Staff Selection Commission Combined Graduate Level Exam
Question : The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. The average of the remaining two numbers is:
Option 1: 4.6
Option 2: 4.5
Option 3: 4.8
Option 4: 4.7
Correct Answer: 4.6
Solution : Given: The average of six numbers = 3.95 The average of two numbers = 3.4 The average of the other two numbers = 3.85 According to the question, The sum of all numbers = 6 × 3.95 = 23.7 The sum of two numbers =
Question : The below equation provides the property of the motion of an object, traversing a circular path. What is 'V' in this equation? AC = V2/R
Option 1: Distance
Option 2: Surface area
Option 3: Speed
Option 4: Intensity
Correct Answer: Speed
Solution : The correct option is Speed.
In the equation ac = V2/R,
Question : Direction: If 264 * 2 = 6, 870 * 3 = 11 then what should be 735 * 5 be?
Option 1: 05
Option 2: 12
Option 3: 16
Option 4: 03
Correct Answer: 12
Solution : Given: 264 * 2 = 6 870 * 3 = 11
Here, 264 * 2 → 264 ÷ 2 = 132 → 1 + 3 + 2 = 6 870 * 3 → 870 ÷ 3 = 290 → 2 + 9 + 0 =
Question : Directions: Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster. ROSE : IVQS :: SUIT : XLWT :: TIME : ?
Option 1: IPKU
Option 2: IPKV
Option 3: JPKU
Option 4: JPKV
Correct Answer: IPKU
Solution : Given: ROSE : IVQS :: SUIT : XLWT :: TIME : ?
Reverse the order of the letters of ROSE and SUIT and then add consecutive natural numbers in decreasing order (starting from 4) to the place values of the obtained letters, to get the
Question : Directions: Select the set in which the numbers are related in the same way as the numbers of the following sets. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is NOT allowed.) (9, 343, 2) (12, 729, 3)
Option 1: (98, 49, 92)
Option 2: (13, 4, 89)
Option 3: (12, 66, 20)
Option 4: (12, 125, 7)
Correct Answer: (12, 125, 7)
Solution : Given: (9, 343, 2); (12, 729, 3)
Here, the pattern followed is as follows – ⇒ (9, 343, 2)→9 – 2 = 7 and 73 = 343 ⇒ (12, 729, 3)→12 – 3 = 9 and 93 = 729
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Question : Which of the following rocks is formed by the cooling and crystallisation of magma?
Option 1: Granite
Option 2: Chalk
Option 3: Coal
Option 4: Shell
Correct Answer: Granite
Solution : The correct answer is Granite.
Granite is a rock that is formed by the cooling and crystallisation of magma. Magma, which is a molten rock material, cools and solidifies beneath the earth's surface to form granite.
Question : The radius of a circle is 10 cm. The angle made by chord AB at the centre of this circle is 60°. What is the length of this chord?
Option 1: 40 cm
Option 2: 20 cm
Option 3: 30 cm
Option 4: 10 cm
Correct Answer: 10 cm
Solution : Given, the radius of the circle = 10 cm Angle made by chord AB at the centre of this circle = 60° OA = OB = 10 cm OAB is an isosceles triangle. So, $\angle$OAB = $\angle$OAB = $\frac{180^\circ-60^\circ}{2}=60^\circ$ [by angle sum property.] Since,
Question : Directions: A piece of paper is folded and cut as shown below in the question figures. From the given answer figures, indicate how it will appear when opened.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the given folded paper is unfolded, it will look like –
Hence, the fourth option is correct.
Question : A sum of Rs. 3200, invested at 10% p.a. compounded quarterly, amounts to Rs. 3362. Compute the time.
Option 1: $\frac{1}{2}$ year
Option 2: $1$ year
Option 3: $2$ years
Option 4: $\frac{3}{4}$ year
Correct Answer: $\frac{1}{2}$ year
Solution : Given: Principal = Rs. 3200 Amount = Rs. 3362 Rate = 10% per annum = $\frac{10}{4}=\frac{5}{2}$ per quarter $\text{Compound interest + Principal}=\text{Principal}×(1+\frac{\text{Rate}}{100})^{\text{Time}}$ ⇒ $3362 = 3200×(1+\frac{5}{2×100})^n$ ⇒ $\frac{3362}{3200}=(\frac{41}{40})^n$ ⇒ $\frac{1681}{1600}=(\frac{41}{40})^n$ ∴ $(\frac{41}{40})^2=(\frac{41}{40})^n$ Comparing the powers, $n = 2$ quarters or $\frac{1}{2}$ year. Hence, the
Question : Refer to the following data table and answer the question.
What was the increase in the height of the child from the 10th Birthday to the 11th birthday?
Option 1: 15 cm
Option 2: 10 cm
Option 3: 5 cm
Option 4: 4 cm
Correct Answer: 5 cm
Solution : Refer to the table: The height of the child on 10th birthday = 145 cm The height of the child on 11th birthday = 150 cm The increase in the height of the child from the 10th birthday to the 11th Birthday = The
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