option 3: Arbitrator
Option 4: Anthropologist
Correct Answer: Cartographer
Solution : The correct choice is the first option.
A cartographer is an individual who engages in the practice or art of making maps. Therefore, "cartographer" is the appropriate one-word substitute for the underlined group of words.
Question : Which of the following is used in photography?
Option 1: Sodium bicarbonate
Option 2: Sodium thiosulphate
Option 3: Sodium hydroxide
Option 4: Sodium sulphate
Correct Answer: Sodium thiosulphate
Solution : The correct option is Sodium thiosulphate.
Sodium thiosulfate is used in photography as a fixing agent, especially in traditional film and darkroom processes. It is used to fix or stabilise the developed image on photographic paper by removing unexposed silver halide.
Question : Directions: Which of the following letter clusters should replace # and % so that the pattern and relationship followed between the letter-cluster pair on the left side of :: is the same as that on the right side of ::? # : CLQ :: NDK : %
Option 1: # = AJS, % = MAM
Option 2: # = AOO, % = PAM
Option 3: # = EIT, % = QBN
Option 4: # = DIS, % = PBN
Correct Answer: # = AOO, % = PAM
Solution : Given: # : CLQ :: NDK : %
Let's check the options – First option: # = AJS, % = MAM AJS : CLQ→A + 2 = C; J + 2 = L; S – 2 = Q NDK : MAM→N – 1 = M; D – 3 = A; K + 2 = M Second option: # = AOO, % = PAM AOO : CLQ→A + 2 = C; O – 3 = L; O + 2 = Q NDK : PAM→N + 2 = P; D – 3 = A; K + 2 = M Third option: # = EIT, % = QBN EIT : CLQ→E – 2 = C; I + 3 = L; T – 3 = Q NDK : QBN→N + 3 = Q; D – 2 = B; K + 3 = N Fourth option: # = DIS, % = PBN DIS : CLQ→D – 1 = C; I + 3 = L; S – 2 = Q NDK : PBN→N + 2 = P; D – 2 = B; K + 3 = N
So, a similar pattern in both pairs can be observed only in the second option. Hence, the second option is correct.
Question : In the given figure, if KI = IT and EK = ET, then $\angle$ TEI =________.
Option 1: 75°
Option 2: 125°
Option 3: 105°
Option 4: 150°
Correct Answer: 105°
Solution : KI = IT and EK = ET $\angle$ KET = 150° In $\triangle$ KEI and $\triangle$ TEI, KI = IT [Given] EK = ET [Given] EI = EI [Common] So, $\triangle$ KEI $\cong$ $\triangle$ TEI, ⇒ $\angle$ KEI = $\angle$ TEI Now, $\angle$ KET + $\angle$ KEI + $\angle$ TEI = 360° ⇒ 150° + 2 × $\angle$ TEI = 360° ⇒ 2 $\angle$ TEI = 210° ⇒ $\angle$ TEI = 105° Hence, the correct answer is 105°.
Question : Directions: In a code language, SLAIN is written as PKCNU and DENT is written as VPGF. How will CUBOID be written in that language?
Option 1: FKQDWE
Option 2: FJQDWE
Option 3: FKQDVF
Option 4: EWDPKE
Correct Answer: FKQDWE
Solution : Given: SLAIN is written as PKCNU and DENT is written as VPGF.
Follow the pattern to obtain the required code – Thus, SLAIN is coded as PKCNU. And, DENT is written as VPGF. Thus, DENT is coded as VPGF. Similarly, follow the same pattern for CUBOID –
So, CUBOID is coded as FKQDWE. Hence, the first option is correct.
Question : Select the option that can be used as a one-word substitute for the given group of words. A shortened version of a larger work
Option 1: Summary
Option 2: Precise
Option 3: Shorts
Option 4: Abridgement
Correct Answer: Abridgement
Solution : The correct choice is the fourth option.
Abridgement is a term used to describe a version of a larger work that has been condensed. This involves shortening the original work by omitting details while still preserving the essential content and narrative.
The meanings of the other options are as follows:
Question : The sides of a triangle are in the ratio $\frac{1}{2}:\frac{1}{3}:\frac{1}{4}$ and its perimeter is 104 cm. The length of the longest side (in cm) is:
Option 1: 52
Option 2: 48
Option 3: 32
Option 4: 26
Correct Answer: 48
Solution : Given: The ratio of the triangle's sides $=\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$. $=\frac{1}{2} × 12 : \frac{1}{3} × 12 : \frac{1}{4} × 12$ $=6: 4: 3$ The perimeter of the triangle is $104$ cm. $\therefore$ The longest length of the triangle = $\frac{104}{6+4+3}×6= 48$ cm Hence, the correct answer is 48.
Question : Comprehension: In the following passage, some words have been deleted. Fill in the blanks with the help of the alternatives given. Select the most appropriate option for each number.
A marketplace is always abuzz with activity. It is especially (1)___________a visit in the evenings. A (2)_________range of items are on display. (3) _________and getting a satisfactory (4) _________give the necessary sense of (5) __________to the bored housewife and bring a smile (6) ___________her face. People from all (7) __________of life, rich and poor, (8) ___________shoulders with each other. From their busy (9). ___________, here people find time to (10) __________a greeting with friends or neighbours.
Question: Select the most appropriate option to fill in the blank number 10.
Option 1: displace
Option 2: transfer
Option 3: exchange
Option 4: return
Correct Answer: exchange
Solution : The correct choice is the third option.
The word exchange is appropriate in this context as it implies a mutual or reciprocal action of giving and receiving greetings.
People at the marketplace take time from their busy schedules not just to offer greetings but also to receive greetings from friends or neighbours, creating a sense of interaction and connection.
Therefore, the use of exchange in this sentence conveys the idea of a two-way communication of greetings between individuals in the social setting of the marketplace.
Question : If $\sec \theta+\tan \theta=5, (\theta \neq 0)$, then $\sec \theta$ is equal to:
Option 1: $\left(5+\frac{1}{5}\right)$
Option 2: $\frac{1}{2}\left(3+\frac{1}{3}\right)$
Option 3: $\frac{1}{2}\left(5+\frac{1}{5}\right)$
Option 4: $\left(3+\frac{1}{3}\right)$
Correct Answer: $\frac{1}{2}\left(5+\frac{1}{5}\right)$
Solution : Given: $\sec \theta+\tan \theta=5$ ..... equation1 $\sec^{2}\theta - \tan^{2}\theta =1$ ⇒ $(\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1$ ⇒ $\sec \theta-\tan \theta=\frac{1}{5}$......equation2 Adding equation1 and equation2 $2\sec\theta = 5 + \frac{1}{5}$ ⇒ $\sec\theta=\frac{1}{2}\left(5+\frac{1}{5}\right)$ Hence, the correct answer is $\frac{1}{2}\left(5+\frac{1}{5}\right)$.
Question : The following sentence has been split into four segments. Identify the segment that contains a grammatical error. I am sure that / the postman would be / coming shortly / to deliver the letter.
Option 1: I am sure that
Option 2: coming shortly
Option 3: to deliver the letter
Option 4: the postman would be
Correct Answer: the postman would be
Solution : The fourth option contains the error.
Would is used to express a past event and is the past tense of will, which is used to predict a future event. Since we are talking about a future event, we should use will instead of would.
Therefore, the correct sentence is: "I am sure that the postman will be coming shortly to deliver the letter."
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