Staff Selection Commission Sub Inspector Exam
Question : ________ 2005 is referred to as the "Right to Work" as it guaranteed 100 days of employment in a year by the Indian Government to people who need and who can do work.
Option 1: Mahatma Gandhi Regional Employment Guarantee Act
Option 2: Mahatma Gandhi Rural Employment Act
Option 3: Mahatma Gandhi National Rural Employment Guarantee Act
Option 4: Mohan Gandhi Regional Guarantee Act
Correct Answer: Mahatma Gandhi National Rural Employment Guarantee Act
Solution : The correct answer is the Mahatma Gandhi National Rural Employment Guarantee Act.
Enacted on August 23, 2005, the Mahatma Gandhi National Rural Employment Guarantee Act (MGNREGA) provides a crucial social safety net for rural India. Often termed the Right to Work, it ensures 100 days of guaranteed employment annually for those in rural areas seeking work. If the government fails to provide employment, the act also offers unemployment benefits. Implemented in February 2006 under the UPA government, it aims to enhance livelihoods and alleviate rural poverty.
Question : Directions: Select the correct mirror image of the given combination when the mirror is held at the right side.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection. Here, according to the information provided, the mirror is placed on the right side of the figure. So, the left side of the reflected image will appear as the right side, and the right side will appear as the left side. However, the top and bottom of the reflected image will remain the same. Thus, the correct mirror image of the given figure will be –
Hence, the third option is correct.
Question : Direction: The table given below shows the statistics of the top 10 scores in IPL 2016. A few entries are missing in the table. Here INN, AVG and SR stand for innings played, batting average, and batting strike rate respectively. Based on the table answer the following question. (Strike rate = $\frac{\text{Runs}}{\text{balls faced}}\times $100) and AVG = $\frac{\text {Runs}}{\text {INN – NOT OUT}}$
How many runs were scored by hitting sixes taking all the players together?
Option 1: 780
Option 2: 880
Option 3: 786
Option 4: 886
Correct Answer: 786
Solution : As per the given table: Runs scored by sixes = (28 + 32 + 23 + 9 + 5 + 4 + 12 + 6 + 12) × 6 = 131 × 6 = 786 Hence, the correct answer is 786.
Question : Directions: Select the option that represents the letters that when placed from left to right in the blanks below will complete the letter series. _LJ_GH_L_I_HM_J_G_ _LJ_GH
Option 1: MMIJGILHMI
Option 2: MIMJGLIHMI
Option 3: IMMJGLIIMH
Option 4: IMMGJLIHIM
Correct Answer: MIMJGLIHMI
Solution : Given: _LJ_GH_L_I_HM_J_G_ _LJ_GH
To fill the series, we have to divide the series – _LJ_GH / _L_I_H / M_J_G_ / _LJ_GH Let's check the given options – First option: MMIJGILHMI; MLJMGH / ILJIGH / MIJLGH / MLJIGH (No repeated pattern found.) Second option: MIMJGLIHMI; MLJIGH / MLJIGH / MLJIGH / MLJIGH (MLJIGH is repeated in the series.) Third option: IMMJGLIIMH; ILJMGH / MLJIGH / MLJIGI / MLJHGH (No repeated pattern found.) Fourth option: IMMGJLIHIM; ILJMGH / MLGIJH / MLJIGH / ILJMGH (No repeated pattern found.) So, the sequence is MLJIGHMLJIGHMLJIGHMLJIGH. Hence, the second option is correct.
Question : Two circles with their centres at O and P and radii 8 cm and 4 cm respectively touch each other externally. The length of their common tangent is:
Option 1: 8.5 cm
Option 2: $\frac{8}{\sqrt{2}}$ cm
Option 3: $8\sqrt{2}$ cm
Option 4: 8 cm
Correct Answer: $8\sqrt{2}$ cm
Solution : Given, OQ = 8 cm and PR = 4 cm Construction: Draw a perpendicular from P to OQ. Since QR is a tangent, $\angle$ OQR = $\angle$ PRQ = 90$^\circ$ So, PSQR forms a rectangle. Applying Pythagoras theorem in $\triangle$ POS, PO2 = OS2 + PS2 ⇒ (8+4)2 = (8-4)2 + QR2 ⇒ QR2 = 144 – 16 ⇒ QR = $8\sqrt{2}$ cm. Hence, the correct answer is $8\sqrt{2}$ cm.
