Correct Answer: Helium

Solution : The correct option is Helium.

Ionisation energy is the energy required to remove an electron from a neutral atom, forming a positively charged ion. Helium has the highest ionisation energy because it has the smallest atomic size among all the elements and a full electron shell (1s²), making it very stable and resistant to losing its electrons. This results in a high energy requirement to remove an electron from a helium atom.

Correct Answer: 10%

Solution : Let $P$ be the principal sum.
Total amount = $3P$
Simple interest = $3P- P$ = $2P$
Term, $n$ = 20 years
Let $R$ be the rate of interest.
Simple interest, SI = $\frac{PnR}{100}$
⇒ $2P = \frac{P×20×R}{100}$
⇒ $R= \frac{200}{20}= 10$%
Hence, the correct answer is 10%.

Correct Answer:

Solution : When the given folded paper is unfolded, it will look like –

Hence, the first option is correct.

Correct Answer: 1320

Solution : Given:
HEG is coded as 840, JFD is coded as 720.

Multiply the positional values of the letters of HEG, and then the resultant is multiplied by 3, to obtain the required code –
H→8; E→5; G→7
(8 × 5 × 7) × 3 = 840
Thus, HEG is coded as 840.
And, JFD is coded as 720 –
J→10; F→6; D→4
(10 × 6 × 4) × 3 = 720
Similarly, follow the same pattern for JDK→
J→10; D→4; K→11
(10 × 4 × 11) × 3 = 1320

So, JDK is coded as 1320. Hence, the second option is correct.

Correct Answer: 53.1%

Solution : Single equivalent discount = $(a+b-\frac{a×b}{100}$)%, where $a$% and $b$% are successive discounts.
Here $a$ = 33% and $b$ = 30%
So, Single equivalent discount $= 33+30 - \frac{33×30 }{ 100}=63-9.9 = 53.1$%
Hence, the correct answer is 53.1%.

Correct Answer: 20%

Solution : Given: A man bought an old printer for Rs. 2200 and spent Rs. 800 on its repair. He sold it for Rs. 3600.
The total cost of the printer (CP) = (2200 + 800) = Rs. 3000
The selling price (SP) = Rs. 3600
Profit percentage = $\frac{SP-CP}{CP}×100$
= $\frac{3600-3000}{3000}×100$
= 20%
Hence, the correct answer is 20%.

Correct Answer: 133

Solution : Given:
108, 129, 104, ?, 100, 137, 96

Add and subtract alternatively starting with 21 in each number with a difference of 4, to get the required missing number –
108 + 21 = 129; 129 – 25 = 104; 104 + 29 = 133; 133 – 33 = 100; 100 + 37 = 137; 137 – 41 = 96

So, 133 is the required missing number of the series. Hence, the third option is correct. 

Correct Answer: 80

Solution : Let the number of the second group be $x$.
According to the question,
$x$ × 50 = 50 × 80
⇒ $x$ = $\frac{50 × 80}{50}$
$\therefore x$ = 80
Hence, the correct answer is 80.

Correct Answer: INR 3,000

Solution : Simple interest on a certain sum of money for 2 years at 7% per annum = 2 × compound interest on INR 1,000 for 2 years at 10% per annum
According to the question,
$\frac{P_1nR}{100}= 2 × [P_2(1+\frac{R}{100})^n - P_2]$
Here $P_1$ is the principal for simple interest and $P_2$ is the principal for compound interest.
So,$\frac{P_1×2×7}{100}= 2 × [1000(1+\frac{10}{100})^2 - 1000]$
⇒ $\frac{14P_1}{100}= 2 × [1000(\frac{11}{10})^2 - 1000]$
⇒ $\frac{14P_1}{100}= 2 × 1000×(\frac{121}{100}-1)$
⇒ $\frac{14P_1}{100}= 2 × 1000×\frac{21}{100}$
⇒ $P_1 = \frac{42000}{14}=3000$
Hence, the correct answer is INR 3,000.

Correct Answer: to

Solution : The fourth option is correct.

• To is the correct preposition to use when indicating movement or direction towards a specific destination.

Example: "I am going to the store."

Hence, the correct option is to.