Staff Selection Commission Sub Inspector Exam
Question : Directions: How many quadrilaterals are there in the given figure?
Option 1: 5
Option 2: 6
Option 3: 8
Option 4: 10
Correct Answer: 6
Solution : The given figure can be labeled as shown below –
There are 6 quadrilaterals in the above figure. They are ADFE, FEBC, ADCE, BCFA, AFCE, ABCD.
Hence, the second option is correct.
Question : Directions: In the following question, a series is given with one (or more) number(s)/alphabet missing. Choose the correct alternative from the given options. J2Z, K4X, L7V, M11T, ?
Option 1: O17R
Option 2: N17S
Option 3: R16N
Option 4: N16R
Correct Answer: N16R
Solution : Given: J2Z, K4X, L7V, M11T, ?
Add 1 to the place value of the first letter and add consecutive natural numbers starting from 2 to the number of the previous term respectively, and subtract 2 from the third letter to obtain the next term in the series – J2Z→J + 1 = K; 2 + 2 = 4; Z – 2 = X→K4X K4X→K + 1 = L; 4 + 3 = 7; X – 2 = V→L7V L7V→L + 1 = M; 7 + 4 = 11; V – 2 = T→M11T M11T→M + 1 = N; 11 + 5 = 16; T – 2 = R→N16R
So, N16R is the missing term of the series. Hence, the fourth option is correct.
Question : If $\cot \theta=\frac{1}{\sqrt{3}}, 0^{\circ}<\theta<90^{\circ}$, then the value of $\frac{2-\sin ^2 \theta}{1-\cos ^2 \theta}+\left(\operatorname{cosec}^2 \theta-\sec \theta\right)$ is:
Option 1: 0
Option 2: 2
Option 3: 5
Option 4: 1
Correct Answer: 1
Solution : $\cot \theta=\frac{1}{\sqrt{3}}$ ⇒ $\theta=60^{\circ}$ So, $\frac{2-\sin ^2 \theta}{1-\cos ^2 \theta}+\left(\operatorname{cosec}^2 \theta-\sec \theta\right)$ = $\frac{2-\sin ^2 60^{\circ}}{1-\cos ^2 60^{\circ}}+\left(\operatorname{cosec}^2 60^{\circ} -\sec 60^{\circ}\right)$ = $\frac{2- \frac{3}{4}}{1-\frac{1}{4}}+\frac{4}{3} -2$ = $\frac{\frac{5}{4}}{\frac{3}{4}}+\frac{4}{3} -2$ = $\frac{5}{3}+\frac{4}{3} -2$ = $\frac{9}{3} -2$ = 3 – 2 = 1 Hence, the correct answer is 1.
Question : Who is the first woman governor of a State in free India from the following?
Option 1:
Sarojini Naidu
Option 2:
Sucheta Kripalani
Option 3:
Indira Gandhi
Option 4: Vijaya Lakshmi Pandit
Correct Answer:
Solution : The correct answer is Sarojini Naidu.
Sarojini Naidu was the first female Governor of a state in independent India. She served as the Governor of the United Province from 1947 to 1949. Sucheta Kripalani was the country's first woman Chief Minister and held the position of Chief Minister of the Uttar Pradesh Government from 1963 to 1967. Indira Gandhi was India's first female Prime Minister. Vijaya Lakshmi Pandit was the first woman to hold the position of President of the United Nations General Assembly.
Question : Study the graph and answer the question:
The number of families whose monthly expenditures on education are INR 2,500 or more but below INR 4,000 is what percentage more than the number of families whose monthly expenditures on education are INR 4,500 or more but below INR 6,000?
Option 1: 37.6
Option 2: 27.3
Option 3: 29.8
Option 4: 36.4
Correct Answer: 37.6
Solution : Number of families whose monthly expenditure on education is INR 2500 or more but below INR 4000 = 47 + 55 + 70 = 172 Number of families whose monthly expenditures on education are INR 4500 or more but below INR 6000 = 52 + 43 + 30 =125 Required percentage gain = $\frac{172 - 125}{125}\times 100\% = 37.6\%$ Hence, the correct answer is 37.6.
Question : The given pie chart shows the percentage distribution of 450 employees in an organization. Study the pie chart and answer the question that follows.
What is the number of employees working in department B?
Option 1: 72
Option 2: 36
Option 3: 90
Option 4: 63
Correct Answer: 63
Solution : According to the question Total employees = 450 ⇒ number of employees in department B = $\frac{14}{100}$ × 450 = 0.14 × 450 = 63 Hence, the correct answer is 63.
Question : The remainder when 72 × 73 × 78 × 76 is divided by 35 is:
Option 1: 12
Option 2: 15
Option 3: 22
Option 4: 8
Correct Answer: 8
Solution : (72 × 73 × 78 × 76) divided by 35 We divide every number individually by 35, then the total remainder is also divided by 35 to get the required remainder. $\frac{(72 × 73 × 78 × 76)}{35}$ ⇒ $\frac{(2 × 3 × 8 × 6)}{35}$ ⇒ $\frac{288}{35}$ ⇒ $\frac{8}{35}$ Since 8 cannot be divided further by 35 $\therefore$ The required remainder is 8. Hence, the correct answer is 8.
Question : Direction: Study the pie chart and answer the question. Details of % of employees working in various departments and number of males among them. Total number of employees = 800 The % of the number of male employees working in the marketing department to the total number of employees in the marketing department:
Option 1: 84%
Option 2: 86%
Option 3: 88%
Option 4: 91%
Correct Answer: 86%
Solution : Number of employees in the marketing department = $\frac{24}{100} \times 800$ = 192 Number of male employees = 165. ∴ Required percentage = $\frac{165}{192} \times 100$ = 85.93% ≈ 86% Hence, the correct answer is 86%.
Question : A person's salary has increased from INR 7,000 to INR 12,000. What is the percentage increase in his salary?
Option 1: $61 \frac{1}{7} \%$
Option 2: $69 \frac{1}{7} \%$
Option 3: $76 \frac{4}{7} \%$
Option 4: $71 \frac{3}{7} \%$
Correct Answer: $71 \frac{3}{7} \%$
Solution : According to the question, Percentage Increase $= \frac{\text{New Value−Old Value}}{\text{Old Value}} × 100$ $= \frac{12000 − 7000}{7000} × 100$ $= \frac{5000}{7000}× 100$ $ = 71\frac{3}{7}\%$ Hence, the correct answer is $71\frac{3}{7}\%$.
Question : In 1898, whose theory propounded that the ions/groups bonded to the metal by secondary bonding have spatial arrangements corresponding to different characteristic coordination numbers?
Option 1: Henry Taube
Option 2: Alfred Werner
Option 3: Erich Huckel
Option 4: Emil Fischer
Correct Answer: Alfred Werner
Solution : The correct answer is Alfred Werner.
Alfred Werner's theory propounded that the ions/groups bonded to the metal by secondary bonding have spatial arrangements corresponding to different characteristic coordination numbers. This theory states that the transition metal cation will have two valencies: a primary and a secondary. Alfred Werner won the Nobel Prize in chemistry in 1913.
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