Staff Selection Commission Combined Higher Secondary Level Exam
Question : Directions: Study the double bar graph given below and answer the question.
The average number of students participating in the exhibition is:
Option 1: 48.75
Option 2: 52.5
Option 3: 45
Option 4: 50
Correct Answer: 52.5
Solution : From the given graph, The total number of students participating in the exhibition = 45 + 30 + 60 + 75 = 210 The number of classes = 4 The average number of students participating in the exhibition = $\frac{\text{The total number of students participating in the exhibition}}{{\text{The number of classes}}}$ The average number of students participating in the exhibition = $\frac{210}{4}$ = 52.5 Hence, the correct answer is 52.5.
Question : When milk is converted into curd, which type of change is it?
Option 1: Reversible change
Option 2: Physical change
Option 3: Isothermal change
Option 4: Chemical change
Correct Answer: Chemical change
Solution : The correct option is Chemical change.
When milk is converted into curd, it is a chemical change. This transformation involves the fermentation of milk by beneficial bacteria, such as Lactobacillus, which consume the lactose (milk sugar) and produce lactic acid. The production of lactic acid changes the composition and properties of the milk, giving it a thicker texture and a sour taste, which are characteristic of curd or yoghurt. This chemical change is irreversible, as you cannot easily revert curd into milk with the same properties it had before the transformation.
Question : Directions: In the following question, four number pairs are given. The number on the left side of (–) is related to the number on the right side of (–) with some logic, rule, or relationship. Three are similar on the basis of the same logic, rule, or relationship. Select the odd one out of the given alternatives.
Option 1: 7 – 49
Option 2: 2 – 4
Option 3: 5 – 25
Option 4: 3 – 39
Correct Answer: 3 – 39
Solution : Let's check the options – First option: 7 – 49; (7)2 = 49 Second option: 2 – 4; (2)2 = 4 Third option: 5 – 25; (5)2 = 25 Fourth option: 3 – 39; (3)2 = 9 ≠ 39
The fourth option does not fit the pattern. Hence, the fourth option is correct.
Question : Rs. 13000 is divided among X, Y, and Z such that 2 times X's share is equal to 3 times Y's share which is equal to 4 times Z's share. What is the share of Y?
Option 1: Rs. 3200
Option 2: Rs. 4800
Option 3: Rs. 5600
Option 4: Rs. 4000
Correct Answer: Rs. 4000
Solution : Let $2X = 3Y = 4Z = k$ $X =\frac{k}{2}, Y = \frac{k}{3}, Z = \frac{k}{4}$ The sum of shares of all of them together = 13000 ⇒ $\frac{k}{2} + \frac{k}{3} + \frac{k}{4} = 13000$ ⇒ $\frac{6k+4k+3k}{12}=13000$ ⇒ $\frac{13k}{12}=13000$ ⇒ $k = 12000$ $\therefore$ Share of $Y = \frac{1}{3}\times 12000=4000$ Hence, the correct answer is Rs. 4000.
Question : Select the most appropriate synonym for the underlined word in the given sentence.
She is painfully introverted, but she is an intelligent girl.
Option 1: Shy
Option 2: Outspoken
Option 3: Social
Option 4: Bold
Correct Answer: Shy
Solution : The correct choice is the first option.
Introverts are typically reserved people.
Outspoken, social, and bold are terms used for people who are not as reserved as introverts.
The sentence describes the girl as being painfully introverted, which suggests that she is extremely shy and uncomfortable around other people. The other options are not as appropriate because they do not convey the same sense of social awkwardness.
Therefore, shy will be the correct choice.
Question : What is the sum of all two-digit even numbers?
Option 1: 2430
Option 2: 2410
Option 3: 2470
Option 4: 2520
Correct Answer: 2430
Solution : The first 2 digit number is 10 and the last two-digit number is 98. Sum = $\frac{n}{2}(\text{first term + last term})$ Number of terms = $\frac{(98 - 10)}{2} + 1$ = 45 Now, we can find the sum: Sum = $\frac{45}{2}(10 + 98)$ ⇒ Sum = $45\times54$ ⇒ Sum = 2430 Therefore, the sum of all two-digit even numbers is 2430. Hence, the correct answer is 2430.
Question : Somewhat before the time of the Mauryan empire, about ______________years ago, emperors in China began building the Great Wall.
Option 1: 1200
Option 2: 3500
Option 3: 2400
Option 4: 600
Correct Answer: 2400
Solution : The correct answer is 2400.
China's monarchs started constructing the Great Wall some 2400 years ago, before the Mauryan empire. Its purpose was to keep pastoral people away from the empire's northern frontier.
Question : Which of the following is the most problematic and primary difficulty of barter exchanges as against money-based exchanges?
Option 1: Bartered exchanges involve difficulty in preserving value.
Option 2: Barter exchanges may result in an incorrect valuation of the goods transacted.
Option 3: Barter exchanges may be imperfectly divisible.
Option 4: Barter exchanges require a double coincidence of wants.
Correct Answer: Barter exchanges require a double coincidence of wants.
Solution : The correct option is Barter exchanges require a double coincidence of wants.
The most problematic and primary difficulty of barter exchanges compared to money-based exchanges is the requirement of a double coincidence of wants. In barter, both parties must have something the other wants, creating complexity and inefficiency.
Question : The population of a city increases compounded by 10% annually. The present population of this city is 1,33,100. What was the population of the city 2 years ago?
Option 1: 1,01,000
Option 2: 1,10,000
Option 3: 1,21,000
Option 4: 1,00,000
Correct Answer: 1,10,000
Solution : $P=P{_0}×(1+r)^t$ where: $P$ is the present population, $P{_0}$ is the past population, $r$ is the annual growth rate (as a decimal), and $t$ is the number of years. Given, $P{_0} = 133,100$ $r = 10\%$ We have to find the population 2 years ago ($t=−2$ years) $133100=P{_0}×(1+\frac{10}{100})^{2}$ $⇒P{_0}=133100×(\frac{11}{10})^{−2}$ $⇒P{_0}=133100×\frac{1}{(\frac{11}{10})^2}$ $⇒P{_0}=133100×\frac{100}{121}$ $⇒P{_0}=1,10,000$ Hence, the correct answer is 1,10,000.
Question : A can do in one day three times the work done by B in one day. They together finish $\frac{2}{5}$th of the work in 9 days. The number of days by which B can do the work alone is:
Option 1: 90 days
Option 2: 120 days
Option 3: 100 days
Option 4: 30 days
Correct Answer: 90 days
Solution : Given: A can do in one day three times the work done by B in one day. They together finish $\frac{2}{5}$th of the work in 9 days. Let the efficiency of B = $a$ units, So, the efficiency of A = 3$a$ units Here, $\frac{2}{5}$th of the work is done by them in 9 days. So, the total work is done by them in (9 × $\frac{5}{2}$) = $\frac{45}{2}$ days We know, Total work = Total efficiency × Number of days = $(a+3a)×\frac{45}{2}$ = 90$a$ units $\therefore$ The required days for B to do the work alone = $\frac{90a}{a}$ = 90 days Hence, the correct answer is 90 days.
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