Correct Answer:

Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection.
So, according to the above property and the information provided, the mirror is placed on the right side of the figure (on line XY). So, the left side of the reflected image will appear as the right side and the right side will appear as the left side. However, the top and bottom of the reflected image will remain the same.
Thus, the correct mirror image of the given figure will be –

Hence, the first option is correct.

Correct Answer: Sundarbans

Solution : The correct answer is Sundarbans.

A wetland is an area of land that is either covered by water or saturated with water. Sundarbans is the largest protected wetland in India. Sundarbans is a Mangrove area formed in the Bay of Bengal, and there are more than 70 wetlands in India. Chilika Lake in Odisha and Keoladeo National Park in Rajasthan were recognised as the first Ramsar sites in India.

Correct Answer:

Solution : Since the rotation is restricted. So, the embedded figure will have the same orientation as the main figure. By comparison of all the option figures, the given question figure is embedded only in the fourth option figure.

Hence, the fourth option is correct.

Correct Answer: ALV

Solution : Given:
GAYATRI : AAR :: PALLAVI : ?

If we take every other letter of the word GAYATRI, we get the sequence AAR. (GAYATRI)
Thus, GAYATRI is coded as AAR. 
Similarly, if we take every other letter of the word PALLAVI, we get the sequence ALV. (PALLAVI)

Thus, PALLAVI is coded as ALV. Hence, the fourth option is correct.

Correct Answer: $8$

Solution : Given: $\left(5 \div 2\right.$ of $\left.\frac{1}{2}\right)+\left(5 \frac{1}{4} \div \frac{3}{7}\right.$ of $\left.\frac{1}{2}\right) \div\left(5 \frac{1}{9}-7 \frac{7}{8} \div 9 \frac{9}{20}\right) \times \frac{11}{21}$
$=\left(5 \div (2\right.\times\left.\frac{1}{2})\right)+\left( \frac{21}{4} \div (\frac{3}{7}\right.\times\left.\frac{1}{2})\right) \div\left( \frac{46}{9}-\frac{63}{8} \div \frac{189}{20}\right) \times \frac{11}{21}$
$=5+\left( \frac{21}{4} \div \frac{3}{14}\right.) \div\left( \frac{46}{9}-\frac{63}{8} \times \frac{20}{189}\right) \times \frac{11}{21}$
$=5+\left( \frac{21}{4} \times \frac{14}{3}\right.) \div\left( \frac{46}{9}-\frac{5}{6} \right) \times \frac{11}{21}$
$=5+\frac{49}{2} \div \frac{92-15}{18} \times \frac{11}{21}$
$=5+\frac{49}{2} \times \frac{18}{77} \times \frac{11}{21}$
$=5+3$
$=8$
Hence, the correct answer is $8$.

Correct Answer: LNQW

Solution : Let's check each option –

First option: EGKQ; G – E = 2; K – G = 4; Q – K = 6; The difference between the letters follows the increasing order of the even numbers.
Second option: CEIO; E – C = 2; I – E = 4; O – I = 6; The difference between the letters follows the increasing order of the even numbers.
Third option: LNQW; N – L = 2; Q – N = 3; W – Q = 6; The difference between the letters does not follow the increasing order of the even numbers.
Fourth option: PRVB; R – P = 2; V – R = 4; B – V = 6; The difference between the letters follows the increasing order of the even numbers.

So, LNQW is different from the other three. Hence, the third option is correct.

Correct Answer: 9

Solution : Given:
1. She was working is written as 592
2. I was curious is written as 267
3. She is curious is written as 987

By comparing, all three coded sentences –
 In sentences 1 and 2, was and 2 are common.
In sentences 1 and 3, she and 9 are common.
In statements 2 and 3, curious and 7 are common.
The remaining word and code in sentence 1 are working and 5; in sentence 2 are I and 6; in sentence 3 are is and 8.

So, she will be coded as 9. Hence, the first option is correct.

Correct Answer: $300(\sqrt3 - 1)$ m

Solution :
$AB$ = height of peak = 300 m
$CD$ = length of Bridge
We are given the angle of depression,
i.e., $\angle EAC = 45°$ and $\angle EAD = 30°$
⇒ $\angle ACB = 45°$ and $\angle ADB = 30°$
Now, \(In \triangle ABC\)
\(\tan\theta = \frac{P}{B}\)
\(\tan45 ^{\circ} =\frac{AB}{BC}\)
\(1=\frac{AB}{BC}=AB:BC=1:1\)
\(In\ \triangle ABD,\)
⇒ \(\tan30 ^{\circ} =\frac{AB}{BD}\)
⇒ \(\frac{1}{\sqrt{3}}=\frac{AB}{BD}\Rightarrow AB:BD=1:\sqrt{3}\)
Now,
\(CD = BD - BC\)
⇒ \(CD \Rightarrow \sqrt{3}-1\)
$AB$ = 1 unit = 300 metre
So, $CD=(\sqrt{3}-1)$ units = $300(\sqrt{3}-1)$ metres
Hence, the correct answer is $300(\sqrt3 - 1)$ m.

Correct Answer: Rs. 1052

Solution : Given: Principal = Rs. 800, Amount = Rs. 956, and Time = 3 years
Rate of interest, $R$ = 4% for extra interest
Use the formula below.
Extra Simple Interest = $\frac{\text{Principle×Rate×Time}}{100}$ 
= $\frac{800×3×4}{100}$
= Rs. 96
So, the total amount received = 956 + 96 = Rs. 1052
Hence, the correct answer is Rs. 1052.

Correct Answer: OPR – JKL

Solution : Let's check each option –
First option: OPR – JKL;  The opposite letter of O is not J; the opposite letter of P is K; and the opposite letter of R is not L.
Second option: BFX –  YUC;  The opposite letter of B is Y; the opposite letter of F is U; and the opposite letter of X is C.
Third option: PHJ –  KSQ;  The opposite letter of P is K; the opposite letter of H is S; and the opposite letter of J is Q.
Fourth option: RTV –  IGE; The opposite letter of R is I; the opposite letter of T is G; and the opposite letter of V is E.

Therefore, the first option is different from the others as it does not have opposite letters. Hence, the first option is correct.