Staff Selection Commission Combined Graduate Level Exam
Question : The Chief Minister of Andhra Pradesh launched a medical scheme for APL families. What is the name of that scheme?
Option 1: Haritha Kalyanam
Option 2: Arogya Raksha
Option 3: Kalyanam Survey
Option 4: Swasthya Raksha
Correct Answer: Arogya Raksha
Solution : The correct option is Arogya Raksha.
To deliver high-quality healthcare to the entire state's population through the implementation of "Aarogya Raksha," Andhra Pradesh is the first state in India to implement "Health for All."
Arogya Raksha Yojana is a systematic health insurance program
Question : Comprehension: In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank.
Education (1)_____ both the teaching and learning of knowledge, proper conduct, and technical competency. It thus (2)____ on the cultivation of skills, trades, or professions, as well as mental, moral, and aesthetic development. Formal education consists of systematic instruction, teaching, and training by (3)____ teachers. This consists of the application of pedagogy and the development of curricula. The right to education is a (4)_____ human right. Educational systems are established to provide education and (5)_______, often for children and the young.
Question:
Select the most appropriate option to fill in the blank number 1.
Option 1: likes
Option 2: releases
Option 3: makes
Option 4: encompasses
Correct Answer: encompasses
Solution : The correct choice is the fourth option.
Likes: It typically refers to preferences or approvals, but in this sentence structure, it doesn't connect logically to the subject "education".
Releases: It means to set something free or make something available. It doesn't coherently
Question : If $\frac{1}{x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}}}=\frac{29}{79}$, where x, y, and z are natural numbers, then the value of $(2 x+3 y-z)$ is:
Option 1: 0
Option 2: 4
Option 3: 1
Option 4: 2
Correct Answer: 2
Solution : According to the question, $\frac{1}{x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}}}=\frac{29}{79}$ ⇒ $x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}} = \frac{79}{29}$ ⇒ $x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}} = 2+\frac{21}{29}$ Comparing both sides, we get $x=2$, and $\frac{1}{y+\frac{2}{z+\frac{1}{4}}} =\frac{21}{29}$ ⇒ $\frac{1}{y+\frac{2}{z+\frac{1}{4}}}={\frac{1}{1+\frac{8}{21}}}$ ⇒ $\frac{1}{y+\frac{2}{z+\frac{1}{4}}}={\frac{1}{1+\frac{2}{5+\frac{1}{4}}}}$ Comparing both sides, we get, $y= 1$ and $z= 5$ $\therefore$ $(2 x+3 y-z)= 2 × 2 + 3
Question : The major constituent of air is
Option 1: Nitrogen
Option 2: Carbon dioxide
Option 3: Oxygen
Option 4: Hydrogen
Correct Answer: Nitrogen
Solution : The correct option is Nitrogen.
Nitrogen is the most abundant element in the atmosphere (78%). This is inert, essential for life, a component of the nitrogen cycle, a diatomic gas that maintains atmospheric pressure and is employed in agriculture and industry.
Question : In which of the following months did the Australian Open take place in 2022?
Option 1: February
Option 2: March
Option 3: January
Option 4: April
Correct Answer: January
Solution : The correct option is January.
The Australian Open is a major tennis tournament held annually in Melbourne, Australia. In 2022, the tournament dates were from January 17 to January 30. The Australian Open is one of the four Grand Slam tournaments in tennis, along
Question : Which of the following statements are correct regarding the Centre-State Relations about the three lists of the Indian Constitution?
A. The subjects which are not included in any of the three lists are called Residuary subjects. B. If there is any conflict between the Union List and the State List, then the former prevails. C. When the Parliament enacts a law on the request of two or more states, then that law made by the Parliament on the State List applies to all the states.
Option 1: A and C only
Option 2: B and C only
Option 3: A, B and C
Option 4: A and B only
Correct Answer: A and B only
Solution : The correct option is A and B only.
The subjects that are not included in any of the three lists (Union List, State List, and Concurrent List) are called residual subjects. These subjects fall under the residuary powers of the Union
Question : Inert gases are
Option 1: miscible with water
Option 2: not stable
Option 3: chemically unreactive
Option 4: chemically very reactive
Correct Answer: chemically unreactive
Solution : The correct option is chemically unreactive.
Inert gases, known as noble gases, exhibit chemical inertness due to their stable electron configurations. Their electron shells are filled, making it highly improbable for these gases to engage in chemical reactions with other elements.
Question : Simple interest received by a person in 10 years on a principal of Rs. 9500 is 130% of the principal. What is the rate of interest (in percent) per annum?
Option 1: 12
Option 2: 13
Option 3: 15
Option 4: 19
Correct Answer: 13
Solution : Given: Principal = Rs. 9500 Time = 10 years Formula Used: SI=$\frac{\text{PRT}}{100}$ Calculation: Let the rate of Interest be R. SI = $\frac{9500 \times 10 \times R}{100}$ Now we know the interest received is 130% of 9500 = $\frac{130 \times 9500}{100}$ $\therefore \frac{9500 \times 10
Question : In the given figure, ABCD is a square. EFGH is a square formed by joining mid-points of sides of ABCD. LMNO is a square formed by joining mid-points of sides of EFGH. A circle is inscribed inside LMNO. If the area of a circle is 38.5 cm2 then what is the area (in cm2) of square ABCD?
Option 1: 98
Option 2: 196
Option 3: 122.5
Option 4: 171.5
Correct Answer: 196
Solution : The area of a circle, $ \text{Area} = \pi r^2$ where $r$ is the radius of the circle. Given that the area of the circle is 38.5 cm2. $⇒ r = \sqrt{\frac{\text{Area}}{\pi}} = \sqrt{\frac{38.5}{\pi}} = 3.5$ cm The side length of square LMNO
Question : The amount (in Rs.) received at 10% per annum compound interest after 3 years is Rs. 1,19,790. What was the principal?
Option 1: 90,000
Option 2: 1,00,000
Option 3: 80,000
Option 4: 75,000
Correct Answer: 90,000
Solution : We have, A = Rs. 119790, r = 10%, and t = 3 years. $A = P \left(1 + \frac{r}{100}\right)^{t}$ Substituting the given values into the formula, we get $⇒119790 = P \left(1+\frac{10}{100}\right)^{1×3}$ $⇒119790 = P \left(1+0.1\right)^{3}$ $⇒119790 = P \left(1.1\right)^{3}$ $⇒P=\frac{119790}{1.331}=Rs. 90,000$ Hence, the
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