Correct Answer: 1924

Solution : The correct answer is 1924.

The first Winter Olympic Games were organised in 1924. These inaugural Winter Games took place in Chamonix, France, and featured sports and events that are typically associated with cold-weather and snow-covered environments, such as ice hockey, figure skating, and skiing.

Correct Answer: 9, 2, ÷, ×

Solution : Given:
150 × 15 + 14 – 9 ÷ 2 = 6

Replace the given symbols and numbers in the options one by one with the original symbols and numbers in the given equation.
First option: 9, 2, –, ×
150 –

Correct Answer: Father-in-law

Solution : Given:
A @ B ⇒ A is the husband of B
A & B ⇒ A is the father of B
A # B ⇒ B is the son of A

As per the given information, the family tree will be as follows –

Here,

Correct Answer: 1928 Amsterdam

Solution : The correct option is 1928 Amsterdam.

India won its first Olympic gold medal in field hockey at the 1928 Amsterdam Olympics. India defeated Great Britain to take the gold. Major Dhyan Chand (the Wizard of Hockey) was part of that game and scored 14

Correct Answer: 1536

Solution : Let the numbers be $x$ and $5x$.
According to the question,
$x × 5x= 320$
$\Rightarrow 5x^2 = 320$
$\Rightarrow x^2 = 64$
$\Rightarrow x = 8$
So, the numbers are $8$ and $(8×5)=40$.
Now, the difference between the squares of $8$ and $40$
$=

Correct Answer: Oceans, lakes, grassland, mangroves

Solution : The correct option is Oceans, lakes, grassland, mangroves.

Because of the expanse of their water bodies and the abundance of diverse tiny algae (phytoplankton), oceans often have the highest primary production. When compared to other terrestrial ecosystems, lakes have a comparatively high

Correct Answer: 140%

Solution : The income of A is 80% of B's income.
The expenditure of A is 60% of B's expenditure.
The income of A is equal to 90% of B's expenditure.
Let the income of B be $100\text{x}$.
So,
Income of A $= (100\text{x} × \frac{80}{100})= 80\text{x}$

Correct Answer: $1$

Solution : Given: The expression is $5–\frac{8+2\sqrt{15}}{4}–\frac{1}{8+2\sqrt{15}}$.
Rationalize the fraction,
$\frac{1}{8+2\sqrt{15}}=\frac{1\times (8–2\sqrt{15})}{(8+2\sqrt{15})\times (8–2\sqrt{15})}$
= $\frac{8–2\sqrt{15}}{64–60}$
= $\frac{8–2\sqrt{15}}{4}$
The expression is $5–\frac{8+2\sqrt{15}}{4}–\frac{8–2\sqrt{15}}{4}$.
= $\frac{20–8–2\sqrt{15}–8+2\sqrt{15}}{4}$
= $\frac{20–16}{4}$
= $\frac{20–16}{4}$
= $\frac{4}{4}$
= 1
Hence, the correct answer is $1$.

Correct Answer: 24.3

Solution :
Since 48, 55, and 73 are triplets
$\triangle ABC$ is a right-angled triangle and $\angle B = 90^\circ$
We know that in a right-angled triangle,
Length of the median from the right-angled vertex = $\frac{\text{Length of hypotenuse}}{2}$
⇒ $BM = \frac{AC}{2} = \frac{73}{2}$
And we

Correct Answer: Goose

Solution : Given:
Bull : Cow :: Gander : ?

Like, the male cow is called a bull.
Similarly, a gander is a male bird, and its female is called a goose.

Hence, the second option is correct.