Staff Selection Commission Sub Inspector Exam
Question : Who used the pseudonym "Bhanusingha"?
Option 1: Bankim Chandra Chattopadhyay
Option 2: Sunil Gangopadhyay
Option 3: Rabindranath Tagore
Option 4: Michael Madhusudan Dutt
Correct Answer: Rabindranath Tagore
Solution : The correct answer is Rabindranath Tagore.
Rabindranath Tagore's pseudonym is "Bhanusingha". He was a famous Bengali polymath, poet, musician, and artist, and was the first Indian-origin person to win the Nobel Prize for literature in 1913.
Question : Where is the satellite launching centre of India located?
Option 1: Ahmedabad
Option 2: Hassan
Option 3: Sriharikota
Option 4: Thumba
Correct Answer: Sriharikota
Solution : The correct option is Sriharikota.
The satellite launching centre of India is called the Satish Dhawan Space Centre. It is located in Sriharikota, Andhra Pradesh. It is the primary launch centre for the Indian Space Research Organisation (ISRO), responsible for launching satellites into various orbits for different purposes, including communication, Earth observation, navigation, and scientific research.
Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term and the sixth term is related to the fifth term. 6 : 32 :: 10 : ? :: 11 : 117
Option 1: 99
Option 2: 110
Option 3: 88
Option 4: 96
Correct Answer: 96
Solution : Given: 6 : 32 :: 10 : ? :: 11 : 117
Square the number given in the first term and then subtract 4 from the resultant number, to obtain the required missing term – Like, 6 : 32→62 – 4 = 36 – 4 = 32 And, 11 : 117→112 – 4 = 121 – 4 = 117 Similarly, follow the same pattern for 10 : ?→ 102 – 4 = 100 – 4 = 96
So, 96 is the required missing number. Hence, the fourth option is correct.
Question : If $a^2+b^2=2$ and $c^2+d^2=1$, then the value of $(ad-bc)^2+(ac+bd)^2$ is:
Option 1: $\frac{4}{9}$
Option 2: $\frac{1}{2}$
Option 3: $1$
Option 4: $2$
Correct Answer: $2$
Solution : Given: $a^2+b^2=2$ and $c^2+d^2=1$ $(ad-bc)^2+(ac+bd)^2$ $= (ad)^2+(bc)^2-2abcd+(ac)^2+(bd)^2+2abcd$ $=d^2(a^2+b^2)+c^2(a^2+b^2)$ $=(a^2+b^2)(c^2+d^2)$ $=2 \times 1$ $=2$ Hence, the correct answer is 2.
Question : Directions: Six students Shree, Dayal, Sharda, Tripti, Shrishti and Manju are sitting around a circular table facing the centre (not necessarily in the same order). Shree is an immediate neighbour of both Dayal and Tripti. Manju is sitting second to the right of Dayal. Shrishti is an immediate neighbour of both Manju and Tripti. Who is an immediate neighbour of Sharda?
Option 1: Dayal
Option 2: Shree
Option 3: Tripti
Option 4: Shrishti
Correct Answer: Dayal
Solution : Given: (I) Six students Shree, Dayal, Sharda, Tripti, Shrishti and Manju are sitting around a circular table facing the centre. Shree is an immediate neighbour of both Dayal and Tripti.
(II) Manju is sitting second to the right of Dayal. Shrishti is an immediate neighbour of both Manju and Tripti.
So, Manju and Dayal are immediate neighbours of Sharda. Hence, the first option is correct.
Question : Study the given graph and answer the question that follows. What is the difference between the production of company C in 2015 and the production of company B in 2018?
Option 1: 15,00,000 tonnes
Option 2: 1,00,000 tonnes
Option 3: 10,000 tonnes
Option 4: 10,00,000 tonnes
Correct Answer: 10,00,000 tonnes
Solution : According to the question, Production of cement by company C in 2015 = 45 lakh tonnes Production of cement by company B in 2018 = 55 lakh tonnes Now the difference in both amounts = 55 lakh tonnes – 45 lakh tons = 10 lakh tonnes or 10,00,000 tonnes Hence, the correct answer is 10,00,000 tonnes.
Question : Select the most appropriate synonym of the given word. Unequivocal
Option 1: Complete
Option 2: Articulate
Option 3: Unambiguous
Option 4: Doubted
Correct Answer: Unambiguous
Solution : The correct choice is the third option.
Unequivocal means leaving no doubt or uncertainty. In this context, unambiguous is a suitable synonym because it also conveys the idea of being clear, definite, and without any ambiguity or confusion.
The meanings of the other words are:
Therefore, the right answer is unambiguous.
Question : A 64 cm wide path is made around a circular garden having a diameter of 10 metres. The area (in m2) of the path is closest to: (Take $\pi=\frac{22}{7}$)
Option 1: 10
Option 2: 21
Option 3: 15
Option 4: 9
Correct Answer: 21
Solution : Width of the circular path = 64 cm Diameter of the circular garden = 10m = 1000 cm The radius of the circular garden = $\frac{1000}{2}$ = 500 cm Inner radius, $r$ = 500 cm Outer radius, $R$ = (500 + 64) = 564 cm Area of path = Outer area – Inner area = $\pi (R^2-r^2)$ = $\frac{22}{7} \times (564^2 - 500^2)$ = $\frac{22}{7} \times (564 + 500)(564 - 500)$ = $\frac{22}{7} \times 1064 \times 64$ = $214016 $ cm2 = $21.4016\approx 21$ m2 Hence, the correct answer is 21.
Question : Mallika Sarabhai was honoured by the __________ government with Chevalier des Palmes Académiques 2005.
Option 1: French
Option 2: Canadian
Option 3: Swiss
Option 4: Belgian
Correct Answer: French
Solution : The correct option is French.
Mallika Sarabhai, an Indian classical dancer, was honoured by the French government with the Chevalier des Palmes Académiques in 2005. The Chevalier des Palmes Académiques is a French order bestowed to recognise significant contributions to the field of education and culture.
Question : The given bar graph represents the number of boys and girls in five different schools. Study the graph and answer the question that follows.
In which school is the percentage of girls the lowest?
Option 1: B
Option 2: A
Option 3: E
Option 4: C
Correct Answer: E
Solution : According to the question Percentage of girls in a school= $\frac{\text{Number of girls}}{\text{Total number of students}}$ × 100 In school A, percentage of girls = $\frac{500}{1100}$ × 100 = 45.4% In school B, percentage of girls = $\frac{550}{1000}$ × 100 = 55% In school C, percentage of girls = $\frac{650}{1400}$ × 100 = 46.4% In school D, percentage of girls = $\frac{600}{1300}$ × 100 = 46.1% In school E, percentage of girls = $\frac{650}{1450}$ × 100 = 44.8% So, school E has a minimum percentage of girls. Hence, the correct answer is E.
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