Staff Selection Commission Combined Graduate Level Exam
Question : Select the most appropriate option to improve the underlined segment in the given sentence.If there is no need to improve it, select ‘No improvement required’.
Each of the naughty boys were punished by the Principal.
Option 1: No improvement required
Option 2: were punish
Option 3: was punishing
Option 4: was punished
Correct Answer: was punished
Solution : The correct choice is the fourth option.
Explanation: The original sentence, "Each of the naughty boys were punished by the principal," contains a subject-verb agreement error. The correct form should use the singular verb "was" instead of the plural verb
Question : Directions: Select the set in which the numbers are related in the same way as the numbers of the following sets. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 - operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed.) (17, 26, 37) (170, 197, 226)
Option 1: (48, 63, 80)
Option 2: (45, 52, 105)
Option 3: (16, 28, 36)
Option 4: (52, 65, 83)
Correct Answer: (48, 63, 80)
Solution : Given: (17, 26, 37); (170, 197, 226)
In the given set of numbers, add 2 to the product of the second number and 2. The resultant is equal to the sum of the first and third numbers. (17, 26, 37)→17 + 37 =
Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement".
Someone must (being) killed.
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 1
Solution : The first option makes the sentence meaningful as 'must' is a modal verb and should be followed by the base form of the verb 'have'. The second and third options are incorrect due to the wrong use of the verb form after 'must'.
Question : Refer to the following data table and answer the question.
What is the value of the total stock?(in lakh rupees)
Option 1: 748.6
Option 2: 74.86
Option 3: 81.97
Option 4: 299
Correct Answer: 74.86
Solution : According to the given data in the table, Value of the total stock = Quantity of the stocks × Average cost = (99 × 15000) + (53 × 13000) + (29 × 59000) + (21 × 56000) + (97 × 25000) = 1485000 + 689000
Question : What is the child sex ratio in India in the 2011 Census?
Option 1: 914 females per 1000 males
Option 2: 911 females per 1000 males
Option 3: 941 females per 1000 males
Option 4: 814 females per 1000 males
Correct Answer: 914 females per 1000 males
Solution : The correct option is 914 females per 1000 males.
According to 2011 Census data, the child sex ratio (0 to 6) was 914 females per 1000 males. A census is a systematic and comprehensive collection of demographic, social, economic, and other
Question : Direction: The table below shows the percentage of literate people in 6 cities. This table also shows the ratio of males to females among literate people.
Percentage of literate people of any city = $\frac{\text{Literate people of the city}}{\text{Total population of the city}} × 100$ If there are 2,59,210 literate females in city 5, what is the total population of city 5?
Option 1: 6,44,000
Option 2: 3,54,200
Option 3: 6,90,000
Option 4: 4,83,000
Correct Answer: 6,44,000
Solution : Let the total number of population be $x$. The number of literate individuals is given as 92% of $x$ = $\frac{92x}{100}$ It is given that the ratio of literate males to that of females is equal to $9:7$ According to the question, The total number
Question : In $\triangle ABC$, $D$ and $E$ are points on sides $AB$ and $AC$, such that $DE$ II $BC$. If $AD=x+3$, $DB =2 x-3$, $A E=x+1$ and $EC=2 x-2$, then the value of $x$ is:
Option 1: $\frac{4}{5}$
Option 2: $\frac{1}{2}$
Option 3: $\frac{3}{5}$
Option 4: $\frac{1}{5}$
Correct Answer: $\frac{3}{5}$
Solution : As $DE \parallel BC$, and $\angle A$ is common in both $\triangle ABC$ and $\triangle ADE$. ⇒ $\triangle ABC \sim \triangle ADE$ ⇒ $\frac{AB}{AD} = \frac{AC}{AE}$ ⇒ $\frac{AD+DB}{AD} = \frac{AE+EC}{AE}$ ⇒ $\frac{ (x + 3 + 2x - 3)}{(x + 3)} = \frac{(x +
Question : Directions: Study the histogram of the marks (in mathematics) distribution of 50 students in class IX and answer the following question:
The number of students who have scored between 39 and 80 is:
Option 1: 22
Option 2: 18
Option 3: 37
Option 4: 15
Correct Answer: 22
Solution : The number of students who have scored in the interval 40 - 60 = 18 The number of students who have scored in the interval 60 - 80 = 4 Required answer = The number of students who have scored in the interval 40 -
Question : If two qualities of pulses 'X' and 'Y' of prices Rs. 100 and Rs.150 per kg are mixed in the ratio 7 : 20, then what is the price (in) of this mixture of pulses (correct to the nearest Rupee)?
Option 1: 137
Option 2: 135
Option 3: 134
Option 4: 136
Correct Answer: 137
Solution : Given: If two qualities of pulses 'X' and 'Y' of prices Rs. 100 and Rs. 150 per kg are mixed in a ratio of 7 : 20. So, the price of the mixture, = $\frac{(100×7)+(150×20)}{(7+20)}$ = $\frac{(700+3000)}{27}$ = $\frac{3700}{27}$ = Rs. 137.04 $\approx$ Rs. 137
Question : What is commonly used unit for measuring the speed of data transmission?
Option 1: Mega Hertz
Option 2: Characters per second
Option 3: Bits per second
Option 4: Nano seconds
Correct Answer: Bits per second
Solution : The correct option is Bits per second.
The standard unit for measuring data transmission speed is "bits per second" (bps). This unit measures the rate at which data is sent through a network or communication channel. Depending on the magnitude of the data
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