Staff Selection Commission Combined Graduate Level Exam
Question : Given below are four sentences in jumbled order. Pick the option that gives their correct order.
A. That is why, when a person shows off we say, 'as vain as a peacock'. B. It gives us the impression of being a very proud bird. C. But the fact is that the peacock is not vain, it displays its plumage to attract the peahen. D. When the peacock dances, it spreads its feathers.
Option 1: CABD
Option 2: DACB
Option 3: DBAC
Option 4: BCDA
Correct Answer: DBAC
Solution : The correct choice is the third option.
Sentence D introduces the specific action of the peacock, followed by sentence B explains the impression the peacock creates due to its display, suggesting that it seems proud, followed by sentence C which provides a clarification, dispelling
Question : Ram loses 12.5% of his money and after spending 75% of the remainder, is left with 630. How much money did Ram have initially?
Option 1: 2,080
Option 2: 2,880
Option 3: 2,205
Option 4: 2,808
Correct Answer: 2,880
Solution : Let $x$ be the total money. Money lost = 12.5% of $x$ Remaining money after losing = 87.5% of $x$ Money spent = 75% of 87.5% of $x$ Money left = 630 According to the question, 25% of 87.5% of $x= 630$ $⇒\frac{25 × 87.5
Question : Directions: In the following question, some parts of the sentence have errors, and some are correct. Find out which part of the sentence has an error. The number of that part is the answer. If a sentence is error-free, your answer is "No Error".
A person who sticks to one thing inspite of initial difficulties is sure to succeed in the end.
(1) A person who sticks to one thing
(2) is sure to succeed in the end.
(3) inspite of initial difficulties
(4) No Error
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The error lies in the third option.
Inspite of is not a valid word. It should be replaced with in spite of, which is a prepositional expression that means regardless of. This makes the sentence grammatically accurate.
The correct sentence is: "A person who
Question : Which of the following is equal to $[\frac{\cos \theta}{\sin \theta}+\frac{\sin \theta}{\cos \theta}]$?
Option 1: $\operatorname{cosec} \theta \sec \theta$
Option 2: $\sec \theta\tan \theta$
Option 3: $\operatorname{cosec} \theta\tan \theta$
Option 4: $\cot \theta \sec \theta$
Correct Answer: $\operatorname{cosec} \theta \sec \theta$
Solution : Given: The expression is $[\frac{\cos \theta}{\sin \theta}+\frac{\sin \theta}{\cos \theta}]$. We know the trigonometric ratios, $\frac{1}{\sin \theta} =\operatorname{cosec} \theta$ and $\frac{1}{\cos \theta} = \sec \theta$ and the trigonometric identity, $\sin^2\theta+\cos^2\theta=1$ $[\frac{\cos \theta}{\sin \theta}+\frac{\sin \theta}{\cos \theta}]$ $=\frac{\sin^2\theta+\cos^2\theta}{\sin \theta\times \cos \theta}$ $=\frac{1}{\sin \theta\times \cos \theta}=\operatorname{cosec}
Question : Directions: In the following question below are given some statements followed by some conclusions based on those statements. Taking the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows the given statements. Statements: All T is G. All G is H. Conclusions: I. All T is H. II. No G is T. III. All H is G.
Option 1: All conclusions follow
Option 2: Only conclusion III follows
Option 3: Only conclusion I follows
Option 4: Only conclusion II follows
Correct Answer: Only conclusion I follows
Solution : The possible Venn diagram, according to the given statements is as follows –
Let's analyse the conclusions – Conclusion (I): All T is H – From the Venn diagram, it is evident that the circle representing T lies inside the circle representing
Question : What is the area (in sq. units) of the triangle formed by the graphs of the equations $2x + 5y - 12=0, x + y = 3,$ and $y = 0$?
Option 1: 3
Option 2: 2
Option 3: 5
Option 4: 6
Correct Answer: 3
Solution : According to the question Intersection point (P) of line $2x + 5y - 12 = 0$ and $y = 0$ ⇒ $2x + 5 × 0 - 12 = 0$ ⇒ $x = 6$ The point of intersection is P (6, 0). Intersection point (Q)
Question : Name the Bhakti Saint from South India who was initially a Jaina and a minister in the court of a Chalukya king in the twelfth century.
Option 1: Karaikkal Ammaiyar
Option 2: Basavanna
Option 3: Eknath
Option 4: Tallapaka Annamacharya
Correct Answer: Basavanna
Solution : The correct option is Basavanna.
Basava, also known as Basavanna or Basaveshwara, is a South Indian Bhakti Saint who was a Jaina and a minister in the court of a Chalukya monarch in the twelfth century. Basava was a notable philosopher, politician, and poet-saint who
Question : Directions: Three of the following letter clusters are alike in some manner and hence form a group. Which letter cluster does not belong to that group?
Option 1: MNG
Option 2: STM
Option 3: ABU
Option 4: HED
Correct Answer: HED
Solution : Let's check the options – First option: MNG; M + 1 = N; N – 7 = G Second option: STM; S + 1 = T; T – 7 = M Third option: ABU; A + 1 = B; B – 7 = U Fourth
Question : To which country India gave Rs. 35 crore rupees to children of freedom fighter's in under the new "Muktijodha scholarship scheme"?
Option 1: Nepal
Option 2: Bhutan
Option 3: Bangladesh
Option 4: Shri Lanka
Correct Answer: Bangladesh
Solution : The correct option is Bangladesh.
The Muktijodha Scholarship Scheme, established by the Government of India, aims to offer educational support to the children of the valiant freedom fighters of Bangladesh who actively participated in the 1971 Bangladesh Liberation War.
Question : The angles of elevation of the top of a temple, from the foot and the top of a building 30 m high, are 60° and 30°, respectively. Then the height of the temple is:
Option 1: 50 metres
Option 2: 43 metres
Option 3: 40 metres
Option 4: 45 metres
Correct Answer: 45 metres
Solution : AB = Height of building = 30 metres. CD = Height of temple = $h$ metres. AB = CE = 30 metres. ∴ DE = $(h – 30)$ metres; BC = AE = $x$ metres $\angle$DAE = 30°; $\angle$DBC = 60° In ∆BCD, $\tan
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