Question : Directions: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
Option 1: 42, 72
Option 2: 56, 63
Option 3: 20, 42
Option 4: 132, 182
Correct Answer: 56, 63
Solution : Let's check each option –
First option: 42, 72; Both are even numbers. Second option: 56, 63; Consists of one even and one odd number. Third option: 20, 42; Both are even numbers. Fourth option: 132, 182; Both are even numbers.
So, the option second is different from the others as here the pairs are not even number. Hence, the second option is correct.
Question : The sides of a triangle are 24 cm, 26 cm, and 10 cm. At each of its vertices, circles of radius 4.2 cm are drawn. What is the area ( in cm2) of the triangle, excluding the portion covered by the sectors of the circles? $\left(\pi=\frac{22}{7}\right)$
Option 1: 120
Option 2: 105.86
Option 3: 92.28
Option 4: 27.72
Correct Answer: 92.28
Solution : According to the question, Side of triangles = 24 cm, 26 cm, and 10 cm. Since $(26)^{2} = (24)^{2} + (10)^{2}$, then the triangle is right angles triangle. So, the area of triangle = $\frac{1}{2}$ × base × height = $\frac{1}{2}$ × 24 × 10 = 120 cm2 Now, The area of the triangle is covered by 3 sectors with a total angle of 180° = $\frac{180}{360}\pi$ × (4.2)2 = 27.72 cm2 ⇒ area of the triangle excluding the area covered by the sectors = 120 – 27.72 = 92.28 cm2 Hence, the correct answer is 92.28.
Question : What is the percentage of people below the poverty line estimated in rural areas of India in 2011–12?
Option 1: 25.7%
Option 2: 13.7%
Option 3: 35.9%
Option 4: 21.9%
Correct Answer: 25.7%
Solution : The correct answer is 25.7%.
According to a news release from the Commission, the estimated percentage of people living below the poverty line in 2011–12 was 25.7% in rural areas, 13.7% in urban areas, and 21.9% nationwide. However, each state will have a different poverty line.
Question : Simplify $\frac{\cos ^4 \theta-\sin ^4 \theta}{\sin ^2 \theta}$.
Option 1: $1-\tan ^2 \theta$
Option 2: $\tan ^2 \theta-1$
Option 3: $\cot ^2 \theta-1$
Option 4: $1-\cot ^2 \theta$
Correct Answer: $\cot ^2 \theta-1$
Solution : $\frac{\cos ^4 \theta-\sin ^4 \theta}{\sin ^2 \theta}$ $= \frac{(\cos^2 \theta - \sin^2 \theta)(\cos^2 \theta + \sin^2 \theta)}{\sin ^2 \theta}$ $=\frac{\cos^2 \theta - \sin^2 \theta}{\sin ^2 \theta}$ [As $\cos^2 \theta + \sin^2 \theta = 1$] $=\frac{\cos^2 \theta}{\sin ^2 \theta}-\frac{\sin^2 \theta}{\sin^2 \theta}$ $=\cot ^2 \theta-1$ Hence, the correct answer is $\cot ^2 \theta-1$.
Question : The value of $[(0.87)^2+(0.13)^2+(0.87)×(0.26)]^{2013}$ is:
Option 1: 0
Option 2: 2013
Option 3: 1
Option 4: –1
Correct Answer: 1
Solution : Given: $[(0.87)^2+(0.13)^2+(0.87)×(0.26)]^{2013}$ = $[(0.87)^2+(0.13)^2+(0.87)×2×(0.13)]^{2013}$ = $(0.87+0.13)^{2\times 2013}$ = $(1)^{2\times 2013}$ = $1$ Hence, the correct answer is 1.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile
