Correct Answer: × and ÷

Solution : Given:
192 × 16 + 9 – 8 ÷ 2 = 5

Let's check the given options –
First Option: × and ÷
⇒ 192 ÷ 16 + 9 – 8 × 2 = 5
Solving the L.H.S. of the equation –
= 12 + 9 – 8 × 2
= 12 + 9 – 16
= 5
Second option: + and –
⇒ 192 × 16 – 9 + 8 ÷ 2 = 5
Solving the L.H.S. of the equation –
= 192 × 16 – 9 + 4
= 3072 – 9 + 4
= 3067 ≠ 5
Third option: × and –
⇒ 192 – 16 + 9 × 8 ÷ 2 = 5
Solving the L.H.S. of the equation –
= 192 – 16 + 9 × 4
= 192 – 16 + 36
= 212 ≠ 5
Fourth option: + and ÷
⇒ 192 × 16 ÷ 9 – 8 + 2 = 5
Solving the L.H.S. of the equation –
= 192 × 1.78 – 8 + 2
= 341.76 – 8 + 2
= 335.76 ≠ 5

So, only the first option satisfies the given equation. Hence, the first option is correct.

Correct Answer: 10 cm

Solution :

AP = 3.5 cm
PC = 5 cm
DP = 7 cm
AP × PB = PC × PD
3.5 × PB = 5 × 7
⇒ PB = $\frac{35}{3.5}$
⇒ PB = 10 cm
Hence, the correct answer is 10 cm.

Correct Answer: 14.4°

Solution : Percent of exports for Turkey = 4%
Corresponding angle $=\frac{4}{100}×360°=14.4°$
Hence, the correct answer is $14.4°$.

Correct Answer: 2 : 3

Solution : According to the question
For maths:
⇒ $\theta$ for maths = $\frac{20}{100}$ × 360° = 72°
For Science
⇒ $\theta$ for science = $\frac{30}{100}$ × 360° = 108°
Ratio = $\frac{\theta ~\text {for maths}}{\theta ~\text{for science}}$ = $\frac{72°}{108°}$  = $\frac{2}{3}$ = 2 : 3
Hence,  the correct answer is 2 : 3.

Correct Answer: 1782

Solution : The correct answer is 1782.

The Treaty of Salbai, which ended the First Anglo-Maratha War, was signed on 17 May 1782 between the British East India Company and the Marathas. The first Anglo-Maratha War started in 1775. The Treaty of Salbai led to the establishment of the status quo which was restored between the English and Marathas.

Correct Answer: 2, 1, 3, 5, 4

Solution : Given:
1. Earth 2. Venus 3. Mars 4. Saturn 5. Jupiter

The correct order of planets based on their distance from the sun is Venus, Earth, Mars, Jupiter, and Saturn.

Thus, the order is 2, 1, 3, 5, 4. Hence, the third option is correct.

Correct Answer: $47$

Solution : Given: $x^2-3x+1=0$
Divide both sides by $x$, we get,
$⇒ x-3+\frac{1}{x}=0$
$\therefore x+\frac{1}{x}=3$
Squaring both sides, we get,
$⇒(x+\frac{1}{x})^2=3^2$
$⇒x^2+\frac{1}{x^2}+2×x×\frac{1}{x}=9$
$\therefore x^2+\frac{1}{x^2}=7$
Again squaring both sides, we get,
$⇒(x^2+\frac{1}{x^2})^2=7^2$
$⇒x^4+\frac{1}{x^4}+2×x^2×\frac{1}{x^2}=49$
$⇒(x^4+\frac{1}{x^4})=49-2$
$\therefore(x^4+\frac{1}{x^4})=47$
Hence, the correct answer is $47$.

Correct Answer: (2)

Solution : The error lies in the second part of the sentence.

"Engaged tone" should be preceded by the indefinite article "an" to indicate that it is referring to one of the several possible engaged tones that someone might hear. Moreover, the article "an" is used with words starting with a vowel sound.

Therefore, the correct sentence is: "If you hear an engaged tone, replace the receiver and dial again."

Correct Answer: 72 km/h

Solution : Let the speed of the car be $x$ km/h.
According to the question,
Relative speed $= (x - 42)$ km/h
Distance $= 30 + 60 = 90$ km
Now the speed of the car will be
$⇒ x - 42 = \frac{90}{3}$
$⇒ x - 42 = 30$
$⇒ x = 30 + 42 = 72$ km/h
Hence, the correct answer is 72 km/h.

Correct Answer: Mirabai

Solution : The correct answer is Mirabai.

Mirabai was a Rajput princess and a prominent figure in the Bhakti movement of medieval India. She was born into the Rathore clan of Rajputs in the late 15th century. Mirabai is renowned for her unwavering devotion to Lord Krishna, and her devotional songs, known as bhajans, are dedicated to him